Misali na lokacin ƙarfi

Misalai 10 na Tambayoyin Lokacin Ƙarfi

1. Tsawon sandar AB mita 2 ne kuma girman ƙarfin F shine Newtons 10. Ƙayyade lokacin salo zuwa ga aya ta A da kuma alkiblar juyawar sandar AB!
Misalin lokacin ƙarfi 1Tattaunawa
Axis na juyawa yana nan a wurin A.

An san cewa:
Ƙarfi (F) = Newtons 10
Nisa AB (r)AB) = mita 2
Ƙarfin F yana samar da kusurwar 90o a kan sandar AB.
Hannun ƙarfi (l) = rAB ba 90o = (mita 2)(1) = mita 2
An tambaya: Lokacin ƙarfi game da ma'ana A da kuma alkiblar juyawar sandar AB

Amsa:
Lokacin ƙarfi:
τ = F l = (10 N)(2 m) = mita 20 na Newton
Lokacin ƙarfin yana da kyau saboda ƙarfin F yana sa sandar AB ta juya akasin agogo.

2. Tsawon sandar AB mita 2 ne kuma girman ƙarfin F shine Newtons 10. Kayyade lokacin ƙarfi game da wurin A da kuma alkiblar juyawar sandar AB!

Tattaunawa
Axis na juyawa shineMisalin lokacin ƙarfi 2yana nan a wurin A.

An san cewa:
Ƙarfi (F) = Newtons 10
Nisa AB (r)AB) = mita 2
Ƙarfin F yana samar da kusurwar 60o a kan sandar AB.
Hannun ƙarfi (l) = rAB ba 60o = (mita 2)(0,5√3) = √mita 3
An tambaya: Torque zuwa nuni A da kuma alkiblar juyawar sandar AB

Amsa:
Lokacin ƙarfi:
τ = F l = (10 N)(√3 m) = 10√3 Mita na Newton
Lokacin ƙarfin yana da kyau saboda ƙarfin F yana sa sandar AB ta juya akasin agogo.

3. Tsawon sandar AB mita 2 ne, girman ƙarfin F1 shine Newtons 10 kuma girman ƙarfin F2 shine Newtons 15. Kayyade lokacin ƙarfin da ya haifar a tsakiyar sandar da kuma alkiblar juyawar sandar AB!

Tattaunawa
Misalin lokacin ƙarfi 4Axis na juyawa yana tsakiyar sandar.
An san cewa:
Salo na 1 (F)1) = 10 Newton
Nisa F1 da kuma tsakiyar tushe (r)1) = mita 1
Salo na F1 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 1 (l)1) = r1 ba 90o = (mita 1)(1) = mita 1

Salo na 2 (F)2) = 15 Newton
Nisa F2 da kuma tsakiyar tushe (r)2) = mita 1
Salo na F2 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 2 (l)2) = r2 ba 90o = (mita 1)(1) = mita 1
An tambaya: Sakamakon lokacin ƙarfi a tsakiyar sandar da kuma alkiblar juyawar sandar AB
Amsa:
Lokacin ƙarfi 1:
τ1 = F1 l1 = (10 N)(1 m) = mita 10 na Newton
Lokacin ƙarfin yana da kyau saboda ƙarfin F yana sa sandar ta juya akasin agogo.

Lokacin ƙarfi 2:
τ2 = F2 l2 = (15 N)(1 m) = -15 Mita Newton
Lokacin ƙarfi yana da kyau saboda ƙarfin F2 yana sa sandar ta juya a hannun agogo.

Lokacin ƙarfi da ya biyo baya:
Στ = τ1 – τ2 = 10 – 15 = – 5 Mita na Newton
Lokacin ƙarfin da aka samu yana da kyau saboda ƙarfin da aka samu na F yana sa sandar AB ta juya a hannun agogo.

4. Tsawon sandar AB mita 2 ne, girman ƙarfin F shine1 shine 10 Newton da girman ƙarfin F2 shine 10 Newton. Kayyade lokacin ƙarfi da aka samu a tsakiyar sandar da kuma alkiblar juyawar sandar AB!
Misalin lokacin ƙarfi 6Tattaunawa
Axis na juyawa yana tsakiyar sandar.
An san cewa:
Salo na 1 (F)1) = 10 Newton
Nisa F1 da kuma tsakiyar tushe (r)1) = mita 1
Salo na F1 samar da kusurwar digiri 60o kan sanda AB
Salon hannu 1 (l)1) = r1 ba 60o = (mita 1)(0,5√3) = mita 0,5√3

Salo na 2 (F)2) = 10 Newton
Nisa F2 da kuma tsakiyar tushe (r)2) = mita 1
Salo na F2 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 2 (l)2) = r2 ba 90o = (mita 1)(1) = mita 1
An tambaya: Sakamakon lokacin ƙarfi a tsakiyar sandar da kuma alkiblar juyawar sandar AB
Amsa:
Lokacin ƙarfi 1:
τ1 = F1 l1 = (10 N)(0,5√3 m) = 5√3 = 8,7 Mita na Newton
Lokacin ƙarfin yana da kyau saboda ƙarfin F1 yana sa sandar ta juya akasin agogo.

