Tambayoyin misalai na karfin juyi

10 Tambayoyin misalai na karfin juyi

1. Ana iya yin watsi da nauyin sandar AB. Idan FR _shine sakamakon ƙarfin F1 _, F2 _, da F3 guda uku _, to girman ƙarfin F2 _da nisan x sune...

A. 50 N ƙasa da 0,5 m zuwa hagu na A

B. 50 N sama da 0,5 m zuwa dama na A

C. 50 N sama da 0,75 m a hagu na A

D. 50 N ƙasa da 0,75 m zuwa dama na A

E. 50 N sama da 0,2 m zuwa dama na A

Tattaunawa

An san cewa:

Ƙarfin da aka samu (FR ₎ = 40 N

F ₁ = N 10

F ₃ = N 20

Tambaya: Girman ƙarfin F ₂ da nisan x

Amsa:

Lissafa girman ƙarfin _F2 :

Ƙarfin da aka tura sama yana da kyau, ƙarfin da aka tura ƙasa yana da kyau.

ΣF = 0 (sanda tana tsaye kuma ba ta motsawa)

– F _R + F ₁ + F ₂ – F ₃ = 0

– 40 + 10 + F ₂ – 20 = 0

– 30 + F ₂ – 20 = 0

– 50 + F ₂ = 0

F₂ = Newtons 50, yana da kyau saboda alkiblar ƙarfin tana sama.

Lissafa nisa x:

Zaɓi maki A a matsayin ma'aunin juyawa.

τ ₁ = F ₁ l ₁ = (10 N) (1 m) = 10 nm

Juyin juyawa na 1 yana da kyau saboda yana sa juyawar sandar AB ta kasance akasin agogon hannu.

τ ₂ = F ₂ x = (50) (x) = 50x Nm

Juyin juyawa na 1 yana da kyau saboda yana sa juyawar sandar AB ta kasance akasin agogon hannu.

τ ₃ = F ₃ x = (20 N) (1,75 m) = -35 nm

Juyin juyawa na 1 ba shi da kyau saboda yana haifar da juyawar sandar AB a daidai alkiblar juyawar agogo.

Juyin Juya Halin:

Στ = 0 (sanda tana nan a tsaye kuma ba ta juyawa)

10 + 50x – 35 = 0

50x - 25 = 0

50x = 25

x = 25/50

x = mita 0,5

Amsar da ta dace ita ce B.

2. Ƙarfin F1 _, F2 _, F3 _, da F4 _{suna aiki} akan sandar ABCD kamar yadda aka nuna a hoton! Idan aka yi watsi da nauyin sandar, to ƙimar lokacin ƙarfi game da batu A shine…..

A. 15 Nm

B. 18 Nm

C. 35 Nm

D. 53 Nm

E. 68 Nm

Tattaunawa

Axis na juyawa shine maki A.

An san cewa:

Ƙarfi F ₁ = 10 N, hannun ƙarfi l ₁ = 0

Ƙarfin F ₂ = 4 N, hannun ƙarfi l ₂ = mita 2

Ƙarfin F ₃ = 5 N, hannun ƙarfi l ₃ = mita 3

Ƙarfin F ₄ = 10 N, hannun ƙarfi l ₄ = mita 6

Tambaya: Lokacin ƙarfi game da batu na A

Amsa:

Lokacin ƙarfi 1 (τ ₁ ) = F ₁ l ₁ = (10) (0) =

Lokacin ƙarfi 2 (τ ₂ ) = F ₂ l ₂ = (4) (2) = -8 Nm

Lokacin ƙarfi 3 (τ ₃ ) = F ₃ l ₃ = (5) (3) = 15 Nm

Lokacin ƙarfi 4 (τ ₄ ) = F ₄ l ₄ = (10) (6) = -60 Nm

Lokacin ƙarfin yana da kyau idan ƙarfin ya sa sandar ta juya akasin agogo.

Lokacin ƙarfin yana da kyau idan ƙarfin ya sa sandar ta juya a hannun agogo.

Lokacin ƙarfi da ya biyo baya:

τ = 0 - 8 Nm + 15 Nm - 60 nm

τ = -68 Nm + 15 Nm

τ = -53 Nm

Alamar da ba ta da kyau tana nufin sandar tana juyawa a hannun agogo.

