Mechaninių bangų greitis – problemos ir sprendimai

1. Greitis skersinė banga Ant 25 metrų virvės yra 50 m/s. Virvės tempimo jėga yra 200 N. Nustatykite virvės masę.

A. 0.08 XNUMX kg

B. 0.5 XNUMX kg

C. 0.8 XNUMX kg

D. 2.0 kg

Žinomas:

Length of rope (l) = 25 m

Speed of transverse wave (v) = 50 m/s

Tension force of rope (T) = 200 N

Ieškoma: Mass of rope (m)

sprendimas:

This problem can be solved using the formula of the wave propagation formula on the rope.

Speed of the mechanical waves - problems and solutions 1

Teisingas atsakymas yra D.

2. On the surface of the lake floats two pieces of wood, the distance between them is 6 m. The waves propagate on the surface of the lake. When the first wood has moved up and down three times, the second wood just moved up and down once. If every 2 seconds both kinds of wood move up and down three times, the wave propagation is …

A. 4.5 m/s

B. 3.0 m/s

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C. 2.0 m/s

D. 1.5 m/s

Žinomas:

Distance between both woods (l) = 6 meters

The first timber has moved up and down three times; the second wood just moved up and down once.

Frequency (f) = 3 / 2 = 1.5 hertz

Ieškoma: Speed of wave (v)

sprendimas:

When the first wood moves up and down once, the bangos ilgis 1 travels to the second wood. When the first wood moves up and down twice, the wavelength 2 travels to the second wood. When the first wood moves up and down three times, the wavelength one has arrived at the second wood position, so that at the same time the second wood moves up and down once.

Speed of the mechanical waves - problems and solutions 2Taigi, atstumas between the first wood and the second wood is two wavelengths (2 λ), as shown in the picture on the side.

Distance of 1 wavelength (λ) = 6 / 2 = 3 meters

The speed of the wave propagation (v):

v = f λ = (1.5 hertz)(3 meters)

v = 4.5 m/s

Teisingas atsakymas yra A.

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3. Factors that accelerate the propagation of waves on the strings are…

(1) extend the wire

(2) magnifying the wire mass

(3) increase the wire tension

(4) enlarge the wire size The correct statement is…

A. (1), (2), (3) and (4)

B. (1), (2) ir (3) punktai

C. (3) ir (4)

D. (3) only

sprendimas:

The formula of the speed of the wave propagation on the strings:

Speed of the mechanical waves - problems and solutions 3

Teisingas atsakymas yra A.

v = speed of the wave propagation on the strings

T = tension force of strings

μ = density of the string

m = mass of the string

l = length of string

4. On a rope propagates a wavelength rope with a frequency of 50 Hz and a wavelength of 2 m. Period and velocity of the wave are…

A. 0.02 seconds and 50 ms-1

B. 0.02 seconds and 100 ms-1

C. 0.04 seconds and 50 ms-1

D. 0.5 seconds and 100 ms-1

Žinomas:

Frequency (f) = 50 Hz

The wavelength (λ) = 2 meters

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Ieškoma: Period (T) and speed of the wave (v)

sprendimas:

Laikotarpis:

T = 1/f = 1/50 Hz = 0.02 seconds

Bangos greitis:

v = f λ = (50 1/second)(2 meters) = 100 meters/second

Teisingas atsakymas yra B.

5. A cork on the surface of water moves up and down due to the surface water waves. The time required from a crest to next crest is 1.2 seconds. If on the water surface, the distance between two crests is 10 cm, then determine the speed of the wave propagation.

A. 12 ms-1

B. 12 cm s-1

C. 8,3 ms-1

D. 8,3 cm s-1

Žinomas:

The time required from crest to the next crest = the time interval for one wavelength = period (T) = 1.2 seconds.

Distance between two crests = distance of 1 wavelength (λ) = 10 cm

Ieškoma: Speed of the wave propagation (V)

sprendimas:

Speed of the wave propagation :

v = f λ = λ / T = 10 cm / 1.2 seconds = 8.3 cm/second = 8.3 cm.s-1

Teisingas atsakymas yra D.

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