Misali na tambayoyin Fluid Dynamics

Misalan Tambayoyi 24 na Tasirin Ruwan Ruwa

Ka'idar Torriceli

1. Babban baho cike da ruwa da famfo kamar yadda aka nuna a hoton. Idan g = 10 ms ^-2 , to saurin fesa ruwa daga famfo shine...

A. 3 ms^-1  

B. 8 ms ^-1

C. 9 ms ^-1

D. 30 ms ^-1

E. 900 ms ^-1

Tattaunawa

An sani cewa :

Tsawo (h) = 85 cm – 40 cm = 45 cm = mita 0,45

Saurin gudu saboda nauyi (g) = 10 m/s ²

Tambaya : Saurin fesa ruwa daga famfo (v)

Amsa :

Ka'idar Torricelli ta bayyana cewa saurin ruwa da ke fesawa ta cikin rami a nesa da saman ruwa iri ɗaya ne da saurin ruwa da ke faɗuwa daga tsayin h.

Ana ƙididdige saurin fesa ruwa ta amfani da dabarar motsi na faɗuwa kyauta v _t ² = 2 gh

v _t ² = 2 gh = 2(10)(0,45) = 9

v _t = √9 = 3 m/s

Amsar da ta dace ita ce A.

2. Tankin ruwa yana ɗauke da rami a bango (duba hoto). Saurin ruwan yayin da yake fita daga ramin shine… (g = 10 ms ^-2 )

A. 12 ms^-1

B. 10 ms ^-1

C. 6 ms ^-1

D. 5 ms ^-1

E. 2 ms ^-1

Tattaunawa

An sani cewa :

Tsawo (h) = 1,5 m – 0,25 m = 1,25 mita

Saurin gudu saboda nauyi (g) = 10 m/s ²

Tambaya : Saurin ruwan idan ya fito daga ramin (v)

Amsa :

v _t ² = 2 gh = 2(10)(1,25) = 25

v _t = √25 = 5 m/s

Amsar da ta dace ita ce D.

3. Wani ma'ajiyar ruwa yana ɗauke da ruwa mai tsayin mita 1 (g = 10 ms ^-2 ) kuma akwai ramin ɓuya a bango (duba hoto). Saurin ruwan da ke fitowa daga ramin shine...

A. 1 ms^-1

B. 2 ms ^-1

C. 4 ms ^-1

D. 8 ms ^-1

E. 10 ms ^-1

Tattaunawa

An sani cewa :

Tsawo (h) = 1 m – 0,20 m = 0,8 mita

Saurin gudu saboda nauyi (g) = 10 m/s ²

Tambaya : Saurin ruwan idan ya fito daga ramin (v)

Amsa :

v _t ² = 2 gh = 2(10)(0,8) = 16

v _t = √16 = 4 m/s

Amsar da ta dace ita ce D.

4. An cika silinda da ruwa mai kyau. Wani ƙaramin rami (ƙaramin fiye da girman silinda) yana kan bangonsa, 20 cm daga sama, wanda ke ba da damar ruwan ya fita (kamar yadda aka nuna a cikin hoton). Menene saurin jirgin ruwa daga ƙaramin ramin?

A. 1,0 ms^-1

B. 2,0 ms ^–1

C. 3,0 ms ^–1

D. 5,0 ms ^–1

E. 5,5 ms ^–1

Tattaunawa

An san cewa:

Nisa daga ramin (h) = 20 cm = mita 0,2

Saurin gudu saboda nauyi (g) = 10 m/s ²

Tambaya: Saurin jirgin ruwa daga ƙaramin ramin nawa yake tafiya?

Amsa:

Ka'idar Torriceli ta bayyana cewa saurin fitar ruwa daga rami iri ɗaya ne da saurin faɗuwa daga tsayi h. A lissafi:

Amsar da ta dace ita ce B.

