1. ʻElua mau nuipa m 1 = 2 kg a me m 2 = 5 kg ma kahi mokulele incline a ua hoʻopili ʻia lāua e ke kaula e like me ka mea i hōʻike ʻia ma ke kiʻi. ʻO ke coefficient o ka friction kinetic ma waena o m 1 a me ka incline he 0.2 a ʻo ke coefficient o ka friction kinetic ma waena o m 2 a me ka incline he 0.1.
(a) E hoʻoholo i ko lākou wikiwiki
(b) E hoʻoholo i ka ikaika hoʻoluhi

ʻIke ʻia:
Nuipaʻa 1 (m1 ) = 2 kg
Nuipaʻa 2 (m2 ) = 4 kg
ʻO ke koina o ka friction kinetic ma waena o m 1 a me ka mokulele inclined (μ k1 ) = 0.2
ʻO ke koina o ka friction kinetic ma waena o m 2 a me ka mokulele inclined (μ k 2 ) = 0.1
Ka wikiwiki ma muli o ke koʻikoʻi (g) = 9.8 m/s 2
a) Ka nui a me ke kuhikuhi o ka hoʻolalelale

w 1 = kaumaha 1 = m 1 g = (2 kg)(9.8 m/s 2 ) = 19.6 Newtons
w 1x = w 1 sin 30 o = (19.6 N)(0.5) = 9.8 Newtons
w 1y = w 1 cos 30 o = (19.6 N)(0.87) = 17 Newtons
N 1 = Ka ikaika maʻamau ma m 1 = w 1y = 17 Newtons
F k1 = Ka ikaika o ka friction kinetic ma m 1 = μ k1 N 1 = (0.2)(17 N) = 3.4 Newtons
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w 2 = kaumaha 2 = m 2 g = (4 kg)(9.8 m/s 2 ) = 39.2 Newtons
w 2x = w 2 hewa 60 o = (39.2 N)(0.87) = 34.1 Newtons
w 2y = w 2 cos 60 o = (39.2 N)(0.5) = 19.6 Newtons
N 2 = Ka ikaika maʻamau ma m 2 = w 2y = 19.6 Newtons
F k2 = Ka ikaika o ka friction kinetic ma m 2 = μ k2 N 2 = (0.1)(19.6 N) = 1.96 Newtons
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Ka nui o ka hoʻolalelale ʻana:
∑ F x = ma x
ʻO w 2x > w 1x no laila ua like ke kuhikuhi o ka hoʻolalelale me ke kuhikuhi o w 2x.
He maikaʻi nā mana e kuhikuhi ana ma ka wikiwiki a he maikaʻi ʻole nā mana e kuhikuhi ana ma ka ʻaoʻao kūʻē i ka wikiwiki.
w2x - Fk2 - T2 +T1 - w1x - Fk1 = (m1 +m2) ax
w 2x – F k2 – w 1x – F k1 = (m 1 + m 2 ) a x
34.1 N – 1.96 N – 9.8 N – 3.4 N = (2 kg + 4 kg) a x
18.94 N = (6 kg) a x
a x = 18.94 N : 6 kg
a x = 3.16 m/s 2
Ka nui o ka hoʻolalelale = 3.16 m/s² . Ke kuhikuhi o ka hoʻolalelale = ke kuhikuhi o T 1 = ke kuhikuhi o w 2x
b) Ka nui o ka ikaika hoʻoluhi
E hoʻopili i ke kānāwai ʻelua o Newton ma ka mea 2:
w 2x – F k2 – T 2 = m 2 a x
34.1 N – 1.96 N – T 2 = (4 kg)(3.16 m/s 2 )
32.14 N – T 2 = 12.64 N
T 2 = 32.14 N – 12.64 N = 19.5 Newtons
ʻO ka ikaika hoʻoluhi = T = T 1 = T 2 = 19.5 Newtons
ʻAʻole maopopo
2. m 1 = 4 kg, m 2 = 2 kg. E hoʻoholo i (a) ka nui a me ke kuhikuhi o ka wikiwiki (b) Ka nui o ka ikaika ume e hoʻopili ai iā m 1 a me m 2 (c) ka nui o ka ikaika ume e hoʻopili ai i ka pulley a me ka hale.

