Ka neʻe ʻana o nā kino ʻelua me ka wikiwiki like ma luna o ka ʻili pālahalaha ʻinoʻino me ka ikaika friction - nā pilikia a me nā hoʻonā

1. ʻO ke kaumaha o ka pahu 1 he 2 kg, ʻo ke kaumaha o ka pahu 2 he 4 kg, ʻo ka wikiwiki o ke koʻikoʻi he 10 m/s 2 , ʻo ka nui o ka ikaika F he 40 Newtons. ʻO ke koʻikoʻi o ka friction kinetic ma waena o ka pahu 1 a me ka papahele he 0.2 a ʻo ke koʻikoʻi o ka friction kinetic ma waena o ka pahu 2 a me ka papahele he 0.3. E huli (a) Ka nui a me ke kuhikuhi o ka wikiwiki o ka pahu (b) Ka nui o ka ikaika i hoʻokau ʻia e ka pahu 1 ma ka pahu 2 (F 12 ) a me ka nui o ka ikaika i hoʻokau ʻia e ka pahu 2 ma ka pahu 1 (F 21 ).

Ka neʻe ʻana o nā kino ʻelua me nā wikiwiki like ma luna o ka ʻili pālahalaha ʻinoʻino me ka ikaika friction - nā pilikia a me nā hoʻonā 1

pāʻoihana

Ka neʻe ʻana o nā kino ʻelua me nā wikiwiki like ma luna o ka ʻili pālahalaha ʻinoʻino me ka ikaika friction - nā pilikia a me nā hoʻonā 2

ʻIke ʻia:

Ka nuipa o ka pahu 1 (m1 ) = 2 kg

Ka nuipa o ka pahu 2 (m2 ) = 4 kg

Ka wikiwiki o ke koʻikoʻi (g) = 10 m/ s² ,

ʻO ka ikaika F = 40 Newton,

ʻO ke koina o ka friction kinetic ma waena o ka pahu 1 a me ka papahele ( μ k1 ) = 0.2

ʻO ke koina o ka friction kinetic ma waena o ka pahu 2 a me ka papahele ( μ k2 ) = 0.3

ʻO ke kaumaha o ka pahu 1 (w 1 ) = m 1 g = (2)(10) = 20 Newtons

ʻO ke kaumaha o ka pahu 2 (w 2 ) = m 2 g = (4)(10) = 40 Newtons

ʻO ka ikaika maʻamau i hoʻokau ʻia ma ka pahu 1 (N 1 ) = w 1 = 20 Newtons

ʻO ka ikaika maʻamau i hoʻokau ʻia ma ka pahu 2 (N 2 ) = w 2 = 40 Newtons

ʻO ka ikaika o ka friction kinetic i hoʻokau ʻia ma ka pahu 1 (f k1 ) = ( μ k1 )(N 1 ) = (0.2)(20) = 4 Newtons

ʻO ka ikaika o ka friction kinetic i hoʻokau ʻia ma ka pahu 2 (f k2 ) = ( μ k1 )(N 2 ) = (0.3)(40) = 12 Newtons

Lōlā:

(a) Ka nui a me ke kuhikuhi o ka wikiwiki o ka pahu

ΣF = ma

F – f k1 – f k2 = (m 1 + m 2 ) a

40 – 4 – 12 = (2 + 4) a

24 = 6 a

a = 24 / 6

a = 4 m/s 2

Ke kuhikuhi o ka hoʻolalelale = ke kuhikuhi o ka ikaika ʻupena = i ka ʻākau.

(b) Ka nui o ka ikaika i hoʻokau ʻia e ka pahu 1 ma ka pahu 2 (F 12 ) a me ka nui o ka ikaika i hoʻokau ʻia e ka pahu 2 ma ka pahu 1 (F 21 ).

E helu i ka nui o F 12 :

ΣF = ma

F 12 – f k2 = (m 2 ) a

F 12 – 12 = (4)(4)

F 12 – 12 = 16

F 12 = 16 + 12

F12 = 28 Newtons

ʻO F 12 a me F 21 nā ikaika hana a me ka hopena e hana ana ma nā mea like ʻole. Loaʻa iā F 12 a me F 21 ka nui like a me ke kuhikuhi ʻē aʻe.

F 12 = 28 Newton = F 21 = 28 Newton.

ʻAʻole maopopo

2. ʻO ke kaumaha o ka pahu 1 he 2 kg, ʻo ke kaumaha o ka pahu 2 he 4 kg, ʻo ka wikiwiki o ke koʻikoʻi he 10 m/s 2 , ʻo ka ikaika F he 40 N. ʻO ke koʻikoʻi o ka friction kinetic ma waena o ka pahu 1 a me ka papahele he 0.2 a ʻo ke koʻikoʻi o ka friction kinetic ma waena o ka pahu 2 a me ka papahele he 0.3. E hoʻoholo (a) Ka nui a me ke kuhikuhi o ka wikiwiki (b) Ke tension i loko o ke kaula e hoʻopili ana i nā pahu. E hoʻowahāwahā i ke kaumaha o ke kaula.