5. Tankin ruwa yana da babban sashe, tare da ƙaramin rami a A. Saurin fitar ruwan daga ramin A shine...

A. daidai gwargwado kai tsaye ga h

B. daidai yake da h ₁

C. daidai yake da √h

D. daidai yake da _h2

E. yana daidai gwargwado kai tsaye da (h ₁ – h ₂ )

Tattaunawa

Daidaiton Bernoulli:

P ₁ + 1/2 ρ v ₁ ² + ρ gh ₁ = P ₂ + 1/2 ρ v ₂ ² + ρ gh ₂

Bayani: P ₁ = matsin lamba 1, v ₁ = gudu 1, h ₁ = tsayi 1, ρ = yawa, g = hanzarin nauyi, P ₂ = matsin lamba 2, v ₂ = gudu 2, h ₂ = tsayi 2

Ana iya amfani da wannan lissafin don ƙididdige saurin fitar da ruwa daga ramin A. Idan saman tankin a buɗe yake, to P ₁ = matsin iska a saman saman ruwa. Idan akwai ƙaramin rami a wurin A, to P ₂ = matsin iska a wajen ƙaramin ramin. Matsin iska a ko'ina kusa da tankin dole ne ya kasance iri ɗaya, don haka P ₁ = P _2. Don haka, za a iya kawar da P ₁ da P ₂ daga lissafin Bernoulli.

1/2 ρ v ₁ ² + ρ gh ₁ = 1/2 ρ v ₂ ² + ρ gh ₂

Ramin da ke cikin A ƙarami ne don haka ruwan da ke fitowa ta cikin ramin yana da babban gudu, yayin da saman baho yake da girma don haka saurin raguwar matakin ruwan ƙarami ne. Don haka ƙimar v ₂ ta kusanci sifili don haka an cire 1/2 ρ v ₂ ² daga lissafin.

Bayani: v ₁ = saurin ruwa da ke fitowa daga ramin A, g = hanzari saboda nauyi = 9,8 m/s ² , h = nisa tsakanin ramin A da saman ruwa.

Amsar da ta dace ita ce C.

6. Bututu yana ɗauke da ruwa mai kyau. A bango akwai ƙananan ramuka guda biyu (ƙanana fiye da ɓangaren bututun) don ruwan ya fito (kamar yadda aka gani a hoton). Rabon da ke tsakanin x ₁ da x ₂ shine…..

A. 2: 3

B. 3: 5

C. 2: 5

D. 4: 5

E. 3: 4

Tattaunawa

Da farko, a ƙididdige saurin da ruwan ke fita daga bututun. Ka'idar Torriceli ta bayyana cewa saurin da ruwan ke fita daga bututun yayi daidai da saurin da ruwan ke fitarwa idan ya faɗi daga tsayi inda h ₁ = 20 cm = mita 0,2 da h ₂ = 50 cm = mita 0,5.

Amsar da ta dace ita ce D.

Daidaito Mai Ci gaba

7. Ruwa yana gudana daga bututun A zuwa bututun B kuma yana ci gaba da zuwa bututun C. Rabon yankin giciye na A zuwa yankin giciye na C shine 8:3. Idan yawan kwararar ruwa a cikin bututun A yayi daidai da v, to yawan kwararar ruwa a cikin bututun C shine...

A. 3/8 v

B. V

C. 8/3 v

D. v 3

E. 8 v

Tattaunawa

An san cewa:

Yankin giciye A (A _A ) = 8

Yankin giciye C (A _C ) = 3

Yawan kwarara a cikin bututun A (v _A ) = v

Tambaya: Yawan kwararar ruwa a cikin bututu C (v _C )

Amsa:

Tsarin lissafin ci gaba:

A _A v _A = A _C v _C

8 v = 3 v _C

v _C = 8/3 v

Amsar da ta dace ita ce C.

8. Bututu mai diamita na santimita 12 yana raguwa a gefe ɗaya zuwa diamita na santimita 8. Idan saurin kwarara a cikin babban ɓangaren bututun ya kai santimita 10/s, to saurin kwarara a ƙaramin ƙarshen shine…..

A. 22,5 cm/s

B. 4,4 cm/s

C. 2,25 cm/s

D. 0,44 cm/s

E. 0,225 cm/s

Tattaunawa

An san cewa:

Diamita 1 (d ₁ ) = 12 cm, radius 1 (r ₁ ) = 6 cm

Diamita 2 (d ₂ ) = 8 cm, radius 2 (r ₂ ) = 4 cm

Gudun ruwa 1 (v ₁ ) = 10 cm/s

Ana so: yawan kwarara 2 ( _v2 )

Amsa:

Wuri mai giciye 1 (A ₁ ) = π r ² = π 6 ² = 36π cm ²

Wuri mai giciye 2 (A ₂ ) = π r ² = π 4 ² = 16π cm ²

Daidaiton ci gaba da ruwa:

A ₁ v ₁ = A ₂ v ₂

(36π)(10) = (16π) v ₂

(36)(10) = (16) v ₂

360 = (16) v ₂

v ₂ = 360/16

v ₂ = 22,5 cm/s

Amsar da ta dace ita ce A.

