He tauira mō te whakamahi i ngā ture a Newton i runga i te papa whakarara maeneene (kāore he waku)

E rua ngā tauira o te whakamahi i ngā ture a Newton ki tētahi papa whakarara maeneene (kāore he waku)

1. Ko te taumaha o te poraka he 2 kg, ko te whakaterenga nā te kaha ā-papatipu = 10 m/s². Whakatauhia (a) te kaha hua e whakateretere ana i te poraka (b) te rahi o te whakateretere o te poraka.
Kōrero
E mōhiotia ana :
Taumaha o te poraka (m) = 2 kg
Te whakaterenga nā te kaha ā-papa (g) = 10 m/s²
Taumaha o te poraka (w) = mg = (2)(10) = 20 Newton
w_x = w sin 30 = (20)(0,5) = 10 Ngā Newton
w_y = w cos 30 = (20)(0,5√3) = 10√3 Ngā Newton
Whakautu:
(a) te kaha hua e whakateretere ana i te poraka
He papa whakarara maeneene e whakaarohia ana kāore he waku. Nō reira, ko te kaha e pā ana ki te nekehanga o te poraka he w anake_x
(B) te rahi o te whakaterenga o te poraka
Ko te rahi o te whakaterenga o te poraka he 5 m/s², kei raro te ahunga o te whakaterenga o te poraka.

2. Kei runga te poraka i tētahi papa whakarara maeneene, kāore he waku. Ko te taumaha o te poraka he 3 kg, ā, ko te whakaterenga nā te kaha ā-papatipu he 10 m/s.². Tātaihia te rahi o te kaha F mēnā (a) kei te noho pūmau te poraka (b) ka neke te poraka ki raro me te whakaterenga o te 2 m/s² (c) ka neke te poraka ki runga me te whakaterenga pumau o te 2 m/s².
Kōrero
E mōhiotia ana :
Taumaha o te poraka (m) = 3 kg
Te whakaterenga nā te kaha ā-papa (g) = 10 m/s²
Taumaha o te poraka (w) = mg = (3)(10) = 30 Newton
w_x = w sin 30 = (30)(0,5) = 15 Ngā Newton
w_y = w cos 30 = (30)(0,5√3) = 15√3Ngā Newton
Whakautu:
(a) Tāutuhia a F mēnā kei te okioki te poraka.
E ai ki te ture tuatahi a Newton, ka noho okioki tetahi mea mēnā he kore te kaha e puta mai ana.
(b) Whakatauhia a F mēnā ka neke te poraka ki raro me te whakaterenga o te 2 m/s²
(c) Tāutuhia a F mēnā ka neke te poraka ki runga me te whakaterenga pumau o te 2 m/s²

[Ingarihi: Te nekehanga i runga i te papa whakarara me te kore he kaha waku]