pāʻoihana

w 1 = m 1 g = (4 kg)(9.8 m/s 2 ) = 39.2 Newtons
w 2 = m 2 g = (2 kg)(9.8 m/s 2 ) = 19.6 Newtons
a) Ka nui a me ke kuhikuhi o ka hoʻolalelale
∑ F y = ma y
ʻO w 1 > w 2 no laila ua like ke kuhikuhi o ka mea me ke kuhikuhi o ke kaumaha 1 ( w 1 ) . He maikaʻi nā ikaika i loaʻa ke kuhikuhi like me ka wikiwiki a he maikaʻi ʻole nā ikaika i loaʻa ke kuhikuhi kū'ē me ka wikiwiki.
w 1 – T 1 + T 2 – w 2 = (m 1 + m 2 ) a y
w 1 – w 2 = (m 1 + m 2 ) a y
39.2 N – 19.6 N = (4 kg + 2 kg) i kēlā me kēia makahiki
19.6 N = (6 kg) a y
a y = 19.6 N : 6 kg
a y = 3.26 m/s 2
Ka nui o ka hoʻolalelale = 3.26 m/s² . Ke kuhikuhi o ka hoʻolalelale = ke kuhikuhi o w1.
b) Ka nui o ka ikaika ume e hoʻopili ai iā m 1 a me m 2
E hoʻopili i ke kānāwai ʻelua o Newton ma m 2 :
∑ F y = ma y
w 1 – T 1 = m 1 a y
39.2 N – T 1 = (4 kg)( 3.26 m/s 2 )
39.2 N – T 1 = 13.04 N
T 1 = 39.2 N – 13.04 N
T 1 = 26.16 Newton
Ka nui o ka ikaika ume e hoʻopili ai i nā mea = T = T 1 = T 2 = 26.16 Newtons
c) Ka nui o ka ikaika ume e hoʻohui ai i ka pulley a me ka hale.
Ua hoʻomaha ʻo Pulley:
∑ F y = ma y —— a y = 0
∑ F y = 0
He maikaʻi nā mana i luna, he maikaʻi ʻole nā mana i lalo:
T 3 – T 1 – T 2 = 0
T3 = T1 + T2
Ua like ka nui o T 1 a me T 2 , T 1 = T 2 = T = 26.16 N :
T 3 = 2T = 2(26.16 N) = 52.32 Newtons
ʻAʻole maopopo
3. ʻO ka poloka 1 (m 1 = 10 kg) a me ka poloka 2 (m 2 = 15 kg) i hoʻopili ʻia e ke kaula ma luna o ka pulley frictionless. ʻO ke koina o ka friction static ma waena o ka poloka 2 me ka incline = 0.6. ʻO ke koina o ka friction kinetic ma waena o ka poloka 2 me ka incline = 0.42. E hoʻoholo (a) ʻO ka nui o ka ikaika liʻiliʻi F i hoʻokau ʻia ma luna o nā mea i wikiwiki ai nā mea i luna (b) E hoʻoholo i ka nui o ka ikaika tension.