9. Ruwa yana ratsawa ta cikin bututu kamar yadda aka nuna a cikin hoton da ke ƙasa. Idan yankin giciye A1 ₌ 8 cm2 ^, A2 ₌ 2 cm2 ^{da kuma} saurin ruwa v2 ₌ 2 m/s to girman v1 _shine …

A. 0,5 ms^-1

B. 1,0 ms ^-1

C. 1,5 ms ^-1

D. 2,0 ms ^-1

E. 2,5 ms ^-1

Tattaunawa

An sani cewa :

Yankin giciye 1 (A ₁ ) = 8 cm ²

Yankin giciye 2 (A ₂ ) = 2 cm ²

Saurin ruwa a sashen giciye na 2 (v ₂ ) = 2 m/s

Ana so : saurin ruwa a sashe na 1 (v ₁ )

Amsa :

Daidaiton ci gaba da ruwa :

A ₁ v ₁ = A ₂ v ₂

8 v ₁ = (2)(2)

8 v ₁ = 4

v ₁ = 4/8 = 0,5 m/s

Amsar da ta dace ita ce A.

10. Kalli hoton! Idan diamita na babban ɓangaren giciye ya ninka diamita na ƙaramin ɓangaren giciye, saurin kwararar ruwa a cikin ƙaramin bututu shine ....

A. 01 ms^-1

B. 04 ms ⁻¹

C. 08 ms ⁻¹

D. 16 ms ⁻¹

E. 20 ms ⁻¹

Tattaunawa

An sani cewa :

Babban diamita na giciye (d ₁ ) = 2

Radius na babban giciye-sashe (r ₁ ) = ½ d ₁ = ½ (2) = 1

Babban yanki na giciye ( A ₁ ) = π r ₁ ² = π (1) ² = π (1) = π

Ƙaramin diamita na giciye (d ₂ ) = 1

Ƙaramin radius na giciye (r2 ₎ = ½ d ₂ = ½ (1) = ½

Ƙananan yanki na giciye ( A ₂ ) = π r ₂ ² = π (1/2) ² = π (1/4) = ¼ π

Gudun kwararar ruwa a babban sashe ( v ₁ ) = 4 m/s

Tambaya : saurin kwararar ruwa a ƙaramin sashe ( v ₂ )

Amsa :

Daidaiton ci gaba da ruwa :

A ₁ v ₁ = A ₂ v ₂

π 4 = ¼ π (v ₂ )

4 = ¼ (v ₂ )

v ₂ = 8 m/s

Amsar da ta dace ita ce C.

Ka'idar Bernoulli da Daidaito

11. Bayanin da ke ƙasa ya shafi ƙarfin ɗagawa a cikin jirgin sama, wato...

A. Matsin iska da ke sama da fikafikin ya fi matsin iska da ke ƙarƙashin fikafikin girma.

B. Matsin iska a ƙarƙashin fikafikan ba ya shafar ɗaga jirgin.

C. Gudun iska da ke sama da fikafikan ya fi saurin iska da ke ƙarƙashin fikafikan girma.

D. Saurin kwararar iska a sama da fikafikan ya fi ƙanƙanta fiye da saurin kwararar iska a ƙarƙashin fikafikan.

E. Saurin kwararar iska ba ya shafar ɗaga jirgin.

Tattaunawa

Tsarin matsi: P = F / A, inda P = matsin lamba, F = ƙarfi, A = yankin saman.

Bisa ga wannan dabara, matsin lamba yana daidai gwargwado kai tsaye da ƙarfi. Don haka idan matsin lamba na iska ya fi girma, ƙarfin tura iska shi ma zai fi girma. Ƙarfi shine abin da ke sa abubuwa su motsa, ba matsin lamba ba.

