Tambayoyi da Tattaunawa game da Daidaito a cikin Magani Misali
Pendahuluan
Daidaiton sinadarai muhimmin ra'ayi ne a fannin ilmin sunadarai wanda yake da matukar muhimmanci wajen fahimtar halayen sinadarai. Daidaiton sinadarai a cikin wani bayani yanayi ne da halayen biyu ko fiye masu adawa ke faruwa a daidai wannan lokaci, don haka yawan sinadaran da ke cikin sinadaran da kuma kayayyakinsu ya kasance iri daya a tsawon lokaci. A cikin wannan labarin, za mu tattauna misalai da dama na daidaito a cikin mafita kuma mu tattauna su dalla-dalla. Muna fatan wannan labarin zai taimaka muku zurfafa fahimtar ka'idar daidaiton sinadarai.
Ka'idoji na Asali na Daidaiton Sinadarai
Kafin mu shiga cikin tambayoyin misalai da tattaunawa, yana da mahimmanci mu fahimci wasu mahimman ra'ayoyi na daidaiton sinadarai:
1. Daidaito Mai Sauƙi: A yanayin daidaito, amsawar ba ta tsayawa ba, amma amsawar gaba da amsawar baya suna faruwa a daidai wannan lokacin.
2. Daidaito Mai Daidaito (K): Ana amfani da shi don nuna girman da amsawar ta kai ga daidaito. Tsarin gabaɗaya na daidaitaccen daidaito shine:
\[ K = \frac{{[samfuri]}}{[mai amsawa]} \]
3. Dokar Aikin Mass: Ana bayyana yawan kowane abu a cikin wani abu a cikin wani abu ta hanyar amfani da siffa mai faɗi bisa ga ma'aunin sinadarai.
Tambayoyi da Tattaunawa Samfura
Misali Tambaya ta 1
Tambaya:
Ana kiran lissafin amsawar daidaito kamar haka:
\[ N_2O_4 (g) \ kibayar hagu 2NO_2 (g) \]
A wani zafin jiki, yawan daidaiton \(N_2O_4 \) shine 0.10 M kuma \(NO_2 \) shine 0.20 M. Lissafa ƙimar daidaiton daidaito, \(K_c \), don amsawar.
Tattaunawa:
Daidaiton ma'aunin daidaito \( K_c \) shine:
\[ K_c = \frac{{[NO_2]^2}}{[N_2O_4]} \]
Sanya ƙimar maida hankali a cikin lissafin:
\[ K_c = \frac{{(0.20)^2}}{0.10} \]
\[ K_c = \frac{{0.04}}{0.10} = 0.40 \]
Don haka, ƙimar \( K_c \) don amsawar shine 0.40.
Misali Tambaya ta 2
Tambaya:
A cikin akwati mai rufewa, iskar gas ta \(PCl_5 \) ta rikide zuwa \( PCl_3 \) da \( Cl_2 \) bisa ga lissafin:
\[ PCl_5 (g) \leftrightarrow PCl_3 (g) + Cl_2 (g) \]
Idan daidaiton daidaito, \( K_c \), a wani zafin jiki na musamman shine 0.200 kuma a daidaiton ...
Tattaunawa:
A ce yawan \( PCl_3 \) da \( Cl_2 \) a ma'auni shine x M. Dangane da lissafin amsawa, yawan \( PCl_5 \) yana raguwa da x M kuma.
Saboda haka, ana iya rubuta lissafin daidaito kamar haka:
\[ K_c = \frac{{[PCl_3][Cl_2]}}{[PCl_5]} \]
Maye gurbin ƙimar \( K_c \) da kuma yawan \( PCl_5 \):
\[ 0.200 = \frac{{x^2}}{(1.00 – x)} \]
Magance lissafin quadratic:
\[ 0.200 = \frac{{x^2}}{(1.00 – x)} \]
\[ 0.200 (1.00 – x) = x^2 \]
\[ 0.200 – 0.200x = x^2 \]
\[ x^2 + 0.200x – 0.200 = 0 \]
Maganin wannan lissafin quadratic shine x = 0.332 ko x = -0.532 (maganin mara kyau ba shi da mahimmanci, tunda maida hankali ba zai iya zama mara kyau ba).
Saboda haka, yawan \(PCl_3 \) da \(Cl_2 \) a ma'auni shine 0.332 M.
Misali Tambaya ta 3
Tambaya:
A cikin maganin, ions na hydroxide (\( OH^- \)) na iya yin aiki tare da ions na ammonium (\( NH_4^+ \)) don samar da ruwa (\( H_2O \)) da ammonia (\( NH_3 \)). Daidaiton amsawar shine:
\[ NH_4^+ (aq) + OH^- (aq) \hagu-hagu H_2O (l) + NH_3 (aq) \]
Idan an saita ma'aunin daidaito (\( K_c \)) zuwa 1.8 x 10^5 a wani zafin jiki, kuma farkon yawan \( NH_4^+ \) da \( OH^- \) sune 0.10 M da 0.15 M, bi da bi, ƙididdige yawan \( NH_3 \) lokacin da aka isa daidaito.
Tattaunawa:
Rubuta lissafin daidaito:
\[ K_c = \ frac {{[NH_3]} {[NH_4^+] [OH^-]} \]
A ce x shine yawan sinadarin \(NH_3 \) da aka samar a daidaitacce, sannan yawan sinadarin \(NH_4^+ \) da \(OH^- \) suna raguwa da kowane x.
\[ K_c = \frac{{x}}{(0.10 – x)(0.15 – x)} \]
Maye gurbin ƙimar \( K_c \):
\[ sau 1.8 10^5 = \frac{{x}}{(0.10 – x)(0.15 – x)} \]
A ce x ƙarami ne sosai idan aka kwatanta da 0.10 da 0.15 kamar haka (0.10 – x \approx 0.10 \) da kuma (0.15 – x \approx 0.15 \):
\[ sau 1.8 10^5 = \frac{{x}}{(0.10)(0.15)} \]
\[ x = 1.8 \sau 10^5 \sau (0.10) \sau (0.15) \]
\[x = 2.7 \]
Saboda haka, ana kiyasta yawan \(NH_3 \) a ma'auni ya kai M2.7.
Kammalawa
Daga tattaunawar da ke sama, za a iya kammalawa cewa fahimtar ma'anar daidaiton sinadarai yana da mahimmanci don magance matsaloli daban-daban da suka shafi daidaito a cikin mafita. Ta amfani da dokar aikin taro da kuma daidaitaccen daidaito, za mu iya ƙididdige yawan nau'ikan halittu daban-daban a cikin amsawa lokacin da aka cimma daidaito. Wannan labarin ya tabo kaɗan ne kawai a kan misalai na asali. A aikace, lissafin daidaiton sinadarai na iya zama mafi rikitarwa, wanda ya haɗa da abubuwa kamar zafin jiki, matsin lamba, da aikin ion a cikin mafita.