Amsar da ta dace ita ce D.

3. Sanda da aka yi watsi da nauyinta tana shafar ƙarfi uku F _A = ​​F _C = 10 N da F _B = 20 N kamar yadda aka nuna a cikin hoton. Idan nisan AB = BC = 20 cm, to girman lokacin ƙarfin da ke kusa da wurin C shine…

A. 0 Nm

B. 1 Nm

C. 4 Nm

D. 6 Nm

E. 8 Nm

Tattaunawa

An sani cewa :

Axis na juyawa yana nan a wurin C.

Nisa tsakanin F _A da kuma axis na juyawa (r _AC ) = 40 cm = mita 0,4

Nisa tsakanin F _B da kuma axis na juyawa (r _BC ) = 20 cm = mita 0,2

Nisa tsakanin F _C da axis na juyawa (r _CC ) = 0 cm

F _A = ​​10 Newton

F _B = 20 Newton

FC ₌ Newtons 10

Tambaya : Lokacin ƙarfi da zai biyo baya idan sandar ta juya a kan axis a C

Amsa :

Lissafa lokacin ƙarfin da kowace ƙarfi ta samar.

Lokacin ƙarfi A

Στ _A = (F _A )(r _AC sin 90 ^o ) = (10 N) (0,4 m) (1) = -4 Nm

Lokacin ƙarfin A yana da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin A ya haifar tana juyawa ne a hannun agogo.

Lokacin ƙarfi B

Στ _B = (F _B )(r _BC zunubi 90 ^o ) = (20 N) (0,2 m) (1) = 4 Nm

Lokacin ƙarfin B yana da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin B ya haifar yana akasin agogon agogo.

Lokacin ƙarfi C

Στ _C = (F _C ) (r _CC sin 90 ^o ) = (10 N) (0) (1) = 0

An yiwa lokacin ƙarfin C alama da ƙimar 0 saboda ƙarfin F _C yana daidai da axis na juyawa.

Lokacin ƙarfi da ya biyo baya

Στ = ₁ + Στ ₂ + Στ ₃

Στ = -4 + 4 + 0

Στ = 0 Nm

Amsar da ta dace ita ce A.

4. Sanda mai tsawon santimita 50 tana da ƙarfi 3 iri ɗaya kamar yadda aka nuna a cikin hoton da ke ƙasa. Idan an juya sandar a kusa da pivot a wurin C, to girman jimlar lokacin ƙarfin shine…

A. 1 Nm

B. 3 Nm

C. 4 Nm

D. 5 Nm

E. 6 Nm

Tattaunawa

An sani cewa :

Axis na juyawa yana nan a wurin C.

Nisa tsakanin F ₁ da kuma axis na juyawa (r ₁ ) = 30 cm = mita 0,3

Nisa tsakanin F ₂ da kuma axis na juyawa (r ₂ ) = 10 cm = mita 0,1

Nisa tsakanin F ₃ da kuma axis na juyawa (r ₃ ) = 20 cm = mita 0,2

F ₁ = 10 Newton

F ₂ = 10 Newton

F ₃ = 10 Newton

Tambaya : Lokacin ƙarfi da zai biyo baya idan sandar ta juya a kan axis a C

Amsa :

Lissafa lokacin ƙarfin da kowace ƙarfi ta samar.

Lokacin ƙarfi 1

Στ ₁ = (F ₁ )(r ₁ sin 90 ^o ) = (10 N) (0,3 m) (1) = -3 Nm

Lokacin ƙarfin 1 ba shi da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin 1 ya haifar tana cikin alkibla ɗaya da juyawar hannun agogo.

Lokacin ƙarfi 2

Στ ₂ = (F ₂ )(r ₂ sin 90 ^o ) = (10 N) (0,1 m) (1) = 1 Nm

Moment of force 2 yana da kyau saboda alkiblar juyawar sandar da moment of force 2 ya haifar yana akasin agogo.

Lokacin ƙarfi 3

Στ ₃ = (F ₃ )(r ₃ sin 30 ^o ) = (10 N) (0,2 m) (0,5) = -1 Nm

Lokacin ƙarfin 3 ba shi da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin 3 ya haifar tana cikin alkibla ɗaya da juyawar hannun agogo.