Ka'idar Bernoulli ta bayyana cewa idan saurin iska ya yi yawa to matsin ya yi ƙasa, idan kuma saurin iska ya yi ƙasa to matsin ya yi yawa.

Domin jirgin sama ya tashi, dole ne tura iskar da ke ƙarƙashin fikafikan ta fi girma. Tura ta fi girma idan matsin iskar da ke ƙarƙashin fikafikan ya fi girma. Matsin iskar da ke ƙarƙashin fikafikan ya fi girma idan saurin iskar da ke ƙarƙashin fikafikan ya yi ƙasa.

Amsar da ta dace ita ce C.

12. Kula da waɗannan maganganun!

(1) ɗaga ƙarfi a kan jirgin sama

(2) famfon ruwa

(3) feshin sauro

(4) balan-balan masu zafi na iya tashi

Bayanin da ke sama wanda ƙa'idar aikinsa ta dogara ne akan dokar Bernoulli shine...

A. (1) da (2)

B. (1) da (3)

C. (2) da (4)

D. (1), (2), da (4)

E. (1), (3), da (4)

Tattaunawa

Kalamai waɗanda ƙa'idodin aikinsu suka dogara da dokar Bernoulli sune (1) ɗagawa a kan jiragen sama da (3) feshin sauro. (2) Famfon ruwa na Hydraulic suna aiki bisa ƙa'idar dokar Pascal. (4) Balan-balan na iska mai zafi na iya tashi bisa ƙa'idar dokar Archimedes (flotation).

Amsar da ta dace ita ce B.

13. A cikin hoton, ana tura ruwa da na'urar matsa lamba ta 120 kPa zuwa cikin bututun ƙasa (1) kuma yana gudana sama da gudun 1 ms ^-1 (g = 10 ms ^-2 kuma yawan ruwa shine 1000 kg.m ^-3 ). Matsin ruwa a cikin bututun sama (II) shine….

A. 52,5 kPa

B. 67,5 kPa

C. 80,0 kPa

D. 92,5 kPa

E. 107,5 kPa

Tattaunawa

An san cewa:

Radius na babban bututu (r ₁ ) = 12 cm

Radius na ƙaramin bututu (r2 ₎ = 6 cm

Matsin ruwa a cikin babban bututu (p1 ₎ = 120 kPa = 120.000 Pascal

Gudun ruwa a cikin babban bututu (v ₁ ) = 1 ms ^-1

Tsawon babban bututu (h ₁ ) = 0 m

Tsawon ƙaramin bututu (h ₂ ) = 2 m

Saurin gudu saboda nauyi (g) = 10 ms ^-2

Yawan ruwa = 1000 kg.m ^-3

Tambaya: Matsin ruwa a cikin bututu 2 (shafi _{na 2} )

Amsa:

Ana ƙididdige saurin ruwa a cikin bututun 2 ta amfani da Lissafin Ci gaba:

A ₁ v ₁ = A ₂ v ₂

(π r ₁ ² )(v ₁ ) = (π r ₂ ² )(v ₂ )

(r ₁ ² ) (v ₁ ) = (r ₂ ² ) (v ₂ )

(r ₁ ² ) (v ₁ ) = (r ₂ ² ) (v ₂ )

(12 ² )(1 m/s) = (6 ² )(v ₂ )

144 = 36 v ₂

v ₂ = 144 / 36

v ₂ = 4 m/s

Ana ƙididdige matsin lamba na ruwa a cikin bututun 2 ta amfani da lissafin Bernoulli:

14. Bayanin da ke ƙasa game da ƙarfin ɗagawa a cikin jirgin sama daidai ne...

A. Matsin iska da ke sama da fikafikin ya fi matsin iska da ke ƙarƙashin fikafikin girma.

B. Matsin iska a ƙarƙashin fikafikan ba ya shafar ɗaga jirgin.

C. Gudun iska da ke sama da fikafikan ya fi saurin iska da ke ƙarƙashin fikafikan girma.

D. Saurin kwararar iska a sama da fikafikan ya fi ƙanƙanta fiye da saurin kwararar iska a ƙarƙashin fikafikan.

E. Saurin kwararar iska ba ya shafar ɗaga jirgin.

Tattaunawa

Kwatanta tattaunawar tambayar da ta gabata.

Amsar da ta dace ita ce C.

