Misalin tambayoyin da'irar lantarki

Misalan Matsalolin Lantarki 15

1. Kalli hoton!

Idan R ₁ , = 6 Ω, R ₂ = R ₃ = 2 Ω, kuma bambancin yuwuwar shine volts 14, to girman kwararar wutar lantarki shine...

A. 7 A

B. 6 A

C. 2 A

D. 1 A

Tattaunawa

An san cewa:

Resistor 1 (R ₁ ) = 6 Ω

Resistor 2 (R ₂ ) = 2 Ω

Resistor 3 (R3 ₎ = 2 Ω

Bambancin da zai iya faruwa (V) = Volts 14

Tambaya : Yaya ƙarfin wutar lantarki ke gudana?

Amsa:

Lissafi na maye gurbin resistor (R):

An haɗa R ₂ da R _{3 a layi ɗaya. Resistor ɗin maye gurbin sune:}

1/R ₂₃ = 1/R ₂ + 1/R ₃ = 1/2 + 1/2 = 2/2

R ₂₃ = 2/2 = 1 Ω

An haɗa R ₁ da R _{23 a jere. Resistor ɗin maye gurbin shine:}

R = R ₁ + R ₂₃ = 6 Ω + 1 Ω

R = 7Ω

Lissafa ƙarfin halin yanzu (I):

I = V / R = 14 / 7 = Amperes 2

Amsar da ta dace ita ce C.

2. Idan kowace resistor tana da ƙima ɗaya kuma an sanya ta a daidai bambancin yuwuwar, to da'irar da ke da ƙimar wutar lantarki mafi girma ita ce...

Tattaunawa

A ce darajar kowace resistor R ce kuma bambancin da ke tsakaninta da V shine V.

Amsar da ta dace ita ce B.

3. Kalli hoton!

Lokacin da aka haɗa maɓallin S ₂ , ana nuna madaidaicin alkiblar wutar lantarki ta hanyar maki...

A. A – B – E – F

B. B – C – D – F

C. A – C – D – F

D. F – E – B – A

Tattaunawa

Wutar lantarki tana motsawa daga wurin da ke da babban ƙarfin lantarki zuwa wurin da ke da ƙarancin ƙarfin lantarki. Idan an rufe maɓallin s2 (switch s2 yana kusa da wurin A), to wutar lantarki tana motsawa daga A zuwa B zuwa E zuwa F. Wutar lantarki ba ta motsawa zuwa C da D saboda C da D suna cikin da'irar buɗewa.

Amsar da ta dace ita ce A.

4. Kalli hoton da ke ƙasa!

Idan R ₁ = 4 ohms, R ₂ = 6 ohms, R ₃ = 2 ohms, da V = 24 volts, to adadin wutar lantarki da ke gudana a cikin da'irar shine...

A. 0,5 ampere

B. 1 ampere

C. 2 amperes

D. 12 amperes

Tattaunawa

An san cewa:

Resistor 1 (R ₁ ) = 4 Ohm

Resistor 2 (R ₂ ) = 6 Ohm

Resistor 3 (R ₃ ) = 2 Ohm

Wutar lantarki (V) = Volts 24

An tambaya: Ƙarfin wutar lantarki da ke gudana a cikin da'irar

Amsa:

An haɗa R ₁ , R ₂ da R _{3 a jere. Resistor ɗin maye gurbin sune:}

R = R ₁ + R ₂ + R ₃ = 4 + 6 + 2

R = 12 Ohm

Wutar lantarki da ke gudana a cikin da'irar:

I = V / R = 24 / 12 = Amperes 2

Amsar da ta dace ita ce C.

5. Kalli hoton! Fitilar da wutar lantarkinta take iri ɗaya da wutar da ke wucewa ta tushen emf ita ce...

A. L₁

B. L ₂

C. L ₃

D. L ₄

Tattaunawa

Dokar Farko ta Kirchhoff ta bayyana cewa wutar lantarki da ke ratsa wani reshe za ta rabu. Misali, idan wutar lantarki da ke gudana daga tushen emf ta kai Amperes 4, idan ta shiga reshe biyu, wannan wutar lantarki za ta rabu biyu, kowanne waya tana ɗauke da wutar lantarki ta Amperes 2. Wutar lantarki ta Amperes 2 ta rabu biyu idan wutar lantarki ta shiga reshe mai reshe biyu. Duk da haka, bisa ga hoton da ke sama, wutar lantarki da aka raba a ƙarshe za ta sake haɗuwa.