Lokacin ƙarfi da ya biyo baya

Στ = ₁ + Στ ₂ + Στ ₃

Στ = -3 + 1 – 1

Στ = -3 Nm

Girman lokacin ƙarfin da aka samu shine mita 3 na Newton. Alamar da ba ta dace ba ga lokacin ƙarfin da aka samu yana nufin cewa alkiblar juyawar sandar da lokacin ƙarfin da aka samu ya haifar iri ɗaya ne da alkiblar juyawar hannun agogo.

Amsar da ta dace ita ce B.

5. Ƙarfi uku F1 _, F2 _, da F3 _{suna aiki} akan sanda kamar yadda aka nuna a cikin hoto mai zuwa. Idan aka yi watsi da nauyin sandar kuma tsawon sandar ya kai mita 4, to ƙimar lokacin ƙarfi game da axis na juyawa a wurin C shine…. (sin 53 ^o = 0,8, cos 53 ^o = 0,6, AB = BC = CD = DE = mita 1)

A. 12 Nm

B. 8 Nm

C. 6 Nm

D. 2 Nm

E. Sifili

Tattaunawa

An san cewa:

Axis na juyawa yana a wurin C.

Ƙarfi 1 (F ₁ ) = 5 Newtons

Nisa tsakanin wurin aiki F ₁ da kuma axis na juyawa (r ₁ ) = mita 2

Ƙarfi 2 (F ₂ ) = 0,4 Newtons

Nisa tsakanin wurin aiki F ₂ da kuma axis na juyawa (r ₂ ) = mita 1

Ƙarfi 3 (F ₃ ) = 4,8 Newtons

Nisa tsakanin wurin aiki F ₃ da kuma axis na juyawa (r ₃ ) = mita 2

Tambaya: Darajar lokacin ƙarfi game da axis na juyawa a wurin C

Amsa:

Lokacin Ƙarfi na 1:

τ ₁ = F ₁ r zunubi 53 ^o = (5 N) (2 m) (0,8) = (10) (0,8) N = 8 N

Lokacin ƙarfi na 1 yana sa sandar ta juya akasin agogo don haka lokacin ƙarfi na 1 yana da alama mai kyau.

Lokacin Ƙarfi na 2:

τ ₂ = F ₂ r zunubi 90 ^o = (0,4 N) (1 m) (1) = -0,4 N

Lokacin ƙarfi na 2 yana sa sandar ta juya zuwa ga juyawar agogo ta yadda lokacin ƙarfi na 2 zai sami alama mara kyau.

Lokacin Ƙarfi na 3:

τ ₃ = F ₃ r zunubi 90 ^o = (4,8 N) (2 m) (1) = -9,6 N

Lokacin ƙarfi na 3 yana sa sandar ta juya zuwa ga juyawar agogo ta yadda lokacin ƙarfi na 3 zai sami alama mara kyau.

Lokacin ƙarfi da ya biyo baya:

∑τ = τ ₁ - τ ₂ - τ ₃ = 8 - 0,4 - 9,6 = 8 - 10 = -2 Nm

Girman lokacin ƙarfin shine mita 2 na Newton. Lokacin ƙarfi mara kyau yana nufin sandar tana juyawa akasin agogo.

Amsar da ta dace ita ce D.

6. Girman lokacin ƙarfin da aka samu a kan axis a wurin O ta hanyar ƙarfin da ke aiki a kan sandar idan aka yi watsi da nauyinsa shine….

A. 7,5 Nm

B. 4 Nm

C. 3,5 Nm

D. 3 Nm

E. 2 Nm

Tattaunawa

An san cewa:

Axis na juyawa yana a wurin O.

Ƙarfi 1 (F ₁ ) = 6 Newtons

Nisa tsakanin wurin aiki F ₁ da kuma axis na juyawa (r ₁ ) = mita 1

Ƙarfi 2 (F ₂ ) = 6 Newtons

Nisa tsakanin wurin aiki F ₂ da kuma axis na juyawa (r ₂ ) = mita 2

Ƙarfi 3 (F ₃ ) = 4 Newtons

Nisa tsakanin wurin aiki F ₃ da kuma axis na juyawa (r ₃ ) = mita 2

Tambaya: Darajar lokacin ƙarfi game da axis na juyawa a wurin C

Amsa:

Lokacin Ƙarfi na 1:

τ ₁ = F ₁ l ₁ = (6 N) (1 m) = 6 Nm

Lokacin ƙarfi na 1 yana sa sandar ta juya akasin agogo don haka lokacin ƙarfi na 1 yana da alama mai kyau.

