Tambayoyi Misali Game da Iskar Oxidation da Ragewa
Pendahuluan
Oxidation da ragewa muhimman ra'ayoyi ne a fannin ilmin sunadarai waɗanda suke da alaƙa kuma ba za a iya raba su ba. Waɗannan hanyoyin suna faruwa a lokaci guda a cikin wani martani da aka sani da redox reaction (oxidation-reduction reaction). A cikin wannan martanin, sinadarin da ake samu daga oxidation yana sakin electrons, yayin da sinadarin da ake samu daga ragewa yana samun electrons. Don fahimtar da zurfi, bari mu dubi wata matsala misali da bayaninta.
Tambayoyi da Tattaunawa kan Iskar Oxidation da Ragewa
Misali Tambaya ta 1
Tambaya:
Ƙayyade abubuwan da ke shan iskar shaka da raguwa a cikin waɗannan halayen:
\[ 2Mg(s) + O_2(g) \rightarrow 2MgO(s) \]
Tattaunawa:
Domin tantance waɗanne abubuwa ne ake shaƙatawa da ragewa, muna buƙatar duba canjin adadin iskar shaka na kowane abu a cikin amsawar.
1. Lambobin iskar oxygen a cikin mahaɗin farko:
– Magnesium (Mg) sinadari ne mai kyauta a cikin siffa mai ƙarfi (s), don haka lambar iskar shakawarsa ita ce 0.
– Oxygen (O₂) a cikin nau'in ƙwayoyin iskar gas (g) sinadari ne mai 'yanci, don haka lambar oxidation ɗinsa ita ma 0 ce.
2. Adadin iskar oxygen a cikin mahaɗan samfur:
– Magnesium a cikin magnesium oxide (MgO) yana da adadin iskar shaka na +2 (Mg²⁺).
– Iskar oxygen a cikin magnesium oxide (MgO) tana da adadin iskar oxygen na -2 (O²⁻).
3. Canje-canje a cikin adadin iskar shaka:
– Magnesium yana canzawa daga 0 zuwa +2. Wannan yana nufin cewa magnesium ya fuskanci ƙaruwar adadin iskar shaka, ko kuma an yi masa oxidation.
– Iskar oxygen tana canzawa daga 0 zuwa -2. Wannan yana nufin cewa iskar oxygen ta fuskanci raguwar adadin iskar oxygen, ko kuma an rage ta.
Ƙarshe:
– Magnesium (Mg) wani sinadari ne da ke shiga cikin iskar oxygen.
– Oxygen (O₂) wani abu ne da ake rage shi.
Misali Tambaya ta 2
Tambaya:
Gano wakilin oxidizing da wakilin ragewa a cikin wannan amsawar:
\[Zn + CuSO_4 \arrow ZnSO_4 + Cu \]
Tattaunawa:
A cikin wannan martanin, za mu tantance wanda aka yi wa oxidation da wanda aka rage, da kuma gano wakilin oxidizing da wakilin ragewa.
1. Masu amsawa:
– Zn(s): Lambar iskar oxygen = 0.
– Cu in CuSO₄ : Oxidation lamba = +2.
2. Kayayyaki:
– Zn a cikin ZnSO₄: Lambar iskar oxygen = +2.
– Cu(s): Lambar iskar oxygen = 0.
3. Canje-canje a cikin Adadin Iskar Shaka:
– Zn yana canzawa daga 0 zuwa +2. Wannan yana nufin cewa Zn yana fuskantar ƙaruwa a adadin iskar shaka, ko kuma yana fuskantar iskar shaka.
– Cu yana canzawa daga +2 zuwa 0. Wannan yana nufin cewa Cu yana fuskantar raguwar adadin iskar shaka, ko kuma yana fuskantar raguwa.
4. Sinadaran da ke rage iskar oxygen da kuma sinadaran rage iskar oxygen:
– Maganin oxidizing wani abu ne da ke haifar da oxidation wani abu, kuma shi kansa yana raguwa. A cikin wannan amsawar, Cu²⁺ a cikin CuSO₄ yana sa Zn ya oxidize, don haka Cu²⁺ shine wakilin oxidizing.
