Misali na amfani da dokar farko ta thermodynamics ga tsarin isobaric (matsi mai ɗorewa)

6 Misalan tambayoyi kan amfani da dokar thermodynamics ta farko ga hanyoyin isobaric (matsi mai ɗorewa)

1. Matsi (P) - jadawalin girma (V) na iskar gas da ke fuskantar tsarin isobaric. Aikin da iskar gas ke yi a cikin tsarin AB shine…

Misali na amfani da dokar thermodynamics ta farko ga tsarin isobaric mai matsin lamba akai-akai 1Tattaunawa

An sani :
Matsi (P) = 5 x 105 N / m2
Ƙaramin farko (V)1= 2m3
Ƙarar ƙarshe (V)2= 6m3
An tambaya : aikin da aka yi a cikin tsari AB
Jawab :
W = P (V)2 - V1)
W = (5 x 105)(6 – 2) = (5 x 10)5) (4)
W = 20 x 105 = 2 x106 Joule

2. Bambancin aikin da iskar gas ke yi a cikin hanyoyin AB da CD shine…

Misali na amfani da dokar thermodynamics ta farko ga tsarin isobaric mai matsin lamba akai-akai 2Tattaunawa

An sani :
Tsarin isobaric AB :
Matsi (P) = 6 atm = 6 x 105 N / m2
Ƙaramin farko (V)1) = lita 1 = 1 dm3 = 1 x10-3 m3
Ƙarar ƙarshe (V)2) = lita 3 = 3 dm3 = 3 x10-3 m3 
Tsarin isobaric na CD :
Matsi (P) = 4 atm = 4 x 105 N / m2
Ƙaramin farko (V)1) = lita 2 = 2 dm3 = 2 x10-3 m3
Ƙarar ƙarshe (V)2) = lita 5 = 5 dm3 = 5 x10-3 m3
An tambaya Bambanci a cikin aikin da gas ke yi a cikin hanyoyin AB da CD
Jawab :
Aikin da gas ke yi a cikin tsarin AB:
W = P (V)2 - V1)
W = (6 x 105)(3 x 10-3 - 1 x 10-3)
W = (6 x 105)(2 x 10-3)
W = 12 x 102 = Joule 1200
Aikin da iskar gas ta yi a cikin tsarin CD:
W = P (V)2 - V1)
W = (4 x 105)(5 x 10-3 - 2 x 10-3)
W = (4 x 105)(3 x 10-3)
W = 12 x 102 = Joule 1200
Bambancin aikin da iskar gas ke yi a cikin hanyoyin AB da CD shine 1200 - 1200 = 0.

3. Aikin da iskar gas ta yi a tsarin ABC shine…

Misali na amfani da dokar thermodynamics ta farko ga tsarin isobaric mai matsin lamba akai-akai 3Tattaunawa
An sani :
Matsi na 1 (P)1= 6 x 105 Pascal = 6 x 105 N / m2
Matsi na 2 (P)2= 3 x 105 Pascal = 3 x 105 N / m2
Juzu'i na 1 (V)1= 2 cm3 = 2 x10-6 m3
Juzu'i na 2 (V)2= 6 cm3 = 6 x10-6 m3
An tambaya : Kokarin da aka yi a tsarin ABC.
Jawab :
A cikin tsarin AB, ƙarar tana nan daram, don haka babu wani aiki da gas ke yi. Iskar tana aiki ne kawai a cikin tsarin BC. Don haka aikin da ke aiki ABC = aikin da ke aiki BC.
W = P2 (V2 - V1)
W = (3 x 105)(6 x 10-6 - 2 x 10-6)
W = (3 x 105)(4 x 10-6)
W = 12 x 10-1
W = Joule 1,2
Aikin da aka yi a cikin tsarin ABC = Joules 1,2.

4. Bayanin da ya dace game da hanyoyin thermodynamic shine…
A. Isobaric tsari ne na canza iskar gas a matsin lamba akai-akai.
B. Isobaric tsari ne na canza iskar gas a yanayin zafi mai ɗorewa.
C. Isochoric tsari ne na canza iskar gas a matsin lamba akai-akai.
D. isotherm shine tsarin canza iskar gas a daidai girman da ake buƙata.
E. Isochoric tsari ne na canza iskar gas a yanayin zafi mai ɗorewa.
Tattaunawa
Isobaric = matsin lamba akai-akai
Isochoric = ƙarar da ba ta canzawa
Isothermal = yanayin zafi mai ɗorewa
Amsar da ta dace ita ce A.

5. Kwatanta ƙoƙarin da aka yi a cikin matakai na I da na II bisa ga jadawalin da ke ƙasa shine...
A. 4: 3
B. 3: 4
C. 2: 3
D. 1: 2
E. 1: 3
Tattaunawa:

Dokar 1 ta Thermodynamics 1

An sani :
Tsarin I: P = 15 N/m2, V1 = 15 m3, V2 = 35 m3
Tsarin II: P = 10 N/m2, V1 = 5 m3, V2 = 45 m3
An tambaya :
Kwatanta ƙoƙari (W) na tsari na I da tsari na II?
Jawab :
Dokar 1 ta Thermodynamics 2Amsar da ta dace ita ce B.

6. An nuna zane-zanen PV na iskar helium da ke fuskantar tsarin thermodynamic a cikin hoton da ke ƙasa! Aikin da iskar helium ke yi a cikin tsarin ABC shine…
A. 400 kJ
B. 500 kJ
C. 600 kJ
D. 800 kJ
E. 1000 kJ

Dokar 1 ta Thermodynamics 3Tattaunawa:
An sani :
P1 = 2 x105 N / m2
P2 = 1 x105 N / m2
V1 = 5 m3
V2 = 15 m3
An tambaya :
Aiki (W) a cikin tsarin ABC?
Jawab :
Ana yin aiki ne kawai lokacin da yawan iskar gas ya ƙaru. A cikin tsarin AB, yawan iskar gas ya kasance iri ɗaya, don haka babu wani aiki da iskar helium ke yi. A cikin tsarin BC, yawan iskar gas yana ƙaruwa, don haka ana yin aiki da iskar helium.

Dokar 1 ta Thermodynamics 4

 

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