Lokacin Ƙarfi na 2:

τ ₂ = F ₂ r ₂ sin 30 ^o = (6 N)(2 m)(0,5)= 6 Nm

Lokacin ƙarfi na 2 yana sa sandar ta juya akasin agogo don haka lokacin ƙarfi na 2 yana da alama mai kyau.

Lokacin Ƙarfi na 3:

τ ₃ = F ₃ l ₃ = (4 N) (2 m) = -8 Nm

Lokacin ƙarfi na 3 yana sa sandar ta juya zuwa ga juyawar agogo ta yadda lokacin ƙarfi na 3 zai sami alama mara kyau.

Lokacin ƙarfi da ya biyo baya:

∑τ = τ ₁ + τ ₂ – τ ₃ = 6 + 6 – 8 = 4 nm

Girman lokacin ƙarfin shine mita 4 na Newton. Lokacin ƙarfi mai kyau yana nufin sandar tana juyawa akasin agogo.

Amsar da ta dace ita ce B.

7. Rod AB, wanda aka yi watsi da nauyinsa, an sanya shi a kwance kuma ƙarfi uku ne ke aiki da shi kamar yadda aka nuna a cikin hoton. Lokacin da ƙarfin da ke aiki akan sandar lokacin da aka juya shi akan axis a D shine… (zunubi 53 ^o = 0,8)

A. 2,4 N m
B. 2,6 N m
C. 3,0 N m
D. 3,2 N m
E. 3,4 N m

Tattaunawa
An sani :
Axis na juyawa ko juyawa yana nan a wurin D.
F₁ = 10 N da l₁ =r₁ sin θ = (40 cm)(sin 53)^o) = (0,4 m)(0,8) = mita 0,32
F₂ = 10√2 N da l₂ =r₂ sin θ = (20 cm)(sin 45)^o) = (0,2 m)(0,5√2) = mita 0,1√2
F₃ = 20 N da l₃ =r₁ sin θ = (10 cm)(sin 90)^o) = (0,1 m)(1) = mita 0,1
An tambaya : Sakamakon lokacin ƙarfi
Jawab :

(tabbatacce saboda wannan lokacin ƙarfi yana sa toshen ya juya akasin agogo)

(mara kyau saboda lokacin wannan ƙarfin yana sa toshen ya juya a hannun agogo)

(tabbatacce saboda wannan lokacin ƙarfi yana sa toshen ya juya akasin agogo)
Lokacin ƙarfi da ya biyo baya:

8. Rod AB, wanda aka yi watsi da nauyinsa, an sanya shi a kwance kuma ƙarfi uku ne ke aiki da shi kamar yadda aka nuna a cikin hoton. Lokacin da ƙarfin da ke aiki a kan sandar lokacin da aka juya shi a kan axis a D shine… (zunubi 53^o = 0,8)

A. 2,4 Nm
B. 2,6 Nm
C. 3,0 Nm
D. 3,2 Nm
E. 3,4 Nm

Tattaunawa
An sani :
Axis na juyawa yana nan a D.
Nisa tsakanin F₁ da kuma axis na juyawa (r)_AD) = 40 cm = 0,4 m
Nisa tsakanin F₂ da kuma axis na juyawa (r)_BD) = 20 cm = 0,2 m
Nisa tsakanin F₃ da kuma axis na juyawa (r)_CD) = 10 cm = 0,1 m
F₁ = 10 Newton
F₂ = 10√2 Newton
F₃ = 20 Newton
Zunubi 53^o = 0,8
An tambaya Lokacin ƙarfi da aka samu idan sandar ta juya a kan axis a D
Jawab :

Lissafa lokacin ƙarfin da kowace ƙarfi ta samar.
Lokacin ƙarfi 1
Moment of force 1 yana da kyau saboda alkiblar juyawar sandar da moment of force 1 ya haifar yana akasin agogo.
Lokacin ƙarfi 2
Lokacin ƙarfin 2 ba shi da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin 2 ya haifar tana cikin alkibla ɗaya da juyawar hannun agogo.
Lokacin ƙarfi 3
Moment of force 3 yana da kyau saboda alkiblar juyawar sandar da moment of force 3 ya haifar yana akasin agogo.
Lokacin ƙarfi da ya biyo baya
Amsar da ta dace ita ce D.

