Tsarin Dokar Newton

Tambayoyi da dabarun misalai na dokokin Newton

Dokar Farko ta Newton

1. Mutum yana cikin wani lif wanda ke tafiya da sauri akai-akai. Mutumin yana da nauyin N800. Ba zato ba tsammani igiyar ƙarfe da ke jan lif ɗin ta karye, ta sa lif ɗin ya faɗi. Ƙarfin al'ada daga benen lif zuwa mutumin da ke gaban da kuma bayan ya karye kebul ɗin ƙarfe shine….

1. 800 N da 0
2. 800 N da 800 N
3. 1600 N da 0
4. 1600 N da 800 N

Tattaunawa
An san cewa:
Nauyi (w) = 800 Newtons
Tambaya: Ƙarfin da aka saba da shi (N) yana aiki a kan mutum nan da nan kafin da kuma bayan karyewar igiyar ƙarfe
Amsa:
'Yan mintuna kafin igiyar ƙarfe ta karye
Idan mutum ya tsaya a ƙasan lif, ƙarfin nauyi yana aiki akan mutum kuma alkiblar ƙarfin tana ƙasa (duba hoton da ke ƙasa). Mutumin yana tsaye a cikin lif don haka dole ne a sami ƙarfi na yau da kullun wanda ke daidaita nauyin mutumin, inda wannan ƙarfin yana da alkibla sama kuma yana daidai da girman nauyi. Ƙarfin da ƙasa ke yi wa mutum kuma wannan ƙarfin yana aiki akan mutum.
Domin mutumin yana tsaye a cikin lif kuma lif ɗin yana motsi a cikin sauri mai ɗorewa (babu hanzari), ƙarfin da ke aiki a kan mutumin ba shi da sifili.
∑F = 0
N – w = 0
N = w
N = 800 Newton

Bayan igiyar ƙarfe ta karye
Bayan da kebul na ƙarfe ya karye, lif da mutumin suka faɗi tare cikin 'yanci, inda girma da alkiblar saurin faɗuwar free lif da mutumin suka yi daidai da saurin faɗuwar free lif saboda nauyi a Duniya. lif da mutumin suka faɗi tare cikin 'yanci don haka babu wani ƙarfi na yau da kullun da benen lif ke yi wa mutumin. Mutumin yana faɗuwa kuma ƙafafun mutumin ba za su iya matsawa a ƙasan lif ba saboda lif ɗin ma yana faɗuwa.
Amsar da ta dace ita ce A.

2. Ƙarfi uku, kowannensu yana da girman F₁ = 22 N, F₂ = 18 N da F₃ = 40 N ana amfani da shi a kan tubalin katako. An nuna ƙarfin da ke aiki a kan tubalin, waɗanda ke bin dokar farko ta Newton, a cikin hoton...

Tattaunawa

Dokar Farko ta Newton: Ƙarfin sakamako (ΣF) = 0.

A. F₁ +F₂ - F₃ = 22 N + 18 N – 40 N = 40 N – 40 N = 0

B. F₂ +F₃ - F₁ = 18 N + 40 N – 22 N = 58 N – 22 N = 36 N (a gefen dama)

C. F₂ +F₃ - F₁ = 18 N + 40 N – 22 N = 58 N – 22 N = 36 N (a gefen dama)

D. F₁ +F₃ - F₂ = 22 N + 40 N – 18 N = 62 N – 18 N = 44 N (a hagu)

Amsar da ta dace ita ce A.

Dokar Newton ta Biyu

3.
Kalli hoton!
An ja wani tubali mai nauyin kilogiram 40 da ƙarfin N 200, wanda ke haifar da hanzarin mita 3/s² Don haka girman ƙarfin gogayya da ke faruwa akan abu/toshe shine...

1. 15 N
2. 40 N
3. 43 N
4. 80 N

Tattaunawa
An san cewa:
Mass (m) = 40 kg
Ƙarfi (F) = 200 N
Hanzari (a) = 3 m/s²
Tambaya: Girman ƙarfin gogayya (F)_g)
Amsa:
Tsarin doka ta biyu ta Newton:
∑F = ma
Bayani: ∑F = ƙarfin sakamako, m = taro, a = hanzari

Alkiblar ƙarfin F tana hannun dama yayin da alkiblar gogayya take hannun hagu (alkiblar gogayya tana hannun akasin alkiblar motsin abin). Alkiblar da ke hannun dama tana hannun dama kuma alkiblar da ke hannun hagu tana hannun dama.
∑F = ma
F – F_g = ma
200 - F_g = (40)(3)
200 - F_g = 120
F_g = 200-120
F_g = 80 Newton
Amsar da ta dace ita ce D.

