Teoria cinetica dei gas: problemi e soluzioni

1. Ideal gases in a contenitore chiuso initially have volume V and pressione P. If the final pressure is 4P and the volume is kept constant, what is the ratio of the initial kinetic energy with the final energia cinetica.

Conosciuto :

Pressione iniziale (P₁) = P

Pressione finale (P₂) = 4P

Volume iniziale (V₁) = v

Volume finale (V₂) = v

Ricercato: The ratio of the initial kinetic energy with the final kinetic energy (KE₁ :KE₂)

soluzione:

The relation between pressure (P), volume (V) and kinetic energy (KE) of ideal gases :

The ratio of the initial kinetic energy with the final kinetic energy :

2. What is the average translational kinetic energy of molecules in an ideal gas at 57^oC.

Conosciuto :

Temperature of gas (T) = 57^oC + 273 = 330 Kelvin

Boltzmann‘s constant (k) = 1.38 x 10 ^{all'23 ottobre} Joule/Kelvin

Ricercato: The average translational kinetic energy

soluzione:

The relation between kinetic energy (KE) and the temperatura of the gas (T) :

The average translational kinetic energy :

3. A gas at 27^oC in un contenitore chiuso. If the kinetic energy of the gas increases 2 times the initial kinetic energy, thus the final temperature of the gas is…

Conosciuto :

Temperatura iniziale (T₁) = 27^oC + 273 = 300 K

Initial kinetic energy = kE

Final kinetic energy = 4 KE

Ricercato: La temperatura finale (T₂)

soluzione:

4. An ideal gas is in a closed container, is heated so that the final velocità media of particles of gas increases by 3 times the initial average velocity. If the initial gas temperature is 27^oC, then the final temperature of the ideal gas is…

Conosciuto :

Temperatura iniziale = 27^oC + 273 = 300 Kelvin

Velocità iniziale = v

Velocità finale = 2v

Ricercato : The final temperature of ideal gas

soluzione:

The final average velocity = 2 x the initial average velocity

5. Three moles of gas are in a 36 liters volume space. Each gas molecule has a kinetic energy of 5 x 10 ^{all'21 ottobre} Joule. Universal gas constant = 8.315 J/mole.K and Boltzmann’s constant = 1.38 x 10 ^{all'23 ottobre} J/K. What is the gas pressure in the container.

Conosciuto :

Number of moles (n) = 3 moles

Volume = 36 liters = 36 dm³ = 36 x 10^-3 m³

Boltzmann’s constant (k) = 1.38 x 10 ^{all'23 ottobre} J / K

Kinetic energy (KE) = 5 x 10^-21 Joule

Universal gas constant (R) = 8.315 J/mole.K

Ricercato : Gas pressure (P)

soluzione:

Calculate the temperature using the equation of kinetic energy of gas.

Calculate the gas pressure using th equation of ideal gas law (in number of moles, n) :

PV = n RT

P (36 x 10^-3) = (3)(8.315)(241.5)

P (36 x 10^-3) = 6024.22

The gas pressure is 1.67 x 10⁵ Pascal or 1.67 atmospheres.