pāʻoihana

w 1 = Ke kaumaha o ka poloka 1 = m 1 g = (10 kg)(9.8 m/s 2 ) = 98 Newtons
w 2 = Ke kaumaha o ka poloka 2 = m 2 g = (15 kg)(9.8 m/s 2 ) = 147 Newtons
w 2y = w 2 cos 30 o = (147 N)(0.87) = 127.89 Newtons
w 2x = w 2 hewa 30 o = (147 N)(0.5) = 73.5 Newtons
N 2 = Ka ikaika maʻamau ma ka poloka 2 = w 2y = 127.89 Newtons
F k2 = Ka ikaika o ka friction kinetic ma ka poloka 2 = μ k2 N 2 = (0.42)(127.89 N) = 53.7 Newtons
F s2 = Ka ikaika o ka haʻalulu paʻa ma ka poloka 2 = μ s2 N 2 = (0.6)(127.89 N) = 76.7 Newtons
a) ʻO ka nui o ka ikaika liʻiliʻi loa F i hoʻokau ʻia ma luna o nā mea i wikiwiki ai nā mea i luna
∑ F x = ma x —— a x = 0
∑ F x = 0
He maikaʻi nā mana i luna a me nā mana ʻākau, he maikaʻi ʻole nā mana i lalo a me nā mana hema.
F – F k2 – w 2x – w 1 – T 2 + T 1 = 0
F – F k2 – w 2x – w 1 = 0
F = F k2 + w 2x + w 1
F = 53.7 N + 73.5 N + 98 N
F = 225.2 Newton
b) Ka nui o ka ikaika hoʻoluhi
E hoʻopili i ke kānāwai o ka neʻe ʻana o Newton ma ka poloka 1:
∑ F y = ma y —— a y = 0
∑ F y = 0
T 1 – w 1 = 0
T 1 = w 1 = 98 Newton
E hoʻopili i ke kānāwai o ka neʻe ʻana o Newton ma ka poloka 2:
F – F k2 – w 2x – T 2 = 0
T 2 = F – F k2 – w 2x
T 2 = 225.2 N – 53.7 N – 73.5 N
T 2 = 98 Newton
Ka nui o ka ikaika hoʻoluhi = T 1 = T 2 = T = 98 Newtons
ʻAʻole maopopo
4. Aia ka poloka 1 (m 1 = 16 kg) ma luna o kahi ʻili ākea a aia ka poloka 2 (m 2 = 12 kg) ma luna o kahi mokulele hilig laumania, i hoʻopili ʻia e ke kaula e hele ana ma luna o kahi pulley liʻiliʻi, ʻaʻohe friction. Aia ka poloka 3 (m 3 = 5 kg) ma luna o ka poloka 2. ʻO ke koina o ka friction kinetic ma waena o ka poloka 2 a me ka ʻili ākea he 0,4. ʻO ke koina o ka friction static ma waena o ka poloka 2 me ka poloka 3 he 0,3.
(a) Ke hoʻokuʻu ʻia ka ʻōnaehana mai ka hoʻomaha, e paheʻe pū ana ka poloka 3 a me ka poloka 2?
(b) Inā aia ka poloka 3, he aha ka wikiwiki o ka poloka 1 a me ka poloka 2?

Lōlā:
a) Ke hoʻokuʻu ʻia ka ʻōnaehana mai ka hoʻomaha, e paheʻe pū ana ka poloka 3 a me ka poloka 2?

