1. Két egyszerű inga két különböző helyen van. A második inga hossza 0.4-szerese az első inga hosszának, és a gyorsulásn gravitációs által tapasztalt a második inga gyorsulása a nehézségi gyorsulás 0.9-szerese által tapasztalt az első inga. Határozza meg a c-tösszehasonlítása a gyakorisága Az első inga hoz másodikd inga.
A. 2/3
B. 3/2
C. 4/9
D. 9/4
Ismert:
The length of the cord of the first pendulum (l1) = 1
The length of cord of the second pendulum (l2) = 0.4 (l1) = 0.4 (1) = 0.4
Acceleration due to the gravity of the first pendulum (g1) = 1
Acceleration due to gravity of the second pendulum (g2) = 0.9 (1) = 0.9
Wanted: The comparison of the frequency of the first pendulum (f1) to the second pendulum (f2)
megoldás:
The comparison of the frequency of the first pendulum (f1) to the second pendulum (f2):
A helyes válasz A.
2. An object is suspended from egy end of a cord és azután végezzen a simple harmonic motion with a frequency of 0.5 Hertz. If the length of the cord is increased by four times the initial length, then determine the period of the harmonic motion.
A. ¼ seconds
B. ½ seconds
Kb. 2 másodperc
D. 4 másodperc
Ismert:
Frequency of pendulum (f) = 0.5 Hz
Wanted: Determine the period (T) of the pendulum if the length of cord (L) is four times the initial length
megoldás:
időszak of the first pendulum :
The initial length of cord :
If the length of the cord is increased by four times the initial length :
Then the period of a pendulum is :
The period of motion is 4 másodperc.
A helyes válasz D.
3. Two pendulums with the same length of its cord, but the mass of the second pendulum is four times the mass of the first pendulum. If f1 is the frequency of the first pendulum and f2 is the frequency of the second pendulum, then determine the relationship between f1 és a f2.
A. f1 = f2
B. f1 = 2 f2
C. f2 = 2 f1
D. f1 = 4 f2
megoldás:
The equation of frequency of the simple pendulum :
f = frequency, g = acceleration due to gravity, l = the length of cord
Based on the equation above, can conclude that tömeg does not affect the frequency of the simple pendulum.
A helyes válasz A.
4. The quantities below that do not impact the period of the simple pendulum are…..
A. length of cord and mass of the object
B. length of cord and acceleration due to gravity
C. mass of the object and initial angle
D. length of cord and initial angle
megoldás:
The equation of period of the simple pendulum :
T = period, g = acceleration due to gravity, l = length of cord
Based on the above formula, can conclude the length of the rúd (l) and the acceleration of gravity (g) impact the period of the simple pendulum. Otherwise, the mass of az objektum és a kezdeti szög does not impact the a simple pendulum.
A helyes válasz C.
5. The rope of the simple pendulum made from nylon. At one end of the rope suspended a mass of 10 gram and length of rope is 1 meter. If the frequency produced twice the initial frequency, then the length of the rope must be changed to…
A. 0.25 méter
B. 0.50 méter
C. 2.0 méter
D. 4.0 méter
Ismert:
The mass does not impact the frequency of the simple pendulum.
The length of the cord of the simple pendulum (l) = 1 meter
Wanted: determine the length of rope if the frequency is twice the initial frequency
megoldás:
The initial frequency of the simple pendulum :
The frequency of the simple pendulum is twice the initial frequency :
Minden a utolsó frequency to be doubled, the length of the pendulum should be changed to 0.25 meters.
A helyes válasz A.
