Fikajiana ny fampiasana angovo elektrika amin'ny fitaovana elektrika - olana sy vahaolana
1. Ao an-trano iray, misy jiro 5 25 Watt ampiasaina mandritra ny 14 ora isan'andro, vata fampangatsiahana 200 Watt ampiasaina mandritra ny 24 ora isan'andro, ary paompy rano 125 Watt ampiasaina mandritra ny 8 ora isan'andro. Ohatrinona? angovo elektrika nampiasaina nandritra ny iray volana (30 andro)?
Fantatra:
Herin'ny jiro = 5(25) = 125 Watt ary fotoana fampiasana = 14 ora x 30 = 420 ora
Herin'ny vata fampangatsiahana = 200 Watts ary fotoana fampiasana = 24 ora x 30 = 720 ora
Herin'ny paompin-drano = 125 Watts ary fotoana fampiasana = 8 ora x 30 = 240 ora
Tadiavina: Electrical energy used for a month
vahaolana:
Electric energy = herinaratra x time interval
Energy (lamp) = (125 Watt)(420 hours) = 52,500 Watt jam = 52,5 kilo Watt hours
Energy (refrigerator) = (200 Watt)(720 hours) = 144,000 Watt jam = 144 kilo Watt hours
Energy (water pump) = (125 Watt)(240 hours) = 30,000 Watt jam = 30 kilo Watt hours
Electrical energy used for a month = 52,5 + 144 + 30 = 226,5 kilo Watt hour = 226,5 kilo Watt hour = 226,5kwh.
2. A house using electrical tools as listed in the following table.
How much electrical energy is used for 1 month (30 days)?
Fantatra:
Power of lamp = 4 x 10 Watt = 40 Watt and time of use = 10 hours x 30 = 300 hours
Power of TV = 1 x 100 Watt = 100 Watt and time of use = 10 hours x 30 = 300 hours
Power of iron = 1 x 300 Watt = 300 Watt and time of use = 2 hours x 30 = 60 hours
Tadiavina: Electrical energy is used for 1 month
vahaolana:
Electric energy = electric power x time
Energy used by lamp = (40 Watt)(300 hours) = 12,000 Watt hours = 12 kilo Watt hours = 12 kWh
Energy used by TV = (100 Watt)(300 hours) = 30,000 Watt hours = 30 kilo Watt hours = 30 kWh
Energy used by iron = (300 Watt)(60 hours) = 18,000 Watt hours = 18 kilo Watt hours = 18 kWh
Total energy = 12 kWh + 30 kWh + 18 kWh = 60 kWh.
3.
The electrical energy used by the above three electrical tools is…
A. 158,400 Joule
B. 950,400 Joule
Joule eo ho eo amin'ny 5,860,800
D. 9,504,000 Joule
vahaolana
Electric power of TV :
P = V I = (220 Volt)(0.3 Ampere) = 66 Volt Ampere = 66 Watt = 66 Joule/second
Electric power of computer :
P = V I = (220 Volt)(0.4 Ampere) = 88 Volt Ampere = 88 Watt = 88 Joule/second
Electric power of water pump :
P = V I = (220 Volt)(0.5 Ampere) = 110 Volt Ampere = 110 Watt = 110 Joule/second
Elanelana:
10 hours = 10 x 3600 seconds = 36,000 seconds
6 hours = 6 x 3600 seconds = 21600 seconds
4 hours = 4 x 3600 seconds = 14400 seconds
Electric energy = electric power x time
Electric energy used by TV = 66 Joule/second x 36,000 segondra = 2,376,000 Joule
Electric energy used by computer = 88 Joule/second x 21,600 segondra = 1,900,800 Joule
Electric energy used by water pump = 110 Joule/seconds x 14,400 segondra = 1,584,000 Joule
Total electric energy :
2,376,000 Joule + 1,900,800 Joule + 1,584,000 Joule = 5,860,800 Joule
4. A family uses electrical energy for a month (30 days) for tools as in the following table!
Electric power of washing machine, TV and AC are…
vahaolana:
Electric energy of washing machine = 12 kWh = 12,000 Watt hour, time of use = 2 hours x 30 = 60 hours
Electric energy of TV = 19.2 kWh = 19,200 Watt hour, time of use = 8 hours x 30 = 240 hours
Electric energy of AC = 72 kWh = 72,000 Watt hour, time of use = 6 hours x 30 = 180 hours
Electric power = electric energy / time
Electric power of washing machine = 12,000 Watt hour / 60 hours = 200 Watt
Electric power TV = 19,200 Watt hour / 240 hours = 80 Watt
Electric power AC = 72,000 Watt hour / 180 hours = 400 Watt
