1. Ana juya ƙwallon, wanda aka haɗa a ƙarshen igiya mai kwance, a cikin da'irar radius 20 cm. Ƙwallon yana kusa da 360 o kowace daƙiƙa. Ka ƙayyade girman hanzarin centripetal!
An sani:
Gudun kusurwa (ω ) = 360 o /daƙi = juyin juya hali 1/daƙi = 6.28 radians/daƙi
Radius (r) = 20 cm = 0.2 m
Ana so: Hanzarin tsakiya (a r )
Magani:
a r = v 2 / r —> v = r ω
a r = (r ω) 2 / r = r 2 ω 2 / r
a r = r ω 2
a s = hanzarin centripetal, v = saurin layi, r = radius, ω = saurin kusurwa
Girman hanzarin centripetal :
a r = r ω 2 a r = (0,2 m) ( 6.28 rad/s)
a r = 1.256 m/s 2
[irp]
2. Tayar da ke da santimita 30 a radius tana juyawa a gudun 180 rpm. Kayyade hanzarin centripetal na wani wuri a gefen tayar!
An sani:
Radius (r) = 30 cm = 0.3 m
Gudun kusurwa ( ω ) = juyin juya hali 180 / daƙiƙa 60 = juyin juya hali 3 / daƙiƙa = (3)(radian 6.28) / daƙiƙa = radian 18.84/daƙiƙa
Ana so: hanzarin tsakiya ( a r ) na r = 0.3 m
Magani:
Girman hanzarin centripetal:
a r = r ω 2
a r = (0.3 m)(18.84 rad/s)
a r = 5.65 m/s 2
3. Motar tsere tana tafiya a kan hanyar zagaye ta radius mita 50. Idan gudun motar ya kai kilomita 72/h, a tantance girman saurin centripetal!
An sani:
Radius (r) = mita 50
Gudun (v) = 72 km/h = (72)(mita 1000) / daƙiƙa 3600 = mita 20/daƙiƙa
Ana so : girman hanzarin centripetal (a r )
Magani:
a r = v 2 / r = 20 2 / 50 = 400 / 50 = 8 m/s 2
[irp]
4. Mota tana da matsakaicin saurin centripetal na 10 m/s 2 , don haka motar za ta iya juyawa ba tare da ta zame daga kan hanya mai lanƙwasa ba. Idan motar tana tafiya a daidai gudun 108 km/h, menene radius na lanƙwasa mara bango?
An sani:
Hanzarin tsakiya (a r ) = 10 m/s 2
Gudun mota (v) = 108 km/ h = (108)(1000) / 3600 = mita 30 a /sec c akan d
Ana so: radius (r)
Magani:
r = v 2 / a r
r = 30 2/10 = 900 / 10 = mita 90 a s
[irp]
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