Ahupūngao Kura Tuarua

Ehara i te mea ko ngā mea katoa e tūtaki ana tātou i ia rā, e tū tonu ana. Tērā pea ka tū te mea i te tīmatanga, engari ki te nekehia, ka taea e ia te neke. Ko te pātai, mēnā ka hoki anō ki tōna tūranga taketake i muri i te neke. Kei te nekehanga tēnei. ngā momo taurite o ngā mea te.
Ki te pāngia te mea e okioki ana e te raruraru (he kaha hua, he wā kaha hua rānei e pā ana ki te mea) ka neke te mea. I muri i te neke, e toru ngā mea ka taea, arā: (1) ka hoki te mea ki tōna tūranga taketake, (2) ka neke atu te mea i tōna tūranga taketake, (3) ka noho tonu te mea ki tōna tūranga hou. Ki te hoki te mea ki tōna tūranga taketake i muri i te neke, ka noho te mea i roto i taurite pumau. Ki te neke te mea i tawhiti atu i tōna tūranga taketake i muri i te neke, kāti kei roto te mea i taurite kore pumau. I tētahi atu taha, ki te noho tonu te mea i tōna tūranga hou i muri i te nekenga, kāti kei roto te mea i taurite koretake.

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2 Ngā tauira o ngā pātai taurite matūriki

1. Kei te whakairihia tētahi mea he 10 kg te taumaha ki runga i tētahi taura. Tātaihia te kukū o te taura (T)! g = 10 m/s²
Kōrero

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5 Ngā tauira o ngā pātai mahi mō te pūngao nekeneke me te ahupūngao

1. He motuka he 5000 kg te taumaha e tū ana i te tīmatanga, kātahi ka neke i te tere o te 20 m/s. Tātaihia te mahi katoa i mahia ki te motuka...
Kōrero
E mōhiotia ana :
Taumaha (m) = 5000 kg
Te tere tīmatanga (v_o) = 0 m/s (i te tīmatanga ka tū te motuka)
Te tere whakamutunga (v_t) = 20 m/s
I pātaihia Te whakapau kaha katoa

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15 Ngā Tauira o Ngā Pātai Mātāpono a Black

1. Kua konatunatua te hukapapa 0,2 kg te taumaha ki te tī mahana 0,2 kg te taumaha. Ko te pāmahana o te hukapapa = – 10^oC, pāmahana tī mahana = 40^oC. Te wera motuhake o te hukapapa = 2100 J/kg C^o, te wera motuhake o te wai = 4200 J/kg C^o, ko te wera o te hanumitanga o te wai = 334.000 J/kg. Mēnā ka konatunatua te hukapapa me te tī wera ki roto i tētahi pūnaha motuhake kua kati, whakatauhia te pāmahana whakamutunga o te ranunga.

Kōrero
E mōhiotia ana :
Taumaha o te huka (m es) = 0,2 kg
Taumaha o te wai tī mahana (m tī) = 0,2 kg
Te wera motuhake o te wai (c wai) = 4180 J/kg C^o
Te wera motuhake o te hukapapa (c es) = 2100 J/kg C^o
Te wera o te hanumitanga o te wai (L)_f wai) = 334.000 J/kg

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5 ngā tauira o te nekehanga koki me te nekehanga rārangi i roto i te nekehanga porowhita

1. E 30 henimita te whānui o tētahi wira e hurihuri ana i te tawhiti o te 10 henimita. E hia te tawhiti e haere ai tētahi pūwāhi i te taha o te wira?
Kōrero
Ko te tawhiti i waenganui i te taha o te wira me te pokapū o te wira = te pūtoro o te wira.
E mōhiotia ana:
Pūtoro (r) = 30 henemita = 0,3 mita
Kokonga (tit) = 10 ngā rātiana
I pātaihia: te tawhiti i haerea
Whakautu:

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2 Ngā tauira pātai mō te whakatau i te whārite hua mā te whakamahi i ngā whārite wāhanga

1. F₁ = 6 N, F₂ = 10 N. Ko te hua o ngā whārite kaha e rua ko…

Kōrero
F_1x =F₁ whaimana 60^o = (6)(0,5) = 3 N (pai nā te mea kei te ahunga x pai)
F_2x =F₂ whaimana 30^o = (10)(0,5√3) = 5√3 = (5)(1,372) = -8,66 N (kino nā te mea kei te ahunga x kino)
F_1y =F₁ hara 60^o = (6)(0,5√3) = 3√3 = (3)(1,372) = 4,116 N (he pai nā te mea kei te ahunga y pai)
F_2y =F₂ hara 30^o = (10)(0,5) = -5 N (kino nā te mea kei te ahunga y kino)

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2 Ngā tauira pātai mō te whakatau i ngā wāhanga whārite

1. Ka hangaia he koki o te 30 e te whārite kaha F = 20 Newton^o ki te tuaka-x pai. Whakatauhia ngā wāhanga o te whārite F i runga i te tuaka-x (F_x) me te tuaka-y (F_y).

Kōrero
F_x = F cos 30^o = (20)(cos 30^o) = (20)(0,5√3) = 10√3 Ngā Newton

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Ako tauira o te pokanoa me te whakarara o te māramatanga – te kōhao kotahi, kātahi ka mahi i ngā rapanga pokanoa me te whakawhitiwhiti o te mārama.

1. Ka haere te mārama he 700 nm te roangaru mā roto i tētahi āputa he 0,2 mm te whānui. Kei te tawhiti o te tauira whatuwhatu i runga i te mata he 50 cm mai i te āputa. Tātaihia te tawhiti i waenganui i te rārangi pōuri tuarua me te rārangi mārama matua.
Kōrero

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Ako tauira o te pokanoa me te whakarara o te māramatanga – te whatanga whakarara , kātahi ka mahi i ngā rapanga pokanoa me te whakawhitiwhiti o te mārama.

1. Kua tāutahia he whatanga whakarara, e 4000 ngā rārangi ia 1 cm, ki te tawhiti o te 1 mita mai i te āputa e whakamāramahia ana. Tātaihia te roanga ngaru o te mārama mēnā ko te ahua tuatahi te rahinga nui rawa atu he 30 cm mai i te āputa.
Kōrero
E mōhiotia ana:
d = 1 / (4000 rārangi / cm) = 0,00025 cm = 2,5 x 10^-4 henimita = 2,5 x 10^-6 m
l = 1 mita
y = 30 henimita = 0,3 mita
I pātaihia: te roanga ngaru (lambda)

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