9 Converting temperature scales (Celsius scale Fahrenheit scale Kelvin scale)
1। 50 oC = ….. oF ?
उपाय
At standard atmospheric दबाव, the freezing point of water is 0 oC on the सेल्सियस पैमाने पर और 32 oF on the Fahrenheit scale. At standard atmospheric pressure, the boiling point of water is 100 oC on the Celsius scale and 212 oF on the Fahrenheit scale.
0 oसी = 32 oएफ और 100 oसी = 212 oF. A change of 5 Co = a change of 9 Fo.
For a Celsius scale, the distance between 0 oC और 100 oC divided into 100 equal intervals. For a Fahrenheit scale, the distance between 0 oC और 100 oC divided into 180 equal intervals.
ToF = (180/100) Toसी+32
ToF = (9/5) Toसी+32
ToF = (9/5) 50 + 32
ToF = (9) 10 + 32
Toएफ = 90 + 32
Toएफ = 122
50 oसी = 122 oF
2। 86 oF = ….. oC ?
उपाय
ToC = (100/180)(ToF – 32)
ToC = (5/9)(ToF – 32)
ToC = (5/9)(86 – 32)
ToC = (5/9)(54)
ToC = (5)(6)
Toसी = 30
86 oएफ = 30 oC
3। 50oC = ….. K ?
उपाय
टी = टी oसी+273
टी = 50 + 273
टी = 323
50 oसी = 323 कश्मीर
4। 212oF = ….. K ?
उपाय
ToC = (100/180)(ToF – 32)
ToC = (5/9)(ToF – 32)
ToC = (5/9)(212 – 32)
ToC = (5/9)(180)
ToC = (5)(20)
Toसी = 100
212 oएफ = 100 oसी+273
212 oएफ = 373 K
5. एक्स oC = x oF
x = ….. ?
उपाय
1 : Converting Celsius scale into Fahrenheit scale

2 : Converting Fahrenheit scale into Celsius scale

6. 122°F = ….. Celsius
उपाय
The conversion between the two temperature scales can be written :
TC = 5/9 (TF - एक्सएनएनएक्स)
TC = तापमान in Celsius, TF = temperature in Fahrenheit
The temperature in Celsius :
TC = 5/9 (122 – 32) = TC = 5/9 (90) = 5 (10)
TC = 50 oC
7. The figure below shows the temperature measurement of a liquid with the Fahrenheit scale thermometer! If the temperature of the liquid is measured using a Celsius scale thermometer, then क्या है the liquid temperature.
ज्ञात :
फारेनहाइट स्केल (TF) = 95oF
वांछित : सेल्सियस पैमाने पर
समाधान:
At a pressure of 1 atm, पानी का हिमांक is 0 °C while the Fahrenheit scale is 32 oF. Conversely, the boiling point of water for the Cएल्सियस scale is 100 oC while the Fahrenheit scale is 212 oF.
On the Celsius scale, between 0 °C and 100 ° C there are 100 ° while on the Fahrenheit scale between 32 °F to 212 °F there is 180°.
TC = 100/180 (TF - एक्सएनएनएक्स)
TC = 5/9 (TF - एक्सएनएनएक्स)
TC = 5/9 (95 - एक्सएनएनएक्स)
TC = 5/9 (63)
TC = 315 / 9
TC = 35oC
8. Based on figure below, determine the temperature P on the Celsius thermometer.
उपाय
TC = 100/180 (TF - एक्सएनएनएक्स) 
TC = 5/9 (TF - एक्सएनएनएक्स)
TC = 5/9 (104 – 32)
TC = 5/9 (72)
TC = 360 / 9
TC = 40 oC
9. If the temperature of Celsius scale as shown in figure below, determine the temperature of Fahrenheit scale as shown in figure below.
समाधान:
ToF = (180/100) Toसी+32
ToF = (9/5) Toसी+32
ToF = (9/5) 60 + 32
ToF = (9) 12 + 32
Toएफ = 108 + 32
Toएफ = 140
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