Tambayoyi 3 game da lissafin saurin kusurwa
1. Abu da ke motsi a cikin hanyar da'ira yana da radius na 0.5 m. Ƙwayar za ta iya rufe kusurwar 60π rad cikin daƙiƙa 15. Kayyade saurin kusurwar abin.
Wanda aka sani:
Radius (r) = mita 0.5
Kusurwar (θ) = 60π rad
Tazarar lokaci (t) = daƙiƙa 15
Ana so: Gudun kusurwa (ω)
Magani:
θ = ω t
60π = ω (15)
ω = 60π / 15 = 4π rad/s
2. Tayar keke mai radius na santimita 30 tana juyawa a daidai gwargwado. Bawul ɗin taya zai iya juyawa a kusurwar 120π rad na tsawon daƙiƙa 10. Kayyade saurin kusurwa.
Wanda aka sani:
Radius (r) = 30 cm
Kusurwar (θ) = 120π rad
Tazarar lokaci (t) = s 10
Ana so: Gudun kusurwa (ω)
Magani:
θ = ω t
120π = ω (10)
ω = 120π / 10 = 12π rad/s
3. An naɗe igiyar a kusa da wata ƙafa mai radius R = 25 cm kamar yadda aka nuna. Idan wani wuri a kan igiyar (maki A) yana da gudun 5 m/s to saurin juyawar tayoyin shine…
Wanda aka sani:
Radius (r) = 25 cm = mita 0.25
Gudun (v) = 5 m/s
Ana so: Gudun kusurwa (ω)
Magani:
Tsarin da ke tsakanin saurin kusurwa, saurin layi da radius:
v = r ω
5 = (0,25) ω
ω = 5 / 0,25 = 20 rad/s
