직렬 저항에 관한 기사
그림과 같이 저항기가 연결되어 있으면 직렬 저항이 됩니다. 여기서 말하는 저항기 또는 전기 저항은 저항 부품, 전구 또는 기타 전기 저항의 형태를 띨 수 있습니다.
전하가 저항 1(R)을 통해 이동합니다.1) = 전하 저항 2(R)를 통해 이동합니다.2) = 전하가 저항 3(R)을 통해 이동합니다.3). 전류 사용 (I)는 특정 시간 간격 동안 흐르는 전하량(I = Q / t)이므로 저항 1을 통과하는 전류(I)는 다음과 같습니다.1) = 저항 2을 통과하는 전류(I)2) = 저항 3을 통과하는 전류(I)3수학적으로 총 전류(I) = I입니다.1 = I2 = I3.
Conversely, the electric voltage (V) decreases when the electric charge moves through each resistor. Electricity voltage also called an electric potential difference, is an electric potential energy per unit of electric charge. Electricity voltage is reduced because electricity is used in each electrical resistance. So, the total electrical voltage (V) is equal to the amount of electricity in each resistor. Mathematically, the total electric voltage (V) = V1 + V2 + V3. V = I R so the equation of the electric voltage is V = I R1 + IR2 + IR3. The electric current flowing on each resistor is equal so that this equation changes to V = I (R1 + R2 + R3).
Based on the above equation, it can be concluded that the total electrical resistance (R) or the equivalent resistance of the electrical resistance
which is connected in series is equal to the sum of each electrical resistance, mathematically R = R1 + R2 + R3. If there are only two resistors in series, the equivalent resistor (R) = R1 + R2. If there are four resistors in series, the equivalent resistor (R) = R1 + R2 + R3 + R4. Likewise, if there are five or more five resistors that are connected in series.
Sample problem 1:
If known, R1 = 2 Ω, R2 = 3 Ω 및 R3 = 4 Ω. All three resistors are connected in series. What is the value of the equivalent resistor? (Ω = 옴).
해결 방법 :
R = R1 + R2 + R3 = 2 + 3 + 4 = 9 Ω.
This result indicates that the equivalent resistance is greater than the value of the resistors connected in series.
Sample problem 2:
Two resistors R1 = 50 Ω and 50 Ω are connected in series and connected to a 12 Volt battery. Determine
(a) 등가 저항
(b) 각 저항기를 통과하는 전류
해결 방법 :
(a) R = R1 + R2 = 50Ω + 50Ω = 100Ω.
(b) I = V / R = 12 Volt / 100 Ω = 0.12 A