15. An tsara fikafikan jirgin sama don samar da matsakaicin ɗagawa sama, kamar yadda aka nuna a cikin hoton. Idan v shine saurin iskar da P ke fitarwa kuma P shine matsin iska, to bisa ga ƙa'idar Bernoulli, an yi ƙirar ta yadda...

A. v_A > v_B don haka P_A > P_B

B. v _A > v _B don haka P _A < P _B

C. v _A < v _B don haka P _A < P _B

D. v _A < v _B don haka P _A > P _B

E. v _A > v _B don haka P _A = P _B

Tattaunawa

Domin fikafikin jirgin sama ya samu ɗagawa sama, dole ne tura iska a ƙasan fikafikin ya fi ƙarfin tura saman fikafikin.

Ƙarfin tura da ke ƙarƙashin fikafikan ya fi girma idan matsin iska da ke ƙarƙashin fikafikan ya fi girma.

Ka'idar Bernoulli ta bayyana cewa matsin lamba a ƙarƙashin fikafikan yana da girma idan saurin iska a ƙarƙashin fikafikan ya yi ƙasa.

Don haka v _A > v _B don haka P _A < P _B

Amsar da ta dace ita ce B.

16. Kula da wannan bayanin!

(1) na'urar auna iska

(2) feshin sauro

(3) barometer

(4) ma'aunin zafi da sanyi

Sanarwar da ta shafi aiwatar da dokar Bernoulli ita ce...

A. (1) da (2)

B. (1) da (3)

C. (1) da (4)

D. (2) da (3)

E. (2) da (4)

Tattaunawa

Kalamai waɗanda ƙa'idodin aikinsu suka dogara da dokar Bernoulli sune (1) na'urar venturimeter da (2) na'urar fesa sauro. (3) barometer wanda ƙa'idar aikinsa ta dogara ne akan matsin lamba na hydrostatic (4) na'urar auna mercury ko barasa wadda ƙa'idar aikinta ta dogara ne akan faɗaɗawa.

Amsar da ta dace ita ce A.

17. Kula da wannan bayanin!

(1) famfon ruwa

(2) kaburbura

(3) na'urar auna iska

(4) ma'aunin zafi da sanyi

Kayan aikin da ƙa'idar aikinsu ta dogara ne akan dokar Bernoulli sune...

A. (1) da (2)

B. (1) da (3)

C. (1) da (4)

D. (2) da (3)

E. (2) da (4)

Tattaunawa

Kalamai waɗanda ƙa'idodin aikinsu suka dogara da dokar Bernoulli sune (2) carburetors da (3) venturimeters. (1) famfunan hydraulic waɗanda ƙa'idodin aikinsu suka dogara da matsin lamba na hydrostatic, dokar Pascal. (4) ma'aunin zafi na mercury ko barasa waɗanda ƙa'idodin aikinsu suka dogara da faɗaɗawa.

Amsar da ta dace ita ce D.

18. Kalli hoton da ke ƙasa!

Matsayin babban bututun yana da mita 5 sama da ƙasa kuma ƙaramin bututun yana da mita 1 sama da ƙasa. Gudun ruwa a cikin babban bututun shine 36 km.h ^-1 tare da matsin lamba na 9,1 x 10 ⁵ Pa, yayin da matsin lamba a cikin ƙaramin bututun shine 2.10 ⁵ Pa, to saurin ruwa a cikin ƙaramin bututu shine…. (yawan ruwa = 10 ³ kg.m ^-3 )

A. 10 ms^-1

B. 20 ms ^-1

C. 30 ms ^-1

D. 40 ms ^-1

E. 50 ms ^-1

Tattaunawa

An san cewa:

Matsin ruwa a cikin babban bututu (p1 ₎ = 9,1 x 10 ⁵ Pascal = 910.000 Pascal

Matsin ruwa a cikin ƙaramin bututu (p ₂ ) = 2 x 10 ⁵ Pascal = 200.000 Pascal

Gudun ruwa a cikin babban bututu (v ₁ ) = 36 km/awa = 36(1000)/(3600) = 36000/3600 = 10 m/s

Tsawon babban bututu (h ₁ ) = mita -4

Tsawon ƙaramin bututu (h ₂ ) = mita 0

Saurin gudu saboda nauyi (g) = 10 ms ^-2

Yawan ruwa = 1000 kg.m ^-3

Tambaya: Gudun ruwa a cikin ƙaramin bututu (v ₂ )

Amsa:

Ana ƙididdige saurin ruwa a cikin ƙaramin bututu (v ₂ ) ta amfani da lissafin Bernoulli:

Amsar da ta dace ita ce D.

