1. Jiki mai nauyin kilogiram 1 ya faɗi cikin 'yanci daga hutawa, daga tsayin mita 80. Saurin nauyi saboda nauyi shine 10 m/s 2. Menene kuzarin motsi lokacin da jiki ya faɗi ƙasa.
An sani:
Nauyi (m) = 1 kg
Tsawo (h) = mita 80
Saurin gudu saboda nauyi (g) = 10 m/s 2
Ana so: kuzarin motsi lokacin da jiki ya buga ƙasa
Magani:
Makamashin injina na farko (ME o ) = makamashin ƙarfin nauyi (PE)
M E o = P E = mgh = (1)(10)(80) = Joules 800
Makamashin injiniya na ƙarshe (M E t ) = makamashin motsi (K E )
Ka'idar kiyaye makamashin inji :
M E o = M E t
P E = K E
800 = K E
Ƙarfin motsi na ƙarshe shine Joules 800.
[irp]
2. Jiki mai nauyin kilogiram 4 ya faɗi daga hutawa, daga tsayin mita 10. Saurin nauyi saboda nauyi shine 10 ms –2 . Menene kuzarin motsi da saurin da ke mita 5 sama da ƙasa.
An sani:
Sauyin tsayi (h) = 10 – 5 = mita 5 a sakan daya
Nauyi (m) = 4 kg
Saurin gudu saboda nauyi (g) = 10 m/s 2
Ana so: Ƙarfin motsi a mita 5 a sama da ƙasa da kuma saurin gudu a mita 5 a sama da ƙasa
Magani:
(a) Makamashin motsi a mita 5 sama da ƙasa
Makamashin injina na farko (M E o ) = makamashin ƙarfin nauyi (P E )
M E o = P E = mgh = (4)(10)(5) = Joules 200
Makamashin injiniya na ƙarshe (EM t ) = makamashin motsi (EK)
M E t = K E
Ka'idar kiyaye makamashin injiniya ta bayyana cewa makamashin injiniya na farko = makamashin injiniya na ƙarshe.
M E o = M E t
200 = K E
Makamashin motsi a mita 5 sama da ƙasa shine Joules 200.
(b) gudu a mita 5 sama da ƙasa
Makamashin injina na farko (M E o ) = makamashin injina na ƙarshe (M E t )
P E = K E
200 = ½ mv 2
2(200) / 4 = v 2
100 = v 2
v = √100
v = 10 m/s
Gudun jiki a mita 5 sama da ƙasa shine 10 m/s.
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3. Mangoro yana faɗuwa daga hutawa, daga tsayin mita 2. Saurin nauyi saboda nauyi shine 10 ms –2 . Kayyade saurin mangoro lokacin da ya faɗi ƙasa.
An sani:
Tsawo (h) = mita 2 a sakan daya
Saurin gudu saboda nauyi (g) = 10 m/s 2
Ana so: saurin mangwaro idan ya faɗi ƙasa.
Magani:
Makamashin injina na farko (M E o ) = makamashin ƙarfin nauyi (P E )
M E = P E = mgh = m (10)(2) = 20 m
Makamashin injiniya na ƙarshe (M E t ) = makamashin motsi (K E )
M E t = K E = ½ mv 2
Ka'idar kiyaye makamashin injiniya ta bayyana cewa makamashin injiniya na farko = makamashin injiniya na ƙarshe.
M E o = M E t
20 m = ½ mv 2
20 = ½ v 2
2(20) = v 2
40 = v 2
v = √40 = √(4)(10) = 2√10 m/ s
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