1. Based on the following equation of the halayen fusion, determine the energy produced in the fusion reaction!
Magani
Mass of reactant and product :
Mass of mai amsawa (mmai amsawa) = 1.0078 amu + 1.0078 amu = 2.0156 amu
Mass of samfur (msamfur) = 2.01410 amu + 0.00055 amu = 2.01465 amu
The loss of mass in the reaction :
Δm = mmai amsawa - msamfur
Δm = 2.01560 m - 2.01465 m
Δm = 0.00095 m
The loss of mass in the reaction is 0.00095 sma.
1 amu = 931 MeV. 0.00095 amu = 0.00095 x 931 MeV = 0.88445 MeV.
amu = atomic mass unit
MeV = megaelectron-volt (unit of energy)
2. Based on the following equation of the fusion reaction, determine the energy produced in the fusion reaction!
Magani:
Mass of reactant and product :
Mass of mai amsawa (mmai amsawa) = 2.014 m + 3.016 m = 5.03 m
Mass of samfur (msamfur) = 4.0026 m + 1.0084 m = 5.011 m
The loss of mass in the reaction :
Δm = mmai amsawa - msamfur
Δm = 5.03 amu – 5.011 amu
Δm = 0.019 amu
The loss of mass in the reaction is 0.019 m.
1 amu = 931 MeV. 0.019 amu = 0.019 x 931 MeV = 17.689 MeV = 17.69 MeV.
3. Based on the following equation of the fusion reaction, determine the energy produced in the fusion reaction!
Magani:
Mass of reactant and product :
Mass of mai amsawa (mmai amsawa) = 13.0033 m + 2.0141 m = 15.0174 m
Mass of samfur (msamfur) = 14.0030 m + 1.0078 m = 15.0108 m
The loss of mass in the reaction :
Δm = mmai amsawa - msamfur
Δm = 15.0174 m - 15.0108 m
Δm = 0.0066 m
The loss of mass in the reaction is 0.0066 amu.
1 amu = 931 MeV. 0.0066 amu = 0.0066 x 931 MeV = 6.1446 MeV.
4. Based on the following equation of the fusion reaction, determine the energy produced in the fusion reaction.
Magani:
Mass of reactant and product :
Mass of mai amsawa (mmai amsawa) = 4 (1.0078 m) = 4.0312 m
Mass of samfur (msamfur) = 4.0026 m + 0.0005 m = 4.0031 m
The loss of mass in the reaction :
Δm = mmai amsawa - msamfur
Δm = 4.0312 m - 4.0031 m
Δm = 0.0281 m
The loss of mass in the reaction is 0.0281 amu.
1 amu = 931 MeV. 0.0281 amu = 0.0281 x 931 MeV = 26.1611 MeV.