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Lokacin ƙarfi 2:
τ2 = F2 l2 = (10 N)(1 m) = -10 Mita Newton
Lokacin ƙarfi yana da kyau saboda ƙarfin F2 yana sa sandar ta juya a hannun agogo.

Lokacin ƙarfi da ya biyo baya:
Στ = τ1 – τ2 = 8,7 – 10 = – 1,3 Mita na Newton
Lokacin ƙarfin da aka samu yana da kyau saboda ƙarfin da aka samu na F yana sa sandar AB ta juya a hannun agogo.

5. Tsawon sandar AB mita 10 ne, girman ƙarfin F shine1 shine 10 Newton, girman ƙarfin F2 shine 10 Newton da girman ƙarfin F3 shine Newtons 15. Nisa tsakanin aya ta A da aya ta C shine mita 7,5. Ƙarfin F2 yana tsakiyar sandar AB. Ka ƙayyade lokacin ƙarfin da aka samu a wurin C wanda yake mita 2,5 daga wurin B! Haka kuma ka ƙayyade alkiblar juyawar sandar AB.
Misalin lokacin ƙarfi 8Tattaunawa
Axis na juyawa yana nan a wurin C wanda yake mita 2,5 daga wurin B.
An san cewa:
Salo na 1 (F)1) = 10 Newton
Nisa F1 da kuma maki C (r)1) = mita 2,5
Salo na F1 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 1 (l)1) = r1 ba 90o = (mita 2,5)(1) = mita 2,5

Salo na 2 (F)2) = 10 Newton
Nisa F2 da kuma maki C (r)2) = mita 2,5
Salo na F2 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 2 (l)2) = r2 ba 90o = (mita 2,5)(1) = mita 2,5

Salo na 3 (F)3) = 15 Newton
Nisa F3 da kuma maki C (r)3) = mita 7,5
Salo na F3 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 3 (l)3) = r3 ba 90o = (mita 7,5)(1) = mita 7,5
An tambaya: Lokacin ƙarfi da aka samu game da wurin C da kuma alkiblar juyawar sandar AB.
Amsa:
Lokacin ƙarfi 1:
τ1 = F1 l1 = (10 N)(2,5 m) = mita 25 na Newton
Lokacin ƙarfi yana da kyau saboda ƙarfin F1 yana sa sandar ta juya akasin agogo.

Lokacin ƙarfi 2:
τ2 = F2 l2 = (10 N)(2,5 m) = mita 25 na Newton
Lokacin ƙarfi yana da kyau saboda ƙarfin F2 yana sa sandar ta juya akasin agogo.

Lokacin ƙarfi 3:
τ3 = F3 l3 = (15 N)(7,5 m) = -112,5 Mita Newton
Lokacin ƙarfi yana da kyau saboda ƙarfin F3 yana sa sandar ta juya a hannun agogo.

Lokacin ƙarfi da ya biyo baya:
Στ = τ1 + τ2 – τ3 = 25 + 25 – 112,5 = – 62,5 Mita na Newton
Lokacin ƙarfin da aka samu yana da kyau saboda ƙarfin da aka samu na F yana sa sandar AB ta juya a hannun agogo.

6. Tsawon sandar AB mita 10 ne, girman ƙarfin F shine1 shine 10 Newton, girman ƙarfin F2 shine 10 Newton da girman ƙarfin F3 shine Newtons 10. Kayyade lokacin ƙarfin da aka samu a wurin A wanda yake mita 5 daga wurin tasirin ƙarfi F.1! Haka kuma ƙayyade alkiblar juyawar sandar AB.
Tattaunawa
Misalin lokacin ƙarfi 11Axis na juyawa yana nan a wurin A.
An san cewa:
Salo na 1 (F)1) = 10 Newton
Nisa F1 da kuma maki A (r)1) = mita 5
Salo na F1 samar da kusurwar digiri 60o kan sanda AB
Salon hannu 1 (l)1) = r1 ba 60o = (mita 5)(0,5√3) = mita 2,5√3

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Salo na 2 (F)2) = 10 Newton
Nisa F2 da kuma maki A (r)2) = 0
Salo na F2 samar da kusurwar digiri 90o kan sanda AB
Salon hannu 2 (l)2) = r2 ba 90o = (0)(1) = 0
Salo na 3 (F)3) = 10 Newton
Nisa F3 da kuma maki A (r)3) = mita 10
Salo na F3 samar da kusurwar digiri 30o kan sanda AB
Salon hannu 3 (l)3) = r3 ba 30o = (mita 10)(0,5) = mita 5
An tambaya: Lokacin ƙarfi da aka samu game da maki A da kuma alkiblar juyawar sandar AB.
Amsa:
Lokacin ƙarfi 1:
τ1 = F1 l1 = (10 N)(2,5√3 m) = 25√3 = 43,3 Mita na Newton
Lokacin ƙarfin yana da kyau saboda ƙarfin F1 yana sa sandar ta juya akasin agogo.

