Hafainganam-pandehan'ny onja mivelatra - olana sy vahaolana
1.
Raha 2 segondra ny elanelam-potoana ilaina handehanana avy any A mankany B, dia farito ny hafainganam-pandehan'ny onja miampita.
Fantatra:
Distance AB = 6 metatras
Fotoana fohy AB = 2 segondra
Mitady: Hafainganam-pandehan'ny onja miampita
vahaolana:
1 halavan'ny onjam has 1 crest and 1 trough. There is 4 wavelength between A and B. Distance between A and B is 6 meters so that 1 wavelength (λ) = 6 metatras / 4 = 1.5 meters.
Ny time interval required to travel from A to B is 2 seconds so that the time interval required to travel 1 wavelength = period (T) = 2 seconds / 4 = 0.5 seconds.
The equation of the speed of wave :
v = λ f = λ / T
v = speed of wave, λ = halavan'ny onjam, f = hatetika, T = period
The speed of wave :
v = 1.5 meters / 0.5 segondracons
v = 3 meters/ seFepe
2. If the time interval required to travel from A to B is 8 seconds, determine the speed of transverse wave.
Fantatra:
There are two wavelength.
1 halavan'ny onjam (λ) = 2 x 4 meters = 8 metatras
Period (T) = 8 secons / 2 onjam- = 4 seconds / halavan'ny onjam
Tadiavina: Speed of wave (V)
vahaolana:
The speed of wave calculated using the equation of the speed of wave :
v = f λ = λ/T
v = 8 meters / 4 segondracons
v = 2 meters/ seFepe
