Ke kānāwai o Charles (kaomi mau) - nā pilikia a me nā hoʻonā

1. In a closed container, the gas expands so that the final volume becomes 3 times the initial volume (V = initial volume, T = initial wela). What is the final temperature?

ʻIke ʻia:

Ka nui mua (V1) = V

Ka leo hope loa (V2) = 3V

Mahana mua (T1) = T

Makemake: Mahana hope loa (T2)

Lōlā:

ʻO ke kumu o Charles’s law :

Charles's law (constant pressure) - problems and solutions 1

The final temperature of gases becomes 3 times the initial temperature.

ike no hoi  Nā kaapuni uila - nā pilikia a me nā hoʻonā

2. ʻO waudeal gases initially have volume V and temperature T. If the gas undergoes the isobaric process so that the temperature becomes 2 times the initial temperature then the final volume of gases is…

ʻIke ʻia:

Ka nui mua (V1) = V

Mahana mua (T1) = T

Mahana hope loa (T2) = 2T

Makemake: final volume (V2)

Lōlā:

Charles's law (constant pressure) - problems and solutions 2

The final volume of gases becomes 2 times the initial volume.

ike no hoi  Nā Capacitors ma nā moʻo a me nā ʻano like ʻole - nā pilikia a me nā hoʻonā

3. In a closed container, ideal gases initially have a volume of 2 liters and temperature of 27oC. If the final volume of gases becomes 3 liters then the final temperature is…

ʻIke ʻia:

Ka nui mua (V1) = 2 lita = 2 dm3 = 2x10-3 m3

Ka leo hope loa (V2) = 3 lita = 3 dm3 = 3x10-3 m3

Mahana mua (T1) = 27oC + 273 = 300 K

Makemake ʻia: Mahana hope loa (T2)

Lōlā:

Charles's law (constant pressure) - problems and solutions 3

The final temperature is 177oC or 177 + 273 = 450 Kelvin.

Waiho i ka manaʻo