w 1 = Ke kaumaha o ka poloka 1 = m 1 g = (16 kg)(9.8 m/s 2 ) = 156.8 Newtons
w 1x = w 1 sin 60 o = (156.8 N)(0.87) = 136.4 Newtons
w 1y = w 1 cos 60 o = (156.8 N)(0.5) = 78.4 Newtons
N 1 = Ka ikaika maʻamau i hoʻokau ʻia ma ka poloka 1 e ka mokulele inclined = w 1y = 78.4 Newtons
w 3 = Ke kaumaha o ka poloka 3 = m 3 g = (5 kg)(9.8 m/s 2 ) = 49 Newtons
N 23 = Ka ikaika maʻamau i hoʻokau ʻia ma ka poloka 3 e ka poloka 2 = w 3 = 49 Newtons
N 32 = Ka ikaika maʻamau i hoʻokau ʻia ma ka poloka 2 e ka poloka 3 = N 23 = w 3 = 49 Newtons
(ʻO N 23 a me N 32 nā hui hana-pane )
F s23 = Ka ikaika o ka haʻalulu paʻa i hoʻokau ʻia ma ka poloka 3 e ka poloka 2 = μ s N 23 = (0.3)(49 N) = 14.7 Newtons
F s32 = Ka ikaika o ka haʻalulu paʻa i hoʻokau ʻia ma ka poloka 2 e ka poloka 3 = F s 23 = 14.7 Newtons
(ʻO F s23 a me F s32 he mau hui hana-pane )
w 2 = Ke kaumaha o ka poloka 2 = m 2 g = (12 kg)(9.8 m/s 2 ) = 117.6 Newtons
N 2 = Ka ikaika maʻamau i hoʻokau ʻia ma luna o ka mea 2 e ka ʻili ākea = w 2 + N 32 = 117.6 Newtons + 49
Newton = 166.6 Newton
F k2 = Ka ikaika o ka friction kinetic ma ka poloka 2 = μ k N 2 = (0.4)(166.6 N) = 66.64 Newtons
E hoʻopili i ke kānāwai o ka neʻe ʻana o Newton ma ka poloka 3:
∑ F x = ma x
F s23 = m 3 a x
—–> Fs23 = μs N23 = μs w3 = μs m3 g
μ s m 3 g = m 3 a x
μ s g = a x
a x = (0.3)(9.8 m/s 2 ) = 2.94 m/s 2
ʻO ka wikiwiki kiʻekiʻe loa o ka poloka 3 i hiki ai i ka poloka 3 a me ka poloka 2 ke paheʻe pū he 2.94 m/ s².
I kēia manawa, ke helu nei mākou i ka nui o ka wikiwiki o ka ʻōnaehana ma hope o ka hoʻokuʻu ʻia ʻana mai ka hoʻomaha.
ʻO ke kuhikuhi o ka neʻe ʻana o ka poloka = ke kuhikuhi o ka wikiwiki o ka poloka = ke kuhikuhi o T 2 = ke kuhikuhi o w 1x.
∑ F x = ma x
w1x - T1 +T2 - Fk2 - Fs32 +Fs23 = (m1 +m2 +m3) ax
w 1x – F k2 = (m 1 + m 2 + m 3 ) a x
136.4 N – 66.64 N = (16 kg + 12 kg + 5 kg) a x
69.76 N = (33 kg) a x
a x = 2.11 m/s 2
He maikaʻi ʻo a x , ʻo ia hoʻi ke kuhikuhi o ka neʻe ʻana o ka poloka a i ʻole ke kuhikuhi o ka hoʻolalelale ʻana ua like ia me ke kuhikuhi o T 2 a i ʻole ke kuhikuhi o w 1x.
ʻO ka nui o ka hoʻolalelale ʻana he 2.11 m/s² , haʻahaʻa ma mua o 2.94 m/s² no laila hiki iā mākou ke hoʻoholo e paheʻe pū ana ka poloka 3 a me ka poloka 2 ma hope o ka hoʻokuʻu ʻia ʻana mai ka hoʻomaha.
b) Ka nui o ka wikiwiki o ka poloka 1 a me ka poloka 2
∑ F x = ma x
w 1x – F k2 = (m 1 + m 2 ) a x
—–> Fk2 = μk N2 = μk w2 = μk m2 g = (0.4)(12 kg)(9.8 m/s2) = 47.04 Newton
136.4 N – 47.04 N = (16 kg + 12 kg) a x
89.36 N = (28 kg) a x
a x = 89.36 N : 28 kg = 3.19 m/s 2
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- Ka nuipa a me ke kaumaha
- Ka ikaika maʻamau
- Ke kānāwai ʻelua o ka neʻe ʻana o Newton
- ʻO ka ikaika pili
- Ka neʻe ʻana ma luna o ka ʻili ākea me ka ʻole o ka ikaika friction
- ʻO ka neʻe ʻana o nā kino ʻelua me ka wikiwiki like ma luna o ka ʻili pālahalaha ʻinoʻino me ka ikaika friction
- Ka neʻe ʻana ma luna o ka mokulele i hoʻohuli ʻia me ka ʻole o ka ikaika friction
- Ka neʻe ʻana ma luna o ka mokulele i hoʻohaʻahaʻa ʻia me ka ikaika friction
- Neʻe ʻana i loko o kahi elevator
- Hoʻopili ʻia ka neʻe ʻana o nā kino e nā kaula a me nā pulleys
- ʻElua mau kino me ka nui like o ka wikiwiki
- Ke hoʻopuni ʻana i kahi piʻo pālahalaha - nā dinamika o ka neʻe pōʻai
- Ke hoʻopuni ʻana i kahi piʻo panakō - nā dinamika o ka neʻe pōʻai
- Neʻe like ʻana ma kahi pōʻai ʻākea
- Ka ikaika centripetal i ka neʻe pōʻai like
heluhelu hou