Latent Hëtzt Schmelzwärme Verdampfungswärme – Problemer a Léisungen

4 Latent heat Heat of fusion Heat of vaporization – Problems and Solutions

1. Calculate the amount of Hëtzt added to 1 gram gold to change phase from solid to liquid. The heat of fusion for gold is 64.5 x 10³ J/kg.

Bekannt:

Mass (m) = 1 gram = 1 x 10^-3 kg

Heat of fusion (L_F) = 64.5 x 10³ J / kg

Gesicht: Hëtzt (Q)

Léisung:

Q = m⁻¹⁵L_F

Q = (1 x 10^-3 kg)(64.5 x 10³ J/kg)

Q = 64.5 Joule

2. Calculate the amount of heat released by 1 gram mercury to change phase from liquid to solid. Heat of fusion for mercury is 11.8 x 10³ J/kg.

Bekannt:

Mass (m) = 1 gram = 1 x 10^-3 kg

Heat of fusion (L_F) = 11.8 x 10³ J / kg

Gesicht: Hëtzt (Q)

Léisung:

Q = m⁻¹⁵L_F

Q = (1 x 10^-3 kg)(11.8 x 10³ J/kg)

Q = 11.8 Joule

3. Determine the amount of heat absorbed by 1 kg water to change phase from liquid to vapor (steam). Heat of vaporization for water = 2256 x 10³ J / kg

Bekannt:

Mass (m) = 1 kg

Heat of vaporization (L_V) = 2256 x 10³ J / kg

Gesicht: Hëtzt (Q)

Léisung:

Q = m⁻¹⁵L_V

Q = (1 kg)(2256 x 10³ J/kg)

Q = 2256 x 10³ Joule

4. Determine the amount of heat released by nitrogen to change phase from vapor to liquid. Heat of vaporization for nitrogen = 200 x 10³ J / kg

Bekannt:

Mass (m) = 1 gram = 1 x 10^-3 kg

Heat of vaporization (L_V) = 200 x 10³ J / kg

Bekannt: Hëtzt (Q)

Léisung:

Q = m⁻¹⁵L_V

Q = (1 x 10^-3 kg)(200 x 10³ J/kg)

Q = 200 Joule

1. Temperaturskalaen ëmwandelen
2. Linear Expansioun
3. Flächenerweiderung
4. Volumen Erweiderung
5. Hëtzt
6. Mechanescht Äquivalent vun Hëtzt
7. Spezifesch Hëtzt a Wärmekapazitéit
8. Latent Hëtzt, Schmelzwärm, Verdampfungswärm
9. Energieerhaalung fir Wärmetransfer