Ihe atụ nke itinye iwu mbụ nke thermodynamics n'ọrụ na usoro isobaric (nrụgide na-adịgide adịgide)

6 Ihe atụ nke ajụjụ gbasara itinye iwu mbụ nke thermodynamics n'ọrụ na usoro isobaric (nrụgide na-adịgide adịgide)

1. Nrụgide (P) - eserese olu (V) nke gas na-agafe usoro isobaric. Ọrụ gas na-arụ n'usoro AB bụ…

Ihe atụ nke itinye iwu mbụ nke thermodynamics n'ọrụ na usoro isobaric nrụgide na-aga n'ihu 1Mkparịta ụka

A maara :
Nrụgide (P) = 5 x 105 Nkem2
Mpịakọta mbụ (V)1) = 2 mita3
Mpịakọta ikpeazụ (V)2) = 6 mita3
A jụrụ : ọrụ emere na usoro AB
Jawab :
W = P (V)2 - V1)
W = (5 x 105)(6 – 2) = (5 x 10)5(4)
W = 20 x 105 = 2 x106 Joule

2. Ihe dị iche n'ọrụ gas na-arụ na usoro AB na CD bụ…

Ihe atụ nke itinye iwu mbụ nke thermodynamics n'ọrụ na usoro isobaric nrụgide na-aga n'ihu 2Mkparịta ụka

A maara :
Usoro isobaric AB :
Nrụgide (P) = 6 atm = 6 x 105 Nkem2
Mpịakọta mbụ (V)1) = lita 1 = 1 dm3 = 1 x10-3 m3
Mpịakọta ikpeazụ (V)2) = lita 3 = 3 dm3 = 3 x10-3 m3 
Usoro isobaric CD :
Nrụgide (P) = 4 atm = 4 x 105 Nkem2
Mpịakọta mbụ (V)1) = lita 2 = 2 dm3 = 2 x10-3 m3
Mpịakọta ikpeazụ (V)2) = lita 5 = 5 dm3 = 5 x10-3 m3
A jụrụ : Ọdịiche dị n'ọrụ gas na-arụ na usoro AB na CD
Jawab :
Ọrụ gas na-arụ n'oge usoro AB:
W = P (V)2 - V1)
W = (6 x 105)(3 x 10-3 - 1 x 10-3)
W = (6 x 105)(2 x 10-3)
W = 12 x 102 = 1200 Joule
Ọrụ gas rụrụ na usoro CD:
W = P (V)2 - V1)
W = (4 x 105)(5 x 10-3 - 2 x 10-3)
W = (4 x 105)(3 x 10-3)
W = 12 x 102 = 1200 Joule
Ihe dị iche n'ọrụ gas na-arụ na usoro AB na CD bụ 1200 – 1200 = 0.

3. Ọrụ gas na-arụ n'usoro ABC bụ…

Ihe atụ nke itinye iwu mbụ nke thermodynamics n'ọrụ na usoro isobaric nrụgide na-aga n'ihu 3Mkparịta ụka
A maara :
Nrụgide 1 (P)1) = 6 x 105 Pascal = 6 x 105 Nkem2
Nrụgide 2 (P)2) = 3 x 105 Pascal = 3 x 105 Nkem2
Mpịakọta nke 1 (V)1) = 2cm3 = 2 x10-6 m3
Mpịakọta nke 2 (V)2) = 6cm3 = 6 x10-6 m3
A jụrụ : Mgbalị ndị e mere n'usoro ABC.
Jawab :
N'ime usoro AB, olu ya na-agbanwe agbanwe, yabụ na gas anaghị arụ ọrụ ọ bụla. Gas ahụ na-arụ ọrụ naanị na usoro BC. Ya mere, ọrụ dị na usoro ABC = ọrụ dị na usoro BC.
W = P2 (V2 - V1)
W = (3 x 105)(6 x 10-6 - 2 x 10-6)
W = (3 x 105)(4 x 10-6)
W = 12 x 10-1
W = Joule 1,2
Ọrụ e mere na usoro ABC = 1,2 Joules.

4. Okwu ziri ezi gbasara usoro thermodynamic bụ…
A. Isobaric bụ usoro nke ịgbanwe gas na nrụgide na-adịgide adịgide.
B. Isobaric bụ usoro nke ịgbanwe gas na okpomọkụ na-agbanwe agbanwe.
C. Isochoric bụ usoro nke ịgbanwe gas na nrụgide na-adịgide adịgide.
D. isotherm bụ usoro nke ịgbanwe gas na olu na-agbanwe agbanwe.
E. Isochoric bụ usoro nke ịgbanwe gas na okpomọkụ na-agbanwe agbanwe.
Mkparịta ụka
Isobaric = nrụgide na-adịgide adịgide
Isochoric = olu na-agbanwe agbanwe
Isothermal = okpomọkụ na-agbanwe agbanwe
Azịza ziri ezi bụ A.

5. Ntụnyere mgbalị dị na usoro I na II dabere na eserese dị n'okpuru bụ...
A. 4: 3
B. 3: 4
C. 2: 3
D. 1:2
E. 1: 3
Mkparịta ụka:

Iwu nke abụọ nke thermodynamics 1

A maara :
Usoro nke Mbụ: P = 15 N/m2, V1 = 15 m3, V2 = 35 m3
Usoro nke Abụọ: P = 10 N/m2, V1 = 5 m3, V2 = 45 m3
A jụrụ :
Ntụnyere mgbalị (W) nke usoro I na usoro II?
Jawab :
Iwu nke abụọ nke thermodynamics 2Azịza ziri ezi bụ B.

6. E gosiri eserese PV nke gas helium nke na-agafe usoro thermodynamic n'elu foto dị n'okpuru! Ọrụ nke gas helium na-arụ n'usoro ABC bụ…
A. 400 kJ
B. 500 kJ
C. 600 kJ
D. 800 kJ
E. 1000 kJ

Iwu nke abụọ nke thermodynamics 3Mkparịta ụka:
A maara :
P1 = 2 x105 Nkem2
P2 = 1 x105 Nkem2
V1 = 5 m3
V2 = 15 m3
A jụrụ :
Ọrụ (W) n'usoro ABC?
Jawab :
A na-arụ ọrụ naanị mgbe olu gas na-abawanye. N'usoro AB, olu gas na-anọgide na-agbanwe agbanwe, yabụ na gas helium anaghị arụ ọrụ ọ bụla. N'usoro BC, olu gas na-abawanye, yabụ na gas helium na-arụ ọrụ.

Iwu nke abụọ nke thermodynamics 4

 

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