Don haka bisa ga hoton da ke sama, fitilar da wutar lantarkinta take iri ɗaya da wutar da ke wucewa ta tushen emf ita ce fitilar biyu (L2 ₎ wacce take kusa da kusurwar dama ta sama.

Amsar da ta dace ita ce B.

6. Daga cikin zane mai zuwa, wanne ne zai jagoranci mafi girman wutar lantarki?

Tattaunawa

Wutar lantarki a cikin da'irar A.

Resistor mai maye gurbin (R):

R ₁ = 3 Ω, R ₂ = 4 Ω, R ₃ = 4 Ω, V = 12 Volts

An haɗa R ₂ da R _{3 a layi ɗaya. Resistor ɗin maye gurbin sune:}

1/R ₂₃ = 1/R ₂ + 1/R ₃ = 1/4 + 1/4 = 2/4 = 1/2

R ₂₃ = 2/1 = 2 Ω

An haɗa R ₁ da R _{23 a jere. Resistor ɗin maye gurbin shine:}

R = R ₁ + R ₂₃ = 3 Ω + 2 Ω = 5 Ω

Ƙarfin wutar lantarki (I):

I = V / R = 12 / 5 = Amperes 2,4

Wutar lantarki a cikin da'irar B.

Resistor mai maye gurbin (R):

R ₁ = 8 Ω, R ₂ = 2 Ω, R ₃ = 2 Ω, V = 36 Volts

An haɗa R ₁ , R ₂ da R _{3 a jere. Resistor ɗin maye gurbin sune:}

R = R ₁ + R ₂ + R ₃ = 8 + 2 + 2 = 12 Ω

Ƙarfin wutar lantarki (I):

I = V / R = 36 / 12 = Amperes 3

Wutar lantarki a cikin da'irar C.

Resistor mai maye gurbin (R):

R ₁ = 4 Ω, R ₂ = 4 Ω, R ₃ = 6 Ω, V = 12 Volts

An haɗa R ₂ da R _{3 a layi ɗaya. Resistor ɗin maye gurbin sune:}

1/R ₂₃ = 1/R ₂ + 1/R ₃ = 1/4 + 1/4 + 1/6 = 3/12 + 3/12 + 2/12 = 8/12

R ₂₃ = 12/8 = 1,5 Ω

Ƙarfin wutar lantarki (I):

I = V / R = 12 / 1,5 = Amperes 8

Wutar lantarki a cikin da'irar D.

Resistor mai maye gurbin (R):

R₁ = 3 Ω, R₂ = 3 Ω, R₃ = 3 Ω, R₄ = 3 Ω, R₅ = 6 Ω, V = Volt 24

An haɗa R ₂ , R ₃ da R _{4 a layi ɗaya. Resistor ɗin maye gurbin sune:}

1/R ₂₃₄ = 1/R ₂ + 1/R ₃ + 1/R ₄ = 1/3 + 1/3 + 1/3 = 3/3

R ₂₃₄ = 3/3 = 1 Ω

An haɗa R ₁ , R ₂₃₄ da R _{5 a jere. Resistor ɗin maye gurbin sune:}

R = R ₁ + R ₂₃₄ + R ₅ = 3 + 1 + 6 = 9 Ω

Ƙarfin wutar lantarki (I):

I = V / R = 24 / 9 = Amperes 2,6

Amsar da ta dace ita ce C.