– Maganin ragewa abu ne da ke haifar da raguwar wani abu, kuma ana yin oxidize da kansa. A cikin wannan amsawar, Zn yana sa Cu²⁺ ya ragu, don haka Zn wakili ne mai ragewa.
Ƙarshe:
– Maganin oxidizing shine Cu²⁺ a cikin CuSO₄.
– Maganin ragewa shine Zn.
Misali Tambaya ta 3
Tambaya:
Lissafa adadin oxidation na abubuwan da ke cikin waɗannan mahaɗan:
\[ H_2SO_4 \]
Tattaunawa:
Domin tantance adadin iskar shaka na kowane abu a cikin sinadarin sulfuric acid (H₂SO₄), muna amfani da ƙa'idodi don tantance lambobin iskar shaka.
1. Hydrogen (H) a cikin mahadi yawanci yana da adadin oxidation na +1.
2. Iskar oxygen (O) a cikin mahadi yawanci tana da adadin iskar oxygen na -2.
3. Jimillar adadin oxidation a cikin wani abu mai tsaka tsaki dole ne ya zama 0.
Yanzu muna lissafi:
– Hydrogen: Atom 2 na H kowanne +1, jimilla (+1) 2 = +2.
– Oxygen: Atom 4 O kowanne -2, jimilla (-2) 4 = -8.
– Sulfur: A ce lambar iskar shaka S = x.
Jimlar adadin sinadaran iskar shaka:
\[ 2(+1) + x + 4(-2) = 0 \]
\[ 2 + x – 8 = 0 \]
\[ x – 6 = 0 \]
\[x = +6 \]
Ƙarshe:
– Lambar iskar oxygen H = +1
– Lambar iskar oxygen O = -2
– Lambar iskar oxygen S = +6
Misali Tambaya ta 4
Tambaya:
A cikin wannan amsawar, ƙayyade adadin oxidation na kowane abu, kuma ƙayyade rabin amsawar wannan amsawar redox:
\[ MnO_4^- + 8H^+ + 5Fe^{2+} \rightarrow Mn^{2+} + 4H_2O + 5Fe^{3+} \]
Tattaunawa:
1. Ƙayyade adadin iskar shaka:
– Mn a cikin MnO₄⁻ : Adadin iskar shaka na Mn shine +7. (Domin O = -2 a cikin atom 4 O: (-2) 4 = -8; Daidaitaccen ion na MnO₄⁻ = -1; Don haka Mn dole ne ya zama +7 don daidaito: +7 – 8 = -1).
– Fe a cikin Fe²⁺ : Adadin iskar shaka na Fe shine +2.
– Mn a cikin Mn²⁺: Adadin iskar shaka na Mn shine +2.
– Fe a cikin Fe³⁺ : Adadin iskar shaka na Fe shine +3.
– Iskar Oxygen a cikin H₂O: Adadin iskar O shine -2.
– Hydrogen a cikin H₂O: Adadin iskar shaka na H shine +1.
2. Kayyade rabin amsawar:
– Haɗakar iskar oxygen (Fe²⁺ ya zama Fe³⁺):
\[ Fe^{2+} \rightarrow Fe^{3+} + e^- \]
– Rage amsawar (MnO₄⁻ zuwa Mn²⁺):
\[ MnO_4^- + 8H^+ + 5e^- \arrow Mn^{2+} + 4H_2O \]
Ƙarshe:
– Adadin iskar shaka na Mn a cikin MnO₄⁻ shine +7.
– Adadin iskar shaka na Fe a cikin Fe²⁺ shine +2.
– Adadin iskar shaka na Fe a cikin Fe³⁺ shine +3.
Penutup
Ta hanyar fahimtar misalan da tattaunawarsu, za mu iya fahimtar ra'ayoyin oxidation da ragewa a cikin sinadarai cikin sauƙi. Lambobin oxidation suna taka muhimmiyar rawa wajen tantance waɗanne abubuwa ne aka oxidized da kuma waɗanne ne aka rage a cikin halayen sinadarai. Da fatan, wannan labarin zai taimaka muku fahimtar da kuma fahimtar ra'ayoyin oxidation da ragewa.
