Ke hoʻololi nei i nā unahi mahana (unahi Celsius unahi Fahrenheit unahi Kelvin)

9 Ke hoʻololi nei i nā unahi mahana (unahi Celsius unahi Fahrenheit unahi Kelvin)

1. 50 o C = ….. o F ?

pāʻoihana

Ma ke kaomi lewa maʻamau , ʻo ke kiko hau o ka wai he 0 ° C ma ka pālākiō Celsius a me 32 ° F ma ka pālākiō Fahrenheit. Ma ke kaomi lewa maʻamau, ʻo ke kiko paila o ka wai he 100 ° C ma ka pālākiō Celsius a me 212 ° F ma ka pālākiō Fahrenheit.

0 o C = 32 o F a me 1 00 o C = 212 o F. ʻO kahi loli o 5 C o = kahi loli o 9 F o.

No ka unahi Celsius, ua māhele ʻia ka mamao ma waena o 0 ° C a me 100 ° C i 100 mau wā like. No ka unahi Fahrenheit, ua māhele ʻia ka mamao ma waena o 0 ° C a me 100 ° C i 180 mau wā like.

Iā F = (180/100) Iā C + 32

Iā F = (9/5) Iā C + 32

Iā F = (9/5) 50 + 32

Iā F = (9) 10 + 32

Iā F = 90 + 32

Iā F = 122

50 o C = 122 o F

ʻAʻole maopopo

2. 86 o F = ….. o C ?

pāʻoihana

Iā C = (100/180)(Iā F – 32)

Iā C = (5/9)(Iā F – 32)

Iā C = (5/9)(86 – 32)

Iā C = (5/9)(54)

Iā C = (5)(6)

Iā C = 30

86 o F = 30 o C

3. 50 o C = ….. K ?

pāʻoihana

T = Iā C + 273

T = 50 + 273

T = 323

50 o C = 323 K

ʻAʻole maopopo

4. 212 o F = ….. K ?

pāʻoihana

Iā C = (100/180)(Iā F – 32)

Iā C = (5/9)(Iā F – 32)

Iā C = (5/9)(212 – 32)

Iā C = (5/9)(180)

Iā C = (5)(20)

Iā C = 100

212 o F = 100 o C + 273

212 o F = 373 K

 

5. x o C = x o F

x = ….. ?

pāʻoihana

1: Ke hoʻololi nei i ka unahi Celsius i ka unahi Fahrenheit

Ke hoʻololi nei i nā unahi mahana (unahi Celsius, unahi Fahrenheit, unahi Kelvin) - nā pilikia a me nā hoʻonā 1

2: Ke hoʻololi nei i ka unahi Fahrenheit i ka unahi Celsius

Ke hoʻololi nei i nā unahi mahana (unahi Celsius, unahi Fahrenheit, unahi Kelvin) - nā pilikia a me nā hoʻonā 2

ʻAʻole maopopo

6. 122°F = ….. Kelekia

pāʻoihana

Hiki ke kākau ʻia ka hoʻololi ʻana ma waena o nā unahi mahana ʻelua:

T C = 5/9 (T F – 32)

T C = Mahana ma Celsius, T F = mahana ma Fahrenheit

Ka mahana ma Celsius:

T C = 5/9 (122 – 32) = T C = 5/9 (90) = 5 (10)

T C = 50 o C

7. Hōʻike ke kiʻi ma lalo nei i ke ana ʻana o ka mahana o kahi wai me ka ana wela Fahrenheit! Inā ana ʻia ka mahana o ka wai me ka hoʻohana ʻana i ka ana wela Celsius, a laila he aha ka mahana o ka wai e.

ʻIke ʻia:Ke hoʻololi nei i nā unahi mahana (unahi Celsius, unahi Fahrenheit, unahi Kelvin) - nā pilikia a me nā hoʻonā 5

ʻO ka unahi Fahrenheit (T F ) = 95 o F

Makemake ʻia: Pālākiō Celsius

Lōlā:

Ma ke kaomi o 1 atm, ʻo ke kiko hau o ka wai he 0 °C ʻoiai ʻo ka unahi Fahrenheit he 32 ° F. I ka ʻaoʻao ʻē aʻe, ʻo ke kiko paila o ka wai no ka unahi Celsius he 100 ° C ʻoiai ʻo ka unahi Fahrenheit he 212 ° F.

Ma ke ana wela o Celsius, ma waena o 0 °C a me 100 °C he 100 °, a ma ke ana wela o Fahrenheit mai 32 °F a i 212 °F he 180 °.

T C = 100/180 (T F – 32)

T C = 5/9 (T F – 32)

T C = 5/9 ( 95 – 32)

T C = 5/9 ( 63 )

T C = 315/9

T C = 35 o C

8. Ma muli o ke kiʻi ma lalo nei, e hoʻoholo i ka mahana P ma ka ana wela Celsius.

pāʻoihana

TC = 100/180 (TF - 32) Ke hoʻololi nei i nā unahi mahana (unahi Celsius, unahi Fahrenheit, unahi Kelvin) - nā pilikia a me nā hoʻonā 6

T C = 5/9 (T F – 32)

T C = 5/9 (104 – 32)

T C = 5/9 (72)

T C = 360/9

T C = 40 o C

9. Inā like ka mahana o ke anakahi Celsius me ka mea i hōʻike ʻia ma ke kiʻi ma lalo, e hoʻoholo i ka mahana o ke anakahi Fahrenheit e like me ka mea i hōʻike ʻia ma ke kiʻi ma lalo.

Lōlā:

ToF = (180/100) ToC + 32Ke hoʻololi nei i nā unahi mahana (unahi Celsius, unahi Fahrenheit, unahi Kelvin) - nā pilikia a me nā hoʻonā 7

Iā F = (9/5) Iā C + 32

Iā F = (9/5) 60 + 32

Iā F = (9) 12 + 32

Iā F = 108 + 32

Iā F = 140

  1. Ke hoʻololi nei i nā unahi mahana
  2. Hoʻonui laina
  3. Hoʻonui ʻāina
  4. Hoʻonui leo
  5. wela
  6. ʻO ke kūlike mechanical o ka wela
  7. Ka wela kikoʻī a me ka mana wela
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  9. Ka mālama ʻana i ka ikehu no ka hoʻoili wela

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