7. Kula da jerin masu zuwa!

Ƙayyade:

A. Juriya gaba ɗaya

B. Girman wutar lantarki a cikin da'irar

C. Yanzu I ₁

D. Yanzu I ₂

Tattaunawa

An san cewa:

Resistor 1 (R ₁ ) = 4 Ω

Resistor 2 (R ₂ ) = 4 Ω

Resistor 3 (R ₃ ) = 2 Ω

Resistor 4 (R ₄ ) = 3 Ω

Wutar lantarki (V) = Volts 12

Amsa:

A. Jimlar juriya (R)

_An haɗa masu juriya R2 _da R3 a jere. Masu juriyar maye gurbin sune:

R ₂₃ = R ₂ + R ₃ = 4 Ω + 2 Ω = 6 Ω

An haɗa Resistor R ₂₃ da Resistor R _{4 a layi ɗaya. Resistor ɗin maye gurbin shine:}

1/R ₂₃₄ = 1/ R ₂₃ + 1/ R ₄ = 1/6 + 1/3 = 1/6 + 2/6 = 3/6

R ₂₃₄ = 6/3 = 2 Ω

An haɗa Resistor R ₁ da Resistor R _{234 a jere. Resistor ɗin maye gurbin shine:}

R = R ₁ + R ₂₃₄ = 4 Ω + 2 Ω = 6 Ω

Don haka jimlar juriya ita ce 6 ohms.

B. Girman wutar lantarki a cikin da'irar (I)

Tsarin da ke nuna alaƙar da ke tsakanin ƙarfin lantarki, wutar lantarki da juriya shine:

V = IR

Bayanin dabara: V = Wutar lantarki, I = wutar lantarki, R = juriyar lantarki

Yi amfani da wannan dabarar don ƙididdige ƙarfin wutar lantarki:

I = V / R = Volts 12 / Ohms 6 = Amps 2

C. Yanzu I₁

Wutar lantarki da ke ratsawa ta cikin resistor R ₁ = wutar lantarki da ke ratsawa ta cikin da'irar = 2 Amperes.

D. Yanzu I₂

Kafin a ƙididdige wutar lantarki da ke ratsa resistor R₂, da farko ku kula da bayanin da ke ƙasa.

An haɗa masu juriya R ₂₃ da R ₄ a layi ɗaya. Mai maye gurbin da aka yi bisa ga lissafin da ya gabata shine R ₂₃₄ = 2 Ohm.

Wutar lantarki da ke ratsa resistor R ₂₃₄ = wutar lantarki da ke ratsa resistor R ₁ = 2 Amperes.

Bambancin da ke tsakanin ƙarshen biyu na resistor R₂₃₄ shine:

V = IR ₂₃₄ = (2 A)(2 Ohm ) = Volts 4

Bambancin da ke tsakanin ƙarshen biyu na resistor R ₂₃₄ = bambancin da ke tsakanin ƙarshen biyu na resistor R ₄ = bambancin da ke tsakanin ƙarshen biyu na resistor R ₂₃ = Volts 4.

Resistor mai maye gurbin R ₂₃ bisa ga sakamakon lissafin da ya gabata shine 6 Ohms.

Don haka wutar lantarki da ke ratsawa ta cikin resistor mai maye gurbin R₂₃ shine:

I = V / R = Volts 4 / Ohms 6 = 2/3 Ampere

Wutar lantarki da ke ratsawa ta cikin resistor R ₂₃ = wutar lantarki da ke ratsawa ta cikin resistor R ₂ = wutar lantarki da ke ratsawa ta cikin resistor R ₃ = 2/3 Ampere.

8. Duba da'irar lantarki a gefe! Idan R ₁ = R ₂ = 10 Ω da R ₃ = R ₄ = 8 Ω. Nawa ne wutar lantarki (I) ke gudana?

A. 0,5 A

B. 2 A

C. 36 A

D. 288 A

Tattaunawa

An san cewa:

Resistor R ₁ = Resistor R ₂ = 10 Ω

Resistor R ₃ = Resistor R ₄ = 8 Ω

Wutar lantarki (V) = Volts 12

Tambaya: Ƙarfin wutar lantarki (I) da ke gudana

Amsa:

Resistor mai maye gurbin (R).

An haɗa Resistor R ₃ da Resistor R _{4 a layi ɗaya, Resistor ɗin maye gurbin shine:}

1/R ₃₄ = 1/R ₃ + 1/R ₄ = 1/8 + 1/8 = 2/8

R ₃₄ = 8/2 = 4 Ω

An haɗa masu juriya R ₁ , R ₂ da R ₃₄ a jere, masu adawa da maye gurbin sune:

R = R ₁ + R ₂ + R ₃₄ = 10 Ω + 10 Ω + 4 Ω = 24 Ω

Ƙarfin wutar lantarki:

I = V / R = Volts 12 / Ohms 24 = Volts 0,5/Ohms = Amps 0,5

Amsar da ta dace ita ce A.