19. An haɗa bututu mai radius na 15 cm zuwa wani bututu mai radius na 5 cm. Dukansu suna cikin matsayi a kwance. Idan yawan kwararar ruwa a cikin babban bututun shine 1 ms ^-1 a matsin lamba na 10 ⁵ N m ^-2 , to matsin lamba a cikin ƙaramin bututun (yawan ruwa 1 g cm ^-3 ) shine ...

A. 10.000 N m ^-2

B. 15.000 N m ^-2

C. 30.000 N m ^-2

D. 60.000 N m ^-2

E. 90.000 N m ^-2

Tattaunawa

An san cewa:

Radius na babban bututu (r ₁ ) = 15 cm = 0,15 m

Radius na ƙaramin bututu (r2 ₎ = 5 cm = 0,05 m

Matsin ruwa a cikin babban bututu (p1 ₎ = 10 ⁵ N m ^-2 = 100.000 N m ^-2

Gudun ruwa a cikin babban bututu (v ₁ ) = 1 ms ^-1

Saurin gudu saboda nauyi (g) = 10 ms ^-2

Yawan ruwa = 1 gr cm ^-3 = 1000 kg m ^-3

Dukansu bututun suna cikin matsayi na kwance don haka bambancin tsayin bututu (Δh) = 0.

Tambaya: Matsi a cikin ƙaramin bututu (shafi _{na 2} )

Amsa:

Ana ƙididdige saurin ruwa a cikin bututun 2 ta amfani da Lissafin Ci gaba:

A ₁ v ₁ = A ₂ v ₂

(π r ₁ ² )(v ₁ ) = (π r ₂ ² )(v ₂ )

(r ₁ ² ) (v ₁ ) = (r ₂ ² ) (v ₂ )

(0,15 ² )(1 m/s) = (0,05 ² )(v ₂ )

0,0225 = 0,0025 v ₂

v ₂ = 0,0225 / 0,0025

v ₂ = 9 m/s

Ana ƙididdige matsin lamba a cikin ƙaramin bututu (p ₂ ) ta amfani da lissafin Bernoulli:

Amsar da ta dace ita ce D.

Ka'idar Bernoulli

20. Kalli hoton feshi mai maganin sauro a cikin hoton da ke ƙasa! P yana wakiltar matsin lamba yayin da v yana wakiltar yawan kwararar ruwan maganin sauro. Domin fitar da ruwan maganin sauro, kuna buƙatar...

A. v_A = v_B kuma P_A =P_B

B. v _A > v _B da P _A > P _B

C. v _A > v _B da P _A < P _B

D. v _A < v _B da P _A > P _B

E. v _A < v _B da P _A < P _B

Tattaunawa

v _A > v _B

p _A < p _B

Amsar da ta dace ita ce C.

21. An tsara fikafikan jirgin sama don samun matsakaicin ɗagawa sama, kamar yadda aka nuna a cikin hoton. Idan v shine saurin iskar da P ke fitarwa kuma P shine matsin iska, to bisa ga ƙa'idar Bernoulli an yi ƙirar ta yadda...

A. v_A > v_B don haka P_A > P_B

B. v _A > v _B don haka P _A < P _B

C. v _A < v _B don haka P _A < P _B

D. v _A < v _B don haka P _A > P _B

E. v _A > v _B don haka P _A = P _B

Tattaunawa

Domin fikafikin jirgin sama ya samu ɗagawa sama, dole ne tura iska a ƙasan fikafikin ya fi ƙarfin tura saman fikafikin.

Tura ƙasan fikafikan ya fi girma idan matsin iska a ƙasan fikafikan ya fi girma. P = F/A, inda matsin lamba na P ya yi daidai da F kai tsaye. Girman matsin lamba, ƙarfin ya fi girma.

Ka'idar Bernoulli ta bayyana cewa matsin lamba a ƙarƙashin fikafikan yana da girma idan saurin iska a ƙarƙashin fikafikan ya yi ƙasa.