Lokacin ƙarfi 2:
τ2 = F2 l2 = (10 N)(0) = 0
Lokacin ƙarfi sifili ne saboda ƙarfin F2 yayi daidai da axis na juyawa

Lokacin ƙarfi 3:
τ3 = F3 l3 = (10 N)(5 m) = -50 Mita Newton
Lokacin ƙarfi yana da kyau saboda ƙarfin F3 yana sa sandar ta juya a hannun agogo.

Lokacin ƙarfi da ya biyo baya:
Στ = τ1 + τ2 – τ3 = 43,3 + 0 – 50 = – 6,7 Mita na Newton
Lokacin ƙarfin da aka samu yana da kyau saboda ƙarfin da aka samu na F yana sa sandar AB ta juya a hannun agogo.

7. Ƙarfi uku F1, F2, da kuma F3 yana aiki akan sandar kamar yadda aka nuna a cikin hoto mai zuwa. Idan aka yi watsi da nauyin sandar kuma tsawon sandar ya kai mita 4, to ƙimar lokacin ƙarfi game da axis na juyawa a wurin C shine…. (zunubi 53o = 0,8, cos 53o = 0,6, AB = BC = CD = DE = 1 mita)
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of Force (Moment of Force) 8a

A. 12 Nm
B. 8 Nm
C. 6 Nm
D. 2 Nm
E. Sifili

Tattaunawa
An san cewa:
Axis na juyawa yana a wurin C.
Salo na 1 (F)1) = 5 Newton
Nisa tsakanin wuraren aiki F1 tare da axis na juyawa (r)1) = mita 2
Salo na 2 (F)2) = 0,4 Newton
Nisa tsakanin wurin aiki F2 da kuma axis na juyawa (r)2) = mita 1
Salo na 3 (F)3) = 4,8 Newton
Nisa tsakanin wuraren aiki F3 tare da axis na juyawa (r)3) = mita 2
Tambaya: Darajar lokacin ƙarfi game da axis na juyawa a wurin C
Amsa:

Lokacin Ƙarfi na 1:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of Force (Moment of Force) 8bLokacin ƙarfi na 1 yana sa sandar ta juya akasin agogo don haka lokacin ƙarfi na 1 yana da alama mai kyau.
Lokacin Ƙarfi na 2:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of force (torque) 8cLokacin ƙarfi na 2 yana sa sandar ta juya zuwa ga juyawar agogo ta yadda lokacin ƙarfi na 2 zai sami alama mara kyau.
Lokacin Ƙarfi na 3:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of Force (Moment of Force) 8dLokacin ƙarfi na 3 yana sa sandar ta juya zuwa ga juyawar agogo ta yadda lokacin ƙarfi na 3 zai sami alama mara kyau.

Lokacin ƙarfi da ya biyo baya:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of Force (Moment of Force) 8eGirman lokacin ƙarfin shine mita 2 na Newton. Lokacin ƙarfi mara kyau yana nufin sandar tana juyawa akasin agogo.
Amsar da ta dace ita ce D.

8. Girman lokacin ƙarfin da aka samu a kan axis a wurin O ta hanyar ƙarfin da ke aiki a kan sandar idan aka yi watsi da nauyinsa shine….
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of force (torque) 8f

A. 7,5 Nm
B. 4 Nm
C. 3,5 Nm
D. 3 Nm
E. 2 Nm

Tattaunawa
An san cewa:
Axis na juyawa yana a wurin O.
Salo na 1 (F)1) = 6 Newton
Nisa tsakanin wuraren aiki F1 tare da axis na juyawa (r)1) = mita 1
Salo na 2 (F)2) = 6 Newton
Nisa tsakanin wurin aiki F2 da kuma axis na juyawa (r)2) = mita 2
Salo na 3 (F)3) = 4 Newton
Nisa tsakanin wuraren aiki F3 tare da axis na juyawa (r)3) = mita 2
Tambaya: Darajar lokacin ƙarfi game da axis na juyawa a wurin C
Amsa:
Lokacin Ƙarfi na 1:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare – Moment of force (torque) 8gLokacin ƙarfi na 1 yana sa sandar ta juya akasin agogo don haka lokacin ƙarfi na 1 yana da alama mai kyau.
Lokacin Ƙarfi na 2:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of force (torque) awanni 8Lokacin ƙarfi na 2 yana sa sandar ta juya akasin agogo don haka lokacin ƙarfi na 2 yana da alama mai kyau.
Lokacin Ƙarfi na 3:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of Force (Moment of Force) 8iLokacin ƙarfi na 3 yana sa sandar ta juya zuwa ga juyawar agogo ta yadda lokacin ƙarfi na 3 zai sami alama mara kyau.