9. Kalli hoton da'irar lantarki da aka rufe a gefe! Idan aka yi watsi da juriyar da ke cikin batirin, to wutar lantarki (I) da ke gudana a cikin da'irar tana…..

A. 0,5 Ampere

B. 1 Ampere

C. 2 Amperes

D. 3 Amperes

Tattaunawa

An san cewa:

Resistor R ₁ = 3 Ohm

Resistor R ₂ = 3 Ohm

Resistor R ₃ = 6 Ohm

Wutar lantarki (V) = Volts 6

Tambaya: Ƙarfin wutar lantarki (I)

Amsa:

Lissafi na maye gurbin resistor:

An haɗa masu juriya R ₁ da R ₂ a jere. Masu juriyar maye gurbin sune:

R ₁₂ = R ₁ + R ₂ = 3 Ohms + 3 Ohms = 6 Ohms

An haɗa Resistor R12 da resistor 3 a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R = 1/R ₁₂ + 1/R ₃ = 1/6 + 1/6 = 2/6

R = 6/2 = 3 Ohms

Ƙarfin wutar lantarki:

I = V / R = 6 / 3 = Amperes 2

Amsar da ta dace ita ce C.

10. Duba zane-zanen da'irar da aka rufe a ƙasa! Jimlar wutar lantarki a cikin da'irar ita ce…..

A. 0,5 A

B. 0,6 A

C. 1,2 A

D. 2,0 A

Tattaunawa

An san cewa:

Resistor R ₁ = 6 Ohm

Resistor R ₂ = 4 Ohm

Wutar lantarki (V) = Volts 6

Juriyar ciki (r) = 0,6 Ohm

Tambaya: Jimlar wutar lantarki a cikin da'irar

Amsa:

Resistor R₁ da kuma juriya R₂ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R _P = 1/R1 + 1/R2 = 1/6 + 1/4 = 4/24 + 6/24 = 10/24

R _P = 24/10 = 2,4 Ohm

Resistor R_P kuma juriyar ciki (r) an haɗa ta a jere. Daidaiton juriya shine:

R = R _P + r = 2,4 Ohm + 0,6 Ohm = 3,0 Ohm

Jimillar wutar lantarki da ke cikin da'irar ita ce:

I = V / R = Volts 6 / Ohms 3 = Amps 2

Amsar da ta dace ita ce D.

11.

Kalli da'irar wutar lantarki a gefe! Girman wutar lantarki V shine…

A. Volt 9,6
B. 6,4 Volt
C. 4,5 Volt
D. 3,2 Volt

Tattaunawa

An san cewa:
Resistor 1 (R)₁) = 16 Ohms
Resistor 2 (R)₂) = 8 Ohms
Resistor 3 (R)₃) = 6 Ohms
Wutar lantarki (I) = Amperes 2
Tambaya: Wutar lantarki (V)
Amsa:
Resistor mai maye gurbin
R₁ da kuma R₂ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R_A =R₁ + R₂ = 16 + 8 = 24 Ohms
R_A da kuma R₃ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R = 1/R_A +1/R₃ = 1/24 + 1/6
1/R = 1/24 + 4/24 = 5/24
R = 24/5 = 4,8 Ohms
Ƙarfin wutar lantarki :
V = IR = (2)(4,8) = 9,6 Volt
Amsar da ta dace ita ce A.

12. Duba zane-zanen da'irar lantarki a gefe! Idan aka yi watsi da juriyar da ke cikin tushen wutar lantarki, to voltmeter V yana nuna ƙarfin lantarki da aka auna na...

