Conversio unitatum – problemata et solutiones

Problemata et solutiones de conversione unitatum – problemata et solutiones

1. Dimidium sextarius lactis recentis cum liquamine pulmenti mixti, quantum lactis in liquaminem pulmenti addendum est...

A. 5000 ml

B. 500 cc

Circa 50 dm³

D. 5 m³

Notum:

Volume of milk = 0.5 liter

voluit : 0.5 liter = ….. ml = ….. cm³ (cc) = ... dm³ = ... m³

solution:

1 liter = 1000 milliliter (1000 ml)

1 litrum = 0.001 m³ = 1 dm²³ = X cm³ (1000 cc) ;

0.5 litri = (0.5)(1000 ml) = 500 ml

0.5 dm³ = (0.5)(1000 cc) = 500 cc

0.5 litrae = 0.5 dm²³ 0.0005 = m,³

Responsum rectum est B.

2. If into 100 milliliters of liquid milk added 250 cc of water then how many mixtures are produced.

A. 12.5 dm³

B. 1.25 dm³

Circa 3.5 dm³

D. 0.35 dm³

Notum:

Volume of milk = 100 ml

Volume of water = 250 cc = 250 cm³

voluit : 100 ml + 250 cc = ….. dm³

solution:

ml = milliliter

cc = cm³ = centimeter metrorum cubicorum conplectuntur

dm³ = cubica hocmeter

1 dm³ = 1 liter = 1000 milliliters so that 100 milliliters = 100/1000 liters = 1/10 liters = 0.1 liter = 0.1 dm³

1 dm³ = X cm³ so that 250 cm³ = 250/1000 dm³ = 1/4 dm³ = 0.25 dm²³

100 ml + 250 cm³³ = 0.1 dm²³ + 0.25 dm³ = 0.35 dm²³

Responsum rectum est D.

3. A classroom whose length is 10 m and its width is 8 m, using ceramic as its floor. The size of the ceramic is 20 cm x 20 cm. The amount of ceramics on the floor in the room is ….

A. 20

B. 200

C. 2000

D. 20000

Notum:

The size of a room :

Length = 10 meters

Width = 8 meters

Area of a room = 10 m x 8 m = 80 m²

The size of a ceramic :

Length = 20 cm

Width = 20 cm

Area of a ceramic = 20 cm x 20 cm = 400 cm²

Wanted : The number of ceramic used as the floor

solution:

1m=100cm

m 1² = X cm²

So 80 m² = 80 × 10 000 cm² = X cm²

Number of ceramics = area of a room / area of a ceramic

Number of ceramics = 800,000 cm² / 400cm²

Number of ceramics = 2000

Responsum rectum est C.

4. Every second as much as 4 cc of water dripped from a aquarium in a 5 liters container. The container is fully filled during ….. seconds.

A. 125 seconds

B. 200 seconds

C. 1250 secunda

D. quattuor secunda

Notum:

1 litrae = 1 dm²³ = X cm³

Volume of water = 4 cc = 4 cm³

Volume of container = 5 liters = 5 dm³ = 5 × 10 000 cm³ = X cm³

SE busca: Time interval the container full filled with water

solution:

5000 cm³ / 4cm³ = XXX seconds

Responsum rectum est C.

5. Mother bought drinking water 2 gallons (1 gallon = 19 liters) with price $2. If the volume of a cup aquae is 200 ml, then determine pretium a cup aquae.

Notum:

1 gallon = 19 liters

2 gallon = 2 x 19 liters = 38 liters

1 liters = 1000 milliliters

38 liters = 38 x 1000 milliliters = 38,000 milliliters

1 glass of water = 200 milliliter

Quaesitum: Price of a cup of water

solution:

2 gallon of water = 38 liters = 38,000 milliliters

1 cup of water = 200 milliliters

38,000 ml / 200 ml = 190

In 2 gallon of water there are 190 cup of water.

Price of 2 gallon of water = $2

Price of 1 cup of water = $2 / 190 = $0.01