Ngā Tauira Pātai mō te Kōrero mō ngā Ngaru Reo Irirangi

Ngā Tauira Pātai mō te Kōrero mō ngā Ngaru Reo Irirangi

Ko ngā ngaru reo irirangi he momo irahiko hikohiko e mahi ana i roto i ngā whakawhitiwhiti kōrero ahokore. Me ngā auau mai i ētahi kilohertz (kHz) ki ētahi gigahertz (GHz), e whakamahia ana ngā ngaru reo irirangi i roto i te whānuitanga o ngā tono—mai i ngā pāhotanga reo irirangi me te pouaka whakaata ki ngā pūnaha whakawhitiwhiti kōrero pūkoro. I roto i tēnei tuhinga, ka matapakihia e mātou ngā tauira o ngā ngaru reo irirangi me ō rātou whakamārama hei āwhina i a tātou ki te mārama ki ngā mātāpono me ngā tono o ēnei ngaru i roto i te oranga o ia rā.

Tauira Pātai 1: Auautanga me te Roangaru

Pātai:
Ka tukuna ngā ngaru reo irirangi e tētahi teihana reo irirangi i te auau o te 100 MHz. Tātaihia te roanga ngaru. (Ko te tere o te mārama he 3 x 10^8 m/s.)

Kōrero:
E pā ana te auau (f) me te roanga ngaru (λ) o ngā ngaru hikohiko ki te tere o te mārama (c) mā te whārite:

\[ c = f \times \lambda \]

Dimana:
– \( c \) = te tere o te mārama (3 x 10^8 m/s)
– \( f \) = auau (100 MHz, 100 x 10^6 Hz rānei)
– \( \lambda \) = te roangaru (kia kitea)

Mai i te whārite i runga ake nei, ka taea te tatau i te roanga ngaru mā te:

\[ \lambda = \frac{c}{f} \]

Nā reira:

\[ \lambda = \frac{3 \times 10^8}{100 \times 10^6} = 3 \ \text{mita} \]

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Nō reira, ko te roanga ngaru o te auautanga o te 100 MHz he 3 mita.

Tauira Pātai 2: Te Mana Tuku me te Kaha

Pātai:
Ka tukuna e te tuku reo irirangi 50-wati ngā ngaru reo irirangi i runga i te āhua kotahi (he ōrite ki ngā taha katoa). Tātaihia te kaha o ngā ngaru reo irirangi i te tawhiti o te 10 mita mai i te tuku.

Kōrero:
Ka taea te tatau i te kaha (I) o tētahi ngaru e tukuna ana i te taha kotahi mā te:

\[ I = \frac{P}{A} \]

Dimana:
– \( P \) = mana tuku (50 watts)
– \( A \) = horahanga mata o te porowhita (4πr^2)

I te tawhiti (r) = 10 mita, ko te horahanga o te mata o te pōro ko:

\[ A = 4\pi (10)^2 = 400\pi \]

Nā reira:

\[ I = \frac{50}{400\pi} = \frac{1}{8\pi} \ \text{watt/m}^2 \]

Nō reira, ko te kaha o ngā ngaru reo irirangi i te tawhiti o te 10 mita mai i te tuku ko \( \frac{1}{8\pi} \) watt/m².

Tauira Pātai 3: Te Whānuitanga o te Aratuku me te Kaha o te Hongere

Pātai:
Ko te whānui o te hongere whakawhitiwhiti kōrero he 20 MHz. Mēnā kei te whakamahi koe i te whakarerekētanga QPSK (Quadrature Phase Shift Keying), he aha te kaha mōrahi o te hongere?

Kōrero:
E whā ngā wāhanga rerekē o te whakarerekētanga QPSK, nō reira ka taea e ia te tuku i te 2 moka mō ia tohu i roto i te wā kotahi.