A. 4 V
B. 6 V
C. 9 V
D. 10 V

Tattaunawa

An san cewa:
Resistor 1 (R)₁) = 3,6 Ohms
Resistor 2 (R)₂) = 6 Ohms
Resistor 3 (R)₃) = 4 Ohms
Wutar lantarki (I) = Amperes 1,5
Tambaya: Wutar lantarki (V)
Amsa:
Resistor mai maye gurbin
R₂ da kuma R₃ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1 / R_A = 1/R₂ +1/R₃ = 1/6 + 1/4
1 / R_A = 2/12 + 3/12 = 5/12
R_A = 12/5 = 2,4 Ohms
R₁ da kuma R_A An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R=R₁ + R_A = 3,6 + 2,4 = 6 Ohms
Ƙarfin wutar lantarki :
V = IR = (1,5)(6) = 9 Volt
Amsar da ta dace ita ce C.

13.
Kalli wannan zane mai kama da na'urar lantarki da aka rufe! Idan aka yi watsi da juriyar da ke cikin tushen wutar lantarki E, to voltmeter V yana nuna ƙarfin lantarki da aka auna na...
A. 2 V
B. 4 V
C. 6 V
D. 12 V
Tattaunawa
An san cewa:
Resistor 1 (R)₁) = 3 Ohms
Resistor 2 (R)₂) = 2 Ohms
Resistor 3 (R)₃) = 4 Ohms
Wutar lantarki (I) = Amperes 2
Tambaya: Wutar lantarki (V)
Amsa:
Resistor mai maye gurbin
R₂ da kuma R₃ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R_A =R₂ + R₃ = 2 + 4 = 6 Ohms
R₁ da kuma R_A an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R = 1/R₁ +1/R_A = 1/3 + 1/6
1/R = 2/6 + 1/6 = 3/6
R = 6/3 = 2 Ohms
Ƙarfin wutar lantarki :
V = IR = (2)(2) = 4 Volt
Amsar da ta dace ita ce B.

14. A cikin zane mai zuwa na da'irar lantarki, A, B, C, D da E fitilun wutar lantarki iri ɗaya ne.

Idan aka cire fitilar B, fitilar da ke haskakawa ta fi kyau...

A. fitilun A da C

B. fitilu A da D

Fitilun C. C da D

Fitilun D. C da E

Fitilu E. D da E

Tattaunawa

Fitilun wutar lantarki guda biyar iri ɗaya suna nufin cewa kowace fitila tana da juriya iri ɗaya.

Domin juriya iri ɗaya ce, hasken fitilar ya dogara ne kawai da ƙarfin wutar lantarki da ke ratsa ta cikin fitilar.

A bisa ga dokar Kirchhoff ta farko, wutar lantarki da ke ratsa fitilun D da E iri ɗaya ce domin an haɗa su a jere, yayin da wutar lantarki da ke ratsawa ta cikin da'ira mai layi ɗaya za a raba ta.

Idan aka cire fitilar B, fitilun da suka fi haske su ne fitilun D da E, inda fitilun biyu suke da harshen wuta iri ɗaya.

Amsar da ta dace ita ce E.

15. Kalli zane mai zuwa na da'irar lantarki!

Idan tushen wutar lantarki yana da bambancin yuwuwar volts 24, wutar lantarki a wurin reshe na I shine…

A. 1,2 A

B. 2,0 A

C. 2,4 A

D. 3,0 A

Tattaunawa

An san cewa:

Tushen EMF (E) = Volts 24

Juriyar ciki (r) = 2 Ohm

Resistor 40 Ohm, 20 Ohm da 20 Ohm.

Tambaya: Ƙarfin halin yanzu a wurin reshe na I

Amsa:

An haɗa resistors guda uku a layi ɗaya, resistors masu maye gurbin sune:

1/R = 1/40 + 1/20 + 1/20

1/R = 1/40 + 2/40 + 2/40

1/R = 5/40

R = 40/5

R = 8 Ohm

Ƙarfin wutar lantarki:

V = E – I r

V = 24 – I 2

Ƙarfin halin yanzu a wurin reshe na I:

V = IR

24 – I 2 = I 8

24 = I 8 + I 2

24 = I (10)

I = 24/10

I = 2,4 Amperes

Amsar da ta dace ita ce C.

Tushen tambaya:

Tambayoyin Jarrabawar Ƙasa ta Kimiyya ta Makarantar Sakandare/Makarantar Sakandare ta Musulunci

Tambayoyin Kimiyyar Kimiyyar SBMPTN