Tambayoyi 3 game da lissafin matsin lamba na igiya
1. Hoton da ke ƙasa yana nuna tubalan guda uku, wato A, B da C waɗanda suke kan wani santsi a kwance. Idan nauyin A = 1 kg, nauyin B = 2 kg da nauyin C = 2 kg da F = 10 N, to, a ƙayyade rabon tashin hankali a cikin igiyar tsakanin A da B da tashin hankali a cikin igiyar tsakanin B da C.
Wanda aka sani:
Nauyin A (mA ) = 1 kg
Nauyin B (m B ) = 2 kg
Nauyin C (mC ) = 2 kg
Ƙarfin tauri (F) = 10 N
Ana so: T AB : T BC
Magani:
Lissafa hanzarin tsarin ta amfani da dabarar Dokar Biyu ta Newton:
ΣF = ma
F = (m A + m B + m C ) a
10 = (1 + 2 + 2) a
10 = 5 a
a = 10/5
a = 2 m/s 2
Yi amfani da dabarar matsin lamba ta igiya don ƙididdige T AB
ΣF = ma
T AB = m A a = 1 (2) = 2 Newtons
Yi amfani da dabarar matsin lamba ta igiya don ƙididdige T BC
ΣF = ma
T BC = (m A + m B ) a = (1 + 2) (2) = (3)(2) = 6 Newtons
2. An haɗa abu A mai nauyin kilogiram 6 da abu B mai nauyin kilogiram 3 ta hanyar igiya kamar yadda aka nuna. Idan ma'aunin gogayya shine 0.3 da g = 10 m/s 2 , a tantance hanzarin abu da kuma tashin hankali a cikin igiyoyin kowane toshe.
An sani:
Nauyin abu A (mA ) = 6 kg
Nauyin abu B (m B ) = 3 kg
Ma'aunin gogayya na toshe A (µ k ) = 0.3
Saurin gudu saboda nauyi (g) = 10 m/s 2
Nauyin toshe A (w A ) = m A g = (6)(10) = 60 N
Ƙarfin da aka saba amfani da shi a kan toshe A (N A ) = w A = 60 N
Nauyin toshe B (w B ) = m B g = (3)(10) = 30 N
Ana so: Saurin tsarin (a) da kuma tashin hankali a cikin igiya (T)
Magani:
Lissafa ƙarfin gogayya na motsi wato ƙarfin gogayya lokacin da toshe A ke motsawa:
F k = µ k N A = (0,3) (60) = 18 Newtons
Lissafa hanzarin tsarin (a):
ΣF = ma
wB – F k = (m A + m B ) a
30 – 18 = (6 + 3) a
12 = 9 a
a = 12 / 9 = 1,3 m/s 2
Lissafa tashin hankali a cikin igiyar da ke kan toshe A (T A ):
ΣF = ma
T A – F k = (m A ) a
T A – 18 = (6)(1,3)
T A – 18 = 7,8
TA = 7,8 + 18 = 25,8 Newtons
Lissafa matsin lamba a cikin igiyar da ke kan katakon B (T B ):
ΣF = ma
w B – T B = m B (a)
30 – T B = 3 (1,3)
30 – T B = 3,9
T B = 30 – 3,9
T B = 26,1 Newtons
3. Abubuwa biyu A da B masu nauyin kilogiram 5 da kilogiram 3 an haɗa su da wani kurfi mara gogayya. Ana amfani da ƙarfin P a kan kurfi a sama. Idan duka tubalan biyu sun fara tsayawa a ƙasa, menene saurin toshe A, idan girman P shine 60 N?
Kayyade kuma ƙarfin igiyar a kan tubalan A da B.
An sani:
Saurin gudu saboda nauyi (g) = 10 m/s 2
Nauyin A (mA ) = 5 kg
Nauyin toshe A (w A ) = m A g = (5)(10) = 50 Newtons
Nauyin B (m B ) = 3 kg
Nauyin toshe B (w B ) = m B g = (3)(10) = Newtons 30
Ƙarfin P = 60 N
Ana Bukata: Haɓaka tsarin katako A da B (a) da kuma matsin lamba a cikin igiyar da ke kan katako A (T A ) da katako B (T B )
Magani:
Lissafa hanzarin tsarin ta amfani da dabarar Dokar Biyu ta Newton.
ΣF = ma
w A – w B = (m A + m B ) a
50 – 30 = (5 + 3) a
20 = 8 a
a = 20/8
a = 2,5 m/s 2
Yi amfani da dabarar ƙarfin tashin hankali don ƙididdige tashin hankali a cikin igiya
Jinkirin da ke cikin igiyar a kan toshe A:
ΣF = ma
w A – T A = m A a
50 – T A = 5 (2,5)
50 – TA = 12,5
T A = 50 – 12,5 = 37,5 Newtons
Jinkirin da ke cikin igiyar da ke kan toshe B:
ΣF = ma
T B – w B = m B a
T B – 30 = 3 (2,5)
T B – 30 = 7,5
T B = 7,5 + 30 = 37,5 Newtons