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Lokacin ƙarfi da ya biyo baya:
Tattaunawa kan Jarrabawar Ƙasa ta 2014 don Ilimin Lissafi na Makarantar Sakandare - Moment of force (torque) 8jGirman lokacin ƙarfin shine mita 4 na Newton. Lokacin ƙarfi mai kyau yana nufin sandar tana juyawa akasin agogo.
Amsar da ta dace ita ce B.

9. Sanda tana da tsawon mita 8. Ƙarfi uku suna aiki a kan sandar, kamar yadda aka nuna a cikin hoton da ke ƙasa. Girman lokacin ƙarfin da ke sa sandar ta juya a tsakiyarta shine…
A. 10 N m
B. 20 N m
C. 30 N m
D. 40 N m
E. 50 N m

Tattaunawa:
Misalin Lokacin Ƙarfi - UnTsakiyar sandar tana tsakiya. Tsawon sandar yana da mita 8, don haka tsakiyar sandar tana da mita 4 daga ƙarshen sandar.
Lokacin Ƙarfi 1 = F1 l1 = (10 N)(4 m) = N40 m
Moment of Force 1 yana da ƙima mai kyau saboda Moment of Force 1 yana sa sandar ta juya akasin agogo.
Lokacin Ƙarfi 2 = F2 l2 = (10 N)(2 m) = – 20 N m
Moment of Force 2 yana da ƙimar rashin kyau saboda Moment of Force 2 yana sa sandar ta juya a cikin alkiblar agogo.
Lokacin Ƙarfi 3 = F3 l3 = (15 N)(2 m) = – 30 N m
Moment of Force 3 yana da ƙimar rashin kyau saboda Moment of Force 3 yana sa sandar ta juya a cikin alkiblar agogo.

Lokacin Ƙarfin da ya Samu = 40 N m – 20 N m – 30 N m = – 10 N m

Lokacin da ƙarfin ko ƙarfin da aka samu yana da ƙimar da ba ta dace ba, wannan yana nuna cewa alkiblar juyawar sandar tana juyawa ne a hannun agogo.

Amsar da ta dace ita ce A.

10. Ƙarfin F1 = 10 N, F2 = 15 N, F3 = 15 N da F4 = 10 N, yana aiki akan sandar ABCD kamar yadda aka nuna a cikin hoton. Tsawon sandar ABCD mita 20 ne. Idan aka yi watsi da nauyin sandar to ƙimar lokacin ƙarfi game da wurin D shine...
A. 15 Nm
B. 18 Nm
C. 35 Nm
D. 63 Nm
E. 68 Nm

Tambayoyin misalan karfin juyi - jarrabawar ƙasa - 2Tattaunawa:
Manufar wannan tambayar ita ce a nemo ƙimar lokacin ƙarfin da ya haifar wanda ke sa sandar ta juya, inda tsakiyar juyawar take a wurin D.
Lokacin Ƙarfi 1 = F1 l1 = (10 N)(15 m) = N150 m
Moment of Force 1 yana da ƙima mai kyau saboda Moment of Force 1 yana sa sandar ta juya akasin agogo.
Lokacin Ƙarfi 2 = F2 l2 = (15 N)(5 m) = -75 N m
Moment of Force 2 yana da ƙimar rashin kyau saboda Moment of Force 2 yana sa sandar ta juya a daidai alkiblar juyawar agogo.
Lokacin Ƙarfi 3 = F3 l3 = (15 N)(0 m) = N0 m

Lokacin Ƙarfi na 3 sifili ne saboda F3 yayi daidai da axis na juyawa.
Lokacin Ƙarfi 4 = F4 l4 = (10 N)(5 m) = N50 m
Moment of Force 4 yana da ƙima mai kyau saboda Moment of Force 4 yana sa sandar ta juya akasin agogo.

Lokacin Ƙarfin da ya Samu = 150 N m – 75 N m + 50 N m = 125 N m
Lokacin ƙarfi ko ƙarfin juyi da aka samu yana da ƙima mai kyau, saboda haka alkiblar juyawar sandar ta saba wa alkiblar juyawar hannun agogo.

 

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