1. Oke ihe = 2 kg, osooso n'ihi ike ndọda = 9.8 m/s 2 , osooso nke esemokwu static = 0.2, osooso nke esemokwu kinetic = 0.1. Ihe ahụ ọ na-ezu ike ka ọ na-eme ngwa ngwa? Ọ bụrụ na ihe ahụ apụta ngwa ngwa, chọta (a) ike net (b) na ntụziaka nke osooso igbe ahụ!

ngwọta

A maara:
Ibu (m) = 2 kg
Ọsọ ọsọ nke ike ndọda (g) = 9.8 m/s 2
Ọnụọgụ nke esemokwu na-anaghị agbanwe agbanwe ( μs ) = 0.2
Ọnụọgụ nke esemokwu kinetic ( μk ) = 0.1
Ibu (w) = mg = (2)(9.8) = 19.6 Newtons
Akụkụ kwụ ọtọ nke ibu ahụ (w x ) = w sin 30 o = (19.6)(0.5) = 9.8 Newtons
Akụkụ kwụ ọtọ nke arọ ahụ (w y ) = w cos 30 o = (19.6)(0.5√3) = 9.8√3 Newtons
Ike nkịtị (N) = w y = 9.8√3 Newtons
Ike nke esemokwu na-anaghị agbanwe agbanwe (f s ) = (0.2)(9.8√3) = 1.96√3 Newton = 3.39 Newton
Ike nke esemokwu kinetic (f k ) = (0.1)(9.8√3) = 0.98√3 Newton = 1.69 Newton
Ngwọta:
Ihe ahụ zuru ike ma ọ bụrụ na w x <fs s , ihe ahụ na-aga n'ihu ma ọ bụrụ w x > fs s.
w x = 9.8 Newtons na f s = 3.39 Newtons.
(a) ike netwọk
∑ F = w x – f k = 9.8 – 1.69 = 8.11 Newtons
(b) nha na ụzọ nke osooso ahụ
∑ F = ma
8.11 = (2) a
na = 4.05
Oke nke osooso = 4.05 m/s 2 na ntụziaka nke osooso = ala.
[irp]
2. Oke ihe = 4 kg, osooso n'ihi ike ndọda = 9,8 m/s 2. Ọnụọgụ nke esemokwu kinetic = 0.2 na coefficient nke esemokwu static = 0.4. Oke nke ike F = 40 Newtons. Ihe ahụ na-ezu ike ma ọ bụ na-amịda ala? Ọ bụrụ na ihe ahụ amịda ala, chọta (a) ike net (b) nha na ntụziaka nke osooso!

ngwọta

A maara:
Ibu (m) = 4 kg
Ọsọ ọsọ nke ike ndọda (g) = 9.8 m/s 2
Ọnụọgụ nke esemokwu na-anaghị agbanwe agbanwe ( μs ) = 0.4
Ọnụọgụ nke esemokwu kinetic ( μk ) = 0.2
Ibu (w) = mg = (4)(9.8) = 39.2 Newtons
Akụkụ kwụ ọtọ nke ibu ahụ (w x ) = w sin 30 o = (39.2)(0.5) = 19.6 Newtons
Akụkụ kwụ ọtọ nke ibu ahụ (w y ) = w cos 30 o = (392)(0..5√3) = 19.6√3 Newtons
Ike nkịtị (N) = w y = 19.6√3 Newtons = 33.95 Newtons
ike esemokwu na-anaghị agbanwe agbanwe (f s ) = μ s N = (0,4)(33.95) = 13.58 Newtons
Ike esemokwu kinetic (f k ) = μ k N = (0.2)(33.95) = 6.79 Newtons
F = 40 Newton
Ngwọta:
Ihe ahụ na-amịda ala ma ọ bụrụ na F <w x + f s . Ihe ahụ na-amịda elu ma ọ bụrụ na F > w x + f s.
F = Newton 40, w x = 19.6 Newton na f s = 13.58 Newtons.
F karịrị w x + f s ya mere ihe ahụ na-amị amị elu.
(a) Ike ụgbụ
∑ F = F – w x – f k = 40 – 19.6 – 6.79 = 13.61 Newtons
(b) Oke na ụzọ nke osooso ahụ
∑ F = ma
6.4 = (4) a
na = 1.6
Oke nke ọsọ ọsọ ahụ bụ 1.6 m/s 2 , ebe ụzọ ọsọ ọsọ ahụ dị elu.
[irp]
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