Ka neʻe ʻana o nā kino ʻelua me nā wikiwiki like ma luna o ka ʻili pālahalaha ʻinoʻino me ka ikaika friction - nā pilikia a me nā hoʻonā 3

ʻIke ʻia:

Ka nuipa o ka pahu 1 (m1 ) = 2 kg

Ka nuipa o ka pahu 2 (m2 ) = 4 kg

Ka wikiwiki o ke koʻikoʻi (g) = 10 m/ s² ,

ʻO ka ikaika F = 40 Newton,

ʻO ke koina o ka friction kinetic ma waena o ka pahu 1 a me ka papahele he 0.2 ( μ k1 ) = 0.2

ʻO ke koina o ka friction kinetic ma waena o ka pahu 2 a me ka papahele he 0.2 ( μ k2 ) = 0.3

ʻO ke kaumaha o ka pahu 1 (w 1 ) = m 1 g = (2)(10) = 20 Newtons

ʻO ke kaumaha o ka pahu 2 (w 2 ) = m 2 g = (4)(10) = 40 Newtons

ʻO ka ikaika maʻamau i hoʻokau ʻia ma ka pahu 1 (N 1 ) = w 1 = 20 Newtons

ʻO ka ikaika maʻamau i hoʻokau ʻia ma ka pahu 2 (N 2 ) = w 2 = 40 Newtons

ʻO ka ikaika o ka friction kinetic i hoʻokau ʻia ma ka pahu 1 (f k1 ) = ( μ k1 )(N 1 ) = (0.2)(20) = 4 Newtons

ʻO ka ikaika o ka friction kinetic i hoʻokau ʻia ma ka pahu 2 (f k2 ) = ( μ k1 )(N 2 ) = (0.3)(40) = 12 Newtons

Lōlā:

(a) ka nui a me ke kuhikuhi o ka hoʻolalelale ʻana

ΣF = ma

F – f k1 – f k2 = (m 1 + m 2 ) a

40 – 4 – 12 = (2 + 4) a

24 = 6 a

a = 24 / 6

a = 4 m/s 2

ʻO ka nui o ka hoʻolalelale ʻana he 4 m/s² , ke kuhikuhi o ka hoʻolalelale = ke kuhikuhi o ka ikaika ʻupena = i ka ʻākau.

(b) Ke kaumaha ma ke kaula

ʻO nā ikaika e hana ana ma ka pahu 1 ma ke kuhikuhi pae, ʻo ia ka tension 1 (T 1 ) i ka ʻākau a me ka ikaika o ka friction kinetic 1 (f k1 ) i ka hema. E hoʻopili i ke kānāwai ʻelua o Newton:

ΣF = ma

T 1 – f k1 = m 1 a

T 1 – 4 = (2)(4)

T 1 – 4 = 8

T 1 = 8 + 4 = 12 Newton

ʻO nā ikaika e hana ana ma ka pahu 2 ma ke kuhikuhi pae, ʻo ia ka tension 2 (T 2 ) ma ka hema a me ka ikaika o ka friction kinetic 2 (f k 2 ) ma ka ʻākau. E hoʻopili i ke kānāwai ʻelua o Newton :

ΣF = ma

F – T 2 – f k2 = m 2 a

40 – T 2 – 12 = (4)(4)

28 – T 2 = 16

T 2 = 28 – 16 = 12 Newton

ʻO ke kaomi ma ke kaula e hoʻohui ana i nā pahu = T 1 = T 2 = T = 12 Newtons.

ʻAʻole maopopo

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  1. Ka nuipa a me ke kaumaha
  2. Ka ikaika maʻamau
  3. Ke kānāwai ʻelua o ka neʻe ʻana o Newton
  4. ʻO ka ikaika pili
  5. Neʻe ma luna o ka ʻili moe me ka ʻole o ka ikaika friction
  6. Neʻe ʻana o nā kino ʻelua me ka wikiwiki like ma luna o ka ʻili pālahalaha ʻinoʻino me ka ikaika friction
  7. Neʻe ma luna o ka mokulele i hoʻohaʻahaʻa ʻia me ka ʻole o ka ikaika friction
  8. Neʻe ma luna o ka mokulele i hoʻohaʻahaʻa ʻia me ka ikaika friction
  9. Neʻe ʻana i loko o kahi elevator
  10. Ka neʻe ʻana o nā kino i hoʻopili ʻia e nā kaula a me nā pulleys
  11. ʻElua mau kino me ka nui like o ka wikiwiki
  12. Ke hoʻopuni ʻana i kahi piʻo pālahalaha - nā dinamika o ka neʻe pōʻai
  13. Ke hoʻopuni ʻana i kahi piʻo panakō - nā dinamika o ka neʻe pōʻai
  14. Neʻe like ʻana ma kahi pōʻai ʻākea
  15. Ka ikaika centripetal i ka neʻe pōʻai like

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