Ko te maha o ngā tohu ia hekona ka taea e te whānui o te 20 MHz te whakahaere ko:

\[ \text{Tohu} = 20 \times 10^6 \ \text{tohu/hēkona} \]

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Nā te mea e rua ngā moka e tukuna ana e QPSK mō ia tohu, ko te kaha, te maha rānei o ngā moka mō ia hekona (tere moka) ko:

\[ \text{Te tere tere} = 20 \times 10^6 \times 2 = 40 \ \text{Mbps} \]

Nō reira, ko te kaha mōrahi o te hongere he 40 Mbps.

Tauira Pātai 4: Te Whakararuraru me te Whakararuraru

Pātai:
Kei te pāngia tētahi tuku reo irirangi i te auau o te 101.1 MHz e te pokanoa mai i tētahi atu tuku reo irirangi i te auau o te 101.3 MHz. Tātaihia te auau patupatu ka puta.

Kōrero:
Ko te auau o te patu \( f_{patunga} \) ka puta mai i te rerekētanga i waenga i ngā auau tata e rua, ā, ka taea te tatau mā te:

\[ f_{patunga} = |f_1 – f_2| \]

Dimana:
– \( f_1 \) = 101.1 MHz
– \( f_2 \) = 101.3 MHz

Nā reira:

\[ f_{patunga} = |101.1 – 101.3| = | -0.2 | = 0.2 \ \text{MHz} \]

Nō reira, ko te auau patu hua ko 0.2 MHz.

Tauira Pātai 5: Te Pānga Doppler i roto i ngā Ngaru Reo Irirangi

Pātai:
Ka whakapāho te teihana reo irirangi i te auau o te 95 MHz. Ka whakatata atu te waka rererangi ki te teihana reo irirangi i te tere o te 340 m/s. Tātaihia te auau ka riro i te waka rererangi mēnā he ōrite te tere o ngā ngaru reo irirangi ki te tere o te mārama (3 x 10^8 m/s).

Kōrero:
Ka taea te whakaatu i te pānga Doppler mō ngā ngaru reo irirangi penei:

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\[ f_{whakaae} = f_{0} \left(\frac{c + v}{c}\right) \]

Dimana:
– \( f_0 \) = auau taketake (95 MHz)
– \( v \) = tere rererangi (340 m/s)
– \( c \) = tere o te ngaru (3 x 10^8 m/s)

Nā reira:

\[ f_{whakaae} = 95 \times 10^6 \left(\frac{3 \times 10^8 + 340}{3 \times 10^8}\right) \]

\[ f_{whakaae} = 95 \times 10^6 \left(\frac{3 \times 10^8 + 3.4 \times 10^2}{3 \times 10^8}\right) \]

\[ f_{whakaae} \tata 95 \times 10^6 \left(1 + \frac{3.4 \times 10^2}{3 \times 10^8}\right) \]

\[ f_{whakaae} \tata ki te 95 \times 10^6 \left(1 + 1.1333 \times 10^{-6}\right) \]

\[ f_{whakaae} \tata ki te 95 \whakaahua 10^6 \whakaahua 1.0000011333 \]

\[ f_{whakaae} \tata ki te 95.000107 \ \kuputuhi{MHz} \]

Nō reira, ko te auau e tae mai ana ki te waka rererangi e whakatata mai ana he tata ki te 95.000107 MHz.

Te Katinga

He mea nui te mārama ki ngā mātāpono taketake me ngā tauira rorohiko o ngā ngaru reo irirangi i roto i ngā momo mara hangarau me te pūtaiao. Kei roto i ngā raruraru i runga ake nei ētahi tauira o te whakamahinga o te ahupūngao o ngā ngaru reo irirangi i roto i ngā horopaki mahi maha. Ko te ara ki te māramatanga hohonu ake ko te mahi tonu me te tūhura i ngā tono o te ao tūturu o ngā ngaru reo irirangi i roto i te hangarau whakawhitiwhiti kōrero e whakamahia ana e tātou i ia rā.

Waiho he kōrero