Misalai 3 na dokar Gay-Lussac (ƙarin isochoric-constant)
1. Da farko, akwai iskar gas da dama da ke da matsin lamba P da zafin jiki T. Idan iskar gas ta fuskanci tsarin isochoric ta yadda matsin lambar ya ninka matsin lamba na asali sau 4, to zafin iskar gas din zai canza zuwa...
Tattaunawa
An sani :
Matsi na farko (P)1) = P
Matsi na ƙarshe (P)2) = 4P
Zafin farko (T)1) = T
An tambaya : zafin jiki na ƙarshe (T)2)
Jawab :
Hukum Gay-Lussac (tsarin girma na isochoric ko na dindindin) :
Zafin iskar gas yana canzawa zuwa sau 4 a zafin farko.
2. Iskar gas tana cikin wani akwati da aka rufe a zafin farko na 27°C. Domin ninka matsin lamba, zafin ɗakin...
Tattaunawa
An sani :
Matsi na farko (P)1) = P
Matsi na ƙarshe (P)2) = 2P
Zafin farko (T)1) = 27oC + 273 = 300 K
An tambaya : zafin jiki na ƙarshe (T)2)
Jawab :
Zafin ɗakin shine 327oC.
3. Tayoyin babura suna da matsin lamba na 2 atm a zafin jiki na 27oC. Bayan an hau babur ɗin, zafin da ke cikin tayar zai canza zuwa 47oC. Idan aka yi watsi da faɗaɗawa to matsin iska a cikin tayar zai canza zuwa...
Tattaunawa
Matsar da ma'aunin matsin lamba zuwa matsi mai cikakken ƙarfi. Matsi mai cikakken ƙarfi = matsi mai ma'auni + matsi mai yanayi
An sani :
Matsi a yanayi = 1 atm = 1 x 105 Pascal
Matsin aunawa na farko = 2 atm = 2 x 105 Pascal
Matsi na farko (P)1) = 1 atm + 2 atm = 3 atm = 3 x 105 Pascal
Zafin farko (T)1) = 27oC + 273 = 300 K
Zafin ƙarshe (T)1) = 47oC + 273 = 320 K
An tambaya : Matsi na ƙarshe na ma'aunin
Jawab :
Matsi na ƙarshe = matsin lamba na ƙarshe - matsin lamba na yanayi
Matsin lamba na ƙarshe = 3,2 atm – 1 atm
Matsin lamba na ƙarshe = 2,2 atm
