Cov lus nug piv txwv txog kev txiav txim siab txog cov khoom vector

2 Piv txwv ntawm cov lus nug txog kev txiav txim siab cov khoom vector

1. Lub zog vector F = 20 Newton tsim lub kaum sab xis ntawm 30 o rau qhov x-axis zoo. Txheeb xyuas cov khoom ntawm vector F ntawm x-axis (F x ) thiab y-axis (F y ).

Piv txwv ntawm kev txiav txim siab cov khoom ntawm vector-1Kev Sib Tham
Fx = F cos 30o = (20)(cos 30o) = (20)(0,5√3) = 10√3 Newtons
Fy = F txhaum 30o = (20)(kev txhaum 30o) = (20)(0,5) = 10 Newtons

2. Vector F 1 = 20 Newton tsim lub kaum sab xis ntawm 30 o nrog rau qhov y-axis zoo thiab F 2 = 30 Newton tsim lub kaum sab xis ntawm 60 o nrog rau qhov x-axis tsis zoo. Txheeb xyuas cov khoom ntawm vectors F 1 thiab F 2 ntawm x-axis thiab ntawm y-axis.

Piv txwv ntawm kev txiav txim siab cov khoom ntawm vector-2Kev Sib Tham
F1x =F1 coj 60o = (20)(cos 60o) = (20)(0,5) = -10 Newton (tsis zoo vim nws nyob rau hauv qhov kev taw qhia x tsis zoo)
F2x =F2 coj 60o = (30)(cos 60o) = (30)(0,5) = -15 Newton (tsis zoo vim nws nyob rau hauv qhov kev taw qhia x tsis zoo)
F1y =F1 kev txhaum 60o = (20)(kev txhaum 60o) = (20)(0,5√3) = 10√3 Newton (zoo vim nws nyob rau hauv qhov kev taw qhia y zoo)
F2y =F2 kev txhaum 60o = (30)(kev txhaum 60o) = (30)(0,5√3) = -15√3 Newton (tsis zoo vim nws nyob rau hauv qhov kev taw qhia y tsis zoo)

3. F 1 = 2 N, F 2 = 4 N, F 3 = 6 N. Txheeb xyuas cov khoom ntawm cov vectors F 1 , F 2 thiab F 3 ntawm x thiab y axes!

Piv txwv ntawm kev txiav txim siab cov khoom ntawm vector-3Kev Sib Tham
F1x =F1 coj 60o = (2)(cos 60o) = (2)(0,5) = 1 Newton (zoo vim nws nyob rau hauv qhov kev taw qhia x zoo)
F2x =F2 coj 30o = (4)(cos 30o) = (4)(0,5√3) = -2√3 Newton (tsis zoo vim nws nyob rau hauv qhov kev taw qhia x tsis zoo)
F3x =F3 coj 60o = (6)(cos 60o) = (6)(0,5) = 3 Newton (zoo vim nws nyob rau hauv qhov kev taw qhia x zoo)
F1y =F1 kev txhaum 60o = (2)(kev txhaum 60o) = (2)(0,5√3) = √3 Newton (zoo vim nws nyob rau hauv qhov kev taw qhia y zoo)
F2y =F2 kev txhaum 30o = (4)(kev txhaum 30o) = (4)(0,5) = 2 Newton (zoo vim nws nyob rau hauv qhov kev taw qhia y zoo)
F3y =F3 kev txhaum 60o = (6)(kev txhaum 60o) = (6)(0,5√3) = -3√3 Newton (tsis zoo vim nws nyob rau hauv qhov kev taw qhia y tsis zoo)

Cov lus nug txog kev txiav txim siab txog cov khoom vector

1. Lub zog vector F = 8 Newton tsim lub kaum sab xis ntawm 60o rau qhov x-axis zoo. Txheeb xyuas cov khoom ntawm vector F ntawm x-axis (Fx) thiab y-axis (Fy).
2. Vector F1 = 8 Newtons tsim ib lub kaum sab xis ntawm 45o mus rau qhov y-axis zoo thiab F2 = 10 Newtons tsim ib lub kaum sab xis ntawm 30o rau qhov tsis zoo x-axis. Txheeb xyuas cov khoom ntawm vector F1 thiab F2 ntawm x-axis thiab ntawm y-axis.
3. F1 = 4 N, F2 = 8 N, F3 = 12 N. Txheeb xyuas cov khoom ntawm lub vector F1, F2 thiab F3 ntawm x-axis thiab y-axis!

Cov lus nug txog kev txiav txim siab cov khoom ntawm vector-1

[Lus Askiv: Kev daws cov teeb meem vectors - kev txiav txim siab txog cov khoom vector ]

Sau ib qho lus tawm tswv yim