4. An sanya toshe A mai nauyin gram 100 a saman toshe B tare da nauyin gram 300, sannan toshe B za a tura shi da ƙarfin 5 N a tsaye sama. Idan tubalan ba sa motsawa juna, to girman ƙarfin da aka saba da toshe B akan toshe A shine….

1. 1 N
2. 1,25 N
3. 2 N
4. 3 N

Tattaunawa
An san cewa:
Ƙarfin turawa (F) = 5 Newton
Nauyin toshe A (m)_A) = gram 100 = 0,1 kg
Nauyin tubalan B (m)_B) = gram 300 = 0,3 kg
Saurin gudu saboda nauyi (g) = 10 m/s²
Nauyin toshe A (w)_A) = (0,1 kg)(10 m/s²) = 1 kg m/s² = 1 Newton
Nauyin toshe B (w)_B) = (0,3 kg)(10 m/s²) = 3 kg m/s² = 3 Newton

Tambaya: Ƙarfin al'ada ta toshe B akan toshe A
Amsa:
Akwai ƙarfi da yawa da ke aiki a kan tubalan biyu, kamar yadda aka nuna a cikin hoton da ke ƙasa.
F = ƙarfin turawa (yana aiki akan toshe B)
w_A = ƙarfin nauyi na toshe A (yana aiki akan toshe A)
w_B = nauyin toshe B (yana aiki akan toshe B)
N_A = ƙarfin yau da kullun ta hanyar toshe B akan toshe A (yana aiki akan toshe A)
N_A' = ƙarfin yau da kullun ta hanyar toshe A akan toshe B (yana aiki akan toshe B)

Yi la'akari da duka tubalan a matsayin tsarin guda ɗaya:
Aiwatar da dokar Newton ta biyu ga duka tubalan:
∑F = ma
F – w_A - w_B +N_A - N_A' = (m_A +m_B) da kuma
N_A da kuma N_A' ƙarfin aiki ne wanda ke da girma iri ɗaya amma akasin alkibla don haka an cire shi daga lissafin.
F – w_A - w_B = (m_A +m_B) da kuma
5 – 1 – 3 = (0,1 + 0,3) a
5 – 4 = (0,4) a
1 = (0,4) a
a = 1/0,4
a = 2,5 m/s²
Kasancewar ƙarfin (F) na Newtons guda 5 da ke aiki a tsaye sama a kan tubalan biyu yana sa tubalan biyu su motsa tsaye sama tare da saurin gudu na 2,5 m/s.².

Yi la'akari da toshe A:
Yi amfani da dokar Newton ta biyu don toshe A:
∑F = ma
N_A - w_A = m_A a
N_A – 1 = (0,1)(2,5)
N_A - 1 = 0,25
N_A = 1 + 0,25
N_A = 1,25 Newton
Ƙarfin da aka saba amfani da shi ta hanyar toshe B akan toshe A shine 1,25 Newton.
Amsar da ta dace ita ce B.

Dokar Newton ta Uku

5. Kula da wannan bayanin!

(1) An tura fasinjoji gaba lokacin da bas ɗin, wanda ke tafiya a hankali, ya yi birki da ƙarfi ba zato ba tsammani.

(2) Tarin littattafai da ke saman kwali ba zai faɗi ba idan aka ja kwali da sauri.

(3) Lokacin da ake buga skateboard, idan ƙafar da ba ta da 'yanci ta tura ƙasa baya, skateboard ɗin zai zame gaba.

(4) An tura kwale-kwalen jirgin ruwa baya, jirgin ya ci gaba.

Bayanin da ke sama wanda ya yi daidai da dokar Newton ta uku shine...

A. (1) da (2)

B. (1) da (3)

C. (2) da (3)

D. (3) da (4)

Tattaunawa

(1) Dokar farko ta Newton

(2) Dokar farko ta Newton

(3) Dokar Newton ta uku

(4) Dokar Newton ta uku

Amsar da ta dace ita ce D.

Tushen tambaya:

Tambayoyin Jarrabawar Ƙasa ta Kimiyya ta Makarantar Sakandare/Makarantar Sakandare ta Musulunci

Tambayoyin OSN na Makarantar Sakandare ta Junior Physics