9. Sanda da aka yi watsi da nauyinta tana shafar ƙarfi uku F _A = ​​F _C = 10 N da F _B = 20 N kamar yadda aka nuna a cikin hoton. Idan nisan AB = BC = 20 cm, to girman lokacin ƙarfin da ke kusa da wurin C shine…

A. 0 Nm
B. 1 Nm
C. 4 Nm
D. 6 Nm
E. 8 Nm

Tattaunawa
An sani :
Axis na juyawa yana nan a wurin C.
Nisa tsakanin F_A da kuma axis na juyawa (r)_AC) = 40 cm = mita 0,4
Nisa tsakanin F_B da kuma axis na juyawa (r)_BC) = 20 cm = mita 0,2
Nisa tsakanin F_C da kuma axis na juyawa (r)_CC= 0 cm
F_A = 10 Newton
F_B = 20 Newton
F_C = 10 Newton
An tambaya Lokacin ƙarfi da aka samu idan sandar ta juya a kan axis a C
Jawab :
Lissafa lokacin ƙarfin da kowace ƙarfi ta samar.
Lokacin ƙarfi A
Lokacin ƙarfin A yana da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin A ya haifar tana juyawa ne a hannun agogo.
Lokacin ƙarfi B
Lokacin ƙarfin B yana da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin B ya haifar yana akasin agogon agogo.
Lokacin ƙarfi C

An yiwa lokacin ƙarfin C alama da ƙimar 0 saboda gaya F_C yayi daidai da axis na juyawa
Lokacin ƙarfi da ya biyo baya
Amsar da ta dace ita ce A.

10. Sanda mai tsawon santimita 50 tana da ƙarfi uku masu girma iri ɗaya kamar yadda aka nuna a cikin hoton da ke ƙasa. Idan an juya sandar a kusa da pivot a wurin C, to girman jimlar lokacin ƙarfin shine...

A. 1 Nm
B. 3 Nm
C. 4 Nm
D. 5 Nm
E. 6 Nm
Tattaunawa
An sani :
Axis na juyawa yana nan a wurin C.
Nisa tsakanin F₁ da kuma axis na juyawa (r)₁) = 30 cm = mita 0,3
Nisa tsakanin F₂ da kuma axis na juyawa (r)₂) = 10 cm = mita 0,1
Nisa tsakanin F₃ da kuma axis na juyawa (r)₃) = 20 cm = mita 0,2
F₁ = 10 Newton
F₂ = 10 Newton
F₃ = 10 Newton
An tambaya Lokacin ƙarfi da aka samu idan sandar ta juya a kan axis a C
Jawab :
Lissafa lokacin ƙarfin da kowace ƙarfi ta samar.
Lokacin ƙarfi 1
Lokacin ƙarfin 1 ba shi da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin 1 ya haifar tana cikin alkibla ɗaya da juyawar hannun agogo.
Lokacin ƙarfi 2
Moment of force 2 yana da kyau saboda alkiblar juyawar sandar da moment of force 2 ya haifar yana akasin agogo.
Lokacin ƙarfi 3
Lokacin ƙarfin 3 ba shi da kyau saboda alkiblar juyawar sandar da lokacin ƙarfin 3 ya haifar tana cikin alkibla ɗaya da juyawar hannun agogo.
Lokacin ƙarfi da ya biyo baya
Girman lokacin ƙarfin da aka samu shine mita 3 na Newton. Alamar da ba ta dace ba ga lokacin ƙarfin da aka samu yana nufin cewa alkiblar juyawar sandar da lokacin ƙarfin da aka samu ya haifar iri ɗaya ne da alkiblar juyawar hannun agogo.
Amsar da ta dace ita ce B.

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