Don haka v _A > v _B don haka P _A < P _B

Amsar da ta dace ita ce B.

Torriceli

22. An cika tankin ruwa mai tsawon santimita 100 gaba ɗaya da ruwa. An sanya ramin Q a saman ƙasa da santimita 10. Nisa tsakanin bututun ruwa (x) da ke kwance shine…

A. 0,2 m

B. 0,3 m

C. mita 0,6

D. 0,9 m

E. 1,0 m

Tattaunawa

An san cewa:

Nisa daga ramin da ke saman ruwa (h) = 100 cm – 10 cm = 90 cm = mita 0,9

Saurin gudu saboda nauyi (g) = 10 m/s ²

Tambaya: Nisa tsakanin jirgin ruwa na kwance (x)

Amsa:

Gudun ruwan da ke fitowa daga ramin

Ka'idar Torriceli ta bayyana cewa saurin jirgin ruwa da ke fitowa daga ramin iri ɗaya ne da saurin ruwan da ke faɗuwa daga tsayin h. A lissafi:

Bayani: v = gudu, g = hanzarin nauyi, h = nisan ramin daga saman ruwa

Saurin jirgin ruwa da ke fitowa daga ramin:

Lokacin da ruwa zai isa saman ƙasa

Motsin ruwa daga ramin har sai ya isa ƙasa shine motsin parabolic, inda hanyar take kamar yadda aka nuna a hoton da ke gefe. Ana ɗaukar motsin parabolic a matsayin nau'ikan motsi guda biyu, wato motsi a tsaye da kwance. Ana nazarin motsi a kwance kamar haka motsi na layi ɗaya kuma ana nazarin motsin alkiblar tsaye a wannan yanayin kamar yadda motsi na faɗuwa kyauta.

Da farko, ƙididdige tazarar lokacin da ruwan yake cikin iska ta amfani da dabarar faɗuwar 'free fall'.

An san cewa:

Tsawon rami (y) = 10 cm = mita 0,1

Saurin gudu saboda nauyi (g) = 10 m/s ²

An tambaya: tazara ta lokaci (t)

Amsa:

y = 1/2 gt ^{​​​​2}

0,1 = 1/2 (10) t ²

0,1 = 5 t ²

t ² = 0,1 / 5

t ² = 0,02

t = √0,02 daƙiƙa

Nisa a kwance (x)

An san cewa:

Saurin farko (vo _o = v _ox ) = 3 √2 m/s

Tazarar lokaci (t) na ruwa a cikin iska = √0,02 daƙiƙa

Tambaya: Nisa a kwance (x)

Amsa:

v = x / t

x = vt = (3 √2) ( √0,02) = (3)(1,41)(0,14) = 0,59 = mita 0,6

Amsar da ta dace ita ce C.

23. Kalli hoton da ke ƙasa!

Tanki yana ɗauke da ruwa har tsawon mita 1. A wurin P a bangon tanki akwai ƙaramin rami, don haka saurin fitar ruwan shine… (g = 10 ms ^-2 )

A. 5 ms^-1

B. 4 ms ^-1

C. 2,5 ms ^-1

D. 2 ms ^-1

E. 1,5 ms ^-1

Tattaunawa

An san cewa:

Nisa daga ramin da ke saman ruwa (h) = 100 cm – 80 cm = 20 cm = mita 0,2

Saurin gudu saboda nauyi (g) = 10 m/s ²

Tambaya: Gudun ruwa yana fitowa (v)

Amsa:

Saurin jirgin ruwa da ke fitowa daga ramin:

Amsar da ta dace ita ce D.

Na'urar auna iska (venturimeter)

24. Babban ɓangaren bututun venturimeter yana da yanki mai faɗi A₁ = 6 cm ba² kuma ƙaramin sashin bututun yana da yankin giciye-sashe A₂ = 5 cm ba²Gudun ruwa da ke shiga bututun venturimeter shine... h = 20 cm, g = 10 m/s².
A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s
E. 6 m/s
Tattaunawa:

Amsar da ta dace ita ce B.

 

Tushen tambaya:

Tambayoyin Nazarin Fizik na Ƙasa ga Makarantar Sakandare ta Babbar Sakandare/Makarantar Sakandare ta Sana'a