Saurin kusurwa da saurin layi - matsaloli da mafita

1. Ƙwallo a ƙarshen igiya tana juyawa daidai gwargwado a cikin da'irar kwance ta radius mita 2 a saurin kusurwa mai ɗorewa 10 rad/s. Ka ƙayyade girman saurin layi na wani wuri da ke:

(a) Mita 0.5 daga tsakiya

(b) Mita 1 daga tsakiya

(c) Mita 2 daga tsakiya

An sani:

Radius (r) = mita 0.5 a s, mita 1, mita 3

Gudun kusurwa = 10 radians s / se cond

Ana so: Gudun layi

Magani:

v = r ω

v = saurin layi , r = radius , ω = saurin kusurwa

(a) Gudun layi (v) na wani wuri da ke r = mita 0.5

v = r ω = (mita 0.5 s )(10 rad/s) = mita 5 s / se yanayin

(b) Gudun layi (v) na wani wuri da ke r = mita 1

v = r ω = (mita 1)(10 rad/s) = mita 10 s / se yanayin

(c) Saurin layi (v) na wani wuri da ke r = mita 2 a cikin s

v = r ω = (mita 2 s )(10 rad/s) = mita 20 s / se yanayin

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2. Ruwan wukake a cikin injin blender suna juyawa a gudun 5000 rpm. Kayyade girman saurin layi:

(a) wani wuri da ke da nisan santimita 5 daga tsakiya

(b) wani wuri da ke da nisan santimita 10 daga tsakiya

An sani:

Radius (r) = 5 cm da 10 cm

Gudun kusurwa (ω) = 5000 juyin juya hali / s 60karshen = 83.3 juyin juya hali / seyanayi = (83.3)(radian 6.28) / seyanayi = 523.3 radianss / seyanayi

Ana so: Girman saurin layi

Magani:

(a) Girman saurin layi na wani wuri da ke da nisan mita 0.05 daga tsakiya

v = r ω = (0.05 m)( 523.3 rad/s) = 26 m/s

(b) Girman saurin layi na wani wuri da ke da nisan mita 0,1 daga tsakiya

v = r ω = (0.1 m)( 523.3 rad/s) = 52 m/s

3. Wani wuri a gefen tayar mai tsawon santimita 30 a radius, a kusa da da'ira a gudun mita 10/dakika.

Menene girman saurin kusurwa?

An sani:

Radius ( r) = 30 cm = mita 0.3 a s

Saurin layi (v) = mita 10 a minti ɗaya

Ana so: saurin kusurwa

Magani:

ω = v / r = 10 / 0.3 = 33 radians s / se cond

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4. Motar da ke da tayoyi masu diamita santimita 50 tana tafiya mita 10 cikin daƙiƙa 1. Menene saurin kusurwa?

An sani:

Radius (r) = mita 0.25

Gudun layi na wani wuri a gefen tayoyin (v) = mita 10 s / se cond

Ana so: Gudun kusurwa

Magani:

ω = v / r = 10 / 0.25 = 40 radians s / se cond

5. Gudun kusurwa na tayoyin 20 cm a cikin radians shine 120 rpm. Menene nisan idan motar ta yi tafiya cikin daƙiƙa 10.

An sani:

Radius (r) = 20 cm = mita 0.2 a s

Gudun kusurwa = 120 sakewa / 60 secyanayi = 2 sakewa / seyanayi = (2)(6.28) radians / seyanayi = 12.56 radianss / seyanayi

Ana so: nesa

Magani:

Gudun gefen tayoyin:

v = r ω = (mita 0.2 s )(12.56 radians s / se cond ) = mita 2.5 s / se cond

2.5 mitas / second yana nufin wani wuri a gefen tafiyar tayoyin 2.5 mitas kowane daƙiƙa 1. bayan 10 gayanayi, ma'anar tana tafiya 25 mitas.

Don haka nisan shine mita 25 a sakan daya.

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