Ihe atụ nke iwu Charles (nrụgide isobaric/nrụgide na-adịgide adịgide)

3 Contoh soal hukum Charles (isobarik/tekanan konstan)

1. Dalam suatu wadah tertutup, gas memuai sehingga volumenya berubah menjadi 3 kali volume awal (V = volume awal, T = suhu awal). Suhu gas berubah menjadi…

Mkparịta ụka
A maara :
Mpịakọta mbụ (V)1) = V
Mpịakọta ikpeazụ (V)2) = 3V
Okpomọkụ mbụ (T)1) = T
A jụrụ : okpomọkụ ikpeazụ (T)2)

GỤKWUO

Ihe atụ nke iwu Boyle (okpomọkụ isothermal-constant)

Ihe atụ atọ nke iwu Boyle (okpomọkụ isothermal-constant)

1. Oke gas dị mma na mbụ nwere nrụgide nke P na olu nke V. Ọ bụrụ na gas ahụ emee usoro isothermal nke na nrụgide ahụ ga-aghọ okpukpu anọ nke nrụgide mbụ, olu nke gas ahụ ga-agbanwe gaa...
Mkparịta ụka
A maara :
Nrụgide mbụ (P)1) = P
Nrụgide ikpeazụ (P)2) = 4P
Mpịakọta mbụ (V)1) = V
A jụrụ : olu ikpeazụ nke gas (V2)

GỤKWUO

Ihe atụ nke usoro mmiri

Ihe atụ anọ nke usoro oge opupu ihe ubi

1. E debere isi iyi ise, nke ọ bụla nwere ike na-agbanwe agbanwe nke 200 N/m, n'usoro. Ihe na-agbanwe agbanwe nke oge opupu ihe ubi nke nhazi oge opupu ihe ubi bụ…

Mkparịta ụka
A maara na:
Ọnụọgụ nke oge opupu ihe ubi ọ bụla (k)1 = k2 = k3 = k4 = k5) = 200 N/m
A jụrụ: nnọchi oge opupu ihe ubi (k)
Azịza:

GỤKWUO

Ihe atụ nke nhazi usoro-ntụnyere nke isi iyi

Ihe atụ anọ nke ndokwa oge opupu ihe ubi yiri usoro

1. A na-ahazi isi iyi atọ yiri ibe ha, nke ọ bụla nwere ihe na-agbanwe agbanwe nke 200 N/m, n'usoro ma na-adakọkwa dịka egosiri na foto dị n'okpuru. A na-akwụsịtụ ibu w site na nsọtụ ala nke isi iyi, na-eme ka ogologo nke isi iyi ahụ dịkwuo elu site na 1 cm. Ibu nke ibu w bụ…
Ihe atụ nke usoro-nhazi-n'usoro-nke-mmiri-1Mkparịta ụka
A maara na:
Ọnụọgụ nke oge opupu ihe ubi ọ bụla (k)1 = k2 = k3) = 200 N/m
Mmụba n'ogologo nke sistemụ mmiri (x) = 1 cm = 0,01 mita
A jụrụ: ibu ibu (w)

GỤKWUO

Ihe atụ nke ndokwa yiri nke isi iyi

Ihe atụ atọ nke ndokwa oge opupu ihe ubi yiri nke ahụ

1. E doziri isi iyi ise, nke ọ bụla nwere ike na-agbanwe agbanwe nke 100 N/m, n'otu oge. Ihe na-agbanwe agbanwe nke oge opupu ihe ubi nke nhazi oge opupu ihe ubi bụ…

Mkparịta ụka
A maara na:
Ọnụọgụ nke oge opupu ihe ubi ọ bụla (k)1 = k2 = k3 = k4 = k5) = 100 N/m
A jụrụ: nnọchi oge opupu ihe ubi (k)
Azịza:

GỤKWUO

Ihe atụ nke iwu Hooke

Ihe atụ 9 nke ajụjụ gbasara iwu Hooke

1. E gosiri eserese nke mmekọrịta dị n'etiti ike (F) na mmụba n'ogologo (x) na foto dị n'okpuru. Ihe na-agbanwe agbanwe nke oge opupu ihe ubi dabere na eserese ahụ bụ…
Ajụjụ Ihe Nlereanya nke Iwu Hooke nke 1Mkparịta ụka
Rumus Iwu Hooke :
k = F / x
Ozi:
F = ike (Ngalaba mba ụwa bụ Newton, nke a kpọrọ N)
k = ihe na-agbanweghi agbanwe nke oge opupu ihe ubi (nkeji mba ụwa bụ Newton/mita, nke a kpọrọ N/m)
x = mmụba n'ogologo (nkeji mba ụwa bụ mita, nke a kpọrọ m)

GỤKWUO

Ihe atụ nke nkukota nke na-agbanwe agbanwe nke ọma

Ihe atụ 8 nke nkpọkọ na-agbanwe agbanwe nke ọma

1. Bọọlụ A na Bọọlụ B, nke ọ bụla nwere ibu nke gram 200, na-agbakọta n'ụzọ na-agbanwe agbanwe nke ọma. Ọ bụrụ na tupu mgbawa ahụ, bọọlụ A na-agagharị na ọsọ nke m10/s na bọọlụ B na-ezu ike, mgbe ahụ ọsọ nke bọọlụ A na bọọlụ B mgbe mgbawa ahụ gasịrị bụ...

Mkparịta ụka
A maara :
Ibu nke bọọlụ A (m)A) = gram 200 = 0,2 kg
Ibu nke bọọlụ B (m)B) = gram 200 = 0,2 kg
Ọsọ nke bọọlụ A tupu ihe mgbawa ahụ (v)A) = 10 m/s
Ọsọ nke bọọlụ B tupu ihe mgbawa ahụ (v)B) = 0

GỤKWUO