3 Fampidirana elektromagnetika EMF vokatry ny olan'ny olana sy ny vahaolana
1. Boil iray nosoloina boil hafa izay manana tadivavarana in-2 noho ny tadivavarana voalohany ary tsy miova ny tahan'ny fiovan'ny flux magnetika. Fantaro ny tahan'ny emf nateraka voalohany sy farany.
Fantatra:
Tadivavarana voalohany (N) = 1
Tadivavarana farany (N) = 2
Ny tahan'ny fiovan'ny fikorianan'ny andriamby voalohany (ΔØB / Δt) = ny tahan'ny fiovan'ny fikorianan'ny andriamby farany (ΔØB /Δt)
Mitady: The ratio of initial and final induced emf
vahaolana:
The equation of Faraday’s law of induction :
E = -N (ΔØB /Δt)
E = induced EMF, N = number of loops, ΔØB / Δt = the rate of change of magnetic flux
The ratio of initial and final induced emf :
E initial: E final
-N (ΔØB / Δt) : -N (ΔØB /Δt)
1: 2
2. In the initial state (1), the magnetic flux is changed by 5 Wb in 2 seconds on a coil with 20 loops. In the final state (2), the same flux changed in 8 seconds. Determine the ratio of the initially induced emf and the final induced emf.
Fantatra:
Ny tahan'ny fiovan'ny fikorianan'ny andriamby voalohany (ΔØB / Δt) = 5/2
The rate of change of final magnetic flux (ΔØB / Δt) = 5/8
Number of loops (N) = 20
Mitady: The ratio of the initially induced emf and the final induced emf
vahaolana:
E initial: E final
-N (ΔØB / Δt) : -N (ΔØB /Δt)
20 (5/2) : 20 (5/8)
5/2: 5/8
1/1: 1/4
4: 1
3. The magnetic flux of the initial coil has 200 loops changes by 0.06 Wb in 0.4 seconds. The magnetic flux of the final coil has 0.08 Wb in 0.2 seconds. If several loops of the final coils are substituted with the half number of the first coil’s loops, determine the ratio of the induced emf of the initial loops and the final loops.
Fantatra:
Ny tahan'ny fiovan'ny fikorianan'ny andriamby voalohany (ΔØB / Δt) = 0.06 / 0.4
Number of initial loops (N) = 200
The rate of change of final magnetic flux (ΔØB / Δt) = 0.08 / 0.2
Number of final loops (N) = 100
Tadiavina: The ratio of the initial induced emf and the final induced emf
vahaolana:
E initial : E final
-N (ΔØB / Δt) : -N (ΔØB /Δt)
200 (0.06/0.4) : 100 (0.08/0.2)
2 (0.15) : 1 (0.4)
0.3: 0.4
3: 4