Misali na jirgin ruwa da aka haɗa da bututu mai siffar U

Misalan Jirgin Ruwa Mai Siffar U guda 4

1. An cika tasoshin biyu na A da B da ruwa mai yawa daban-daban, kamar yadda aka nuna a cikin hoton. Idan matsin lamba a ƙasan A yayi daidai da 4/5 matsa lamba a ginshiƙin B da kuma yawa ruwa A = 1000 kg m^-3 , to yawan ruwan da ke B shine...

A. 1250 kg m^-3

B. 2500 kg m^-3

C. 3000 kg m^-3

D. 4000 kg m^-3

E. 5000 kg m^-3

Tattaunawa

An san cewa:

Matsi a tushen A (P_A) = sau 4/5 na matsin lamba a gindin B (4/5) P_B)

Yawan ruwa A (ρ_A) = 1000 kg m^-3

An tambaya: Yawan ruwa B (ρ_B)

Amsa:

Tsarin matsin lamba na ruwa mai hydrostatic A shine P_A = ρ_A gh_A

RTsarin matsin lamba na ruwa B shine P_B = ρ_B gh_B

Matsi a tushen A = sau 4/5 na matsin lamba a gindin B:

Tsayin ruwan a A = tsayin ruwan a B don haka h_A kuma h_B an cire shi daga lissafin.

Hawan da aka samu sakamakon nauyi g iri ɗaya ne don haka an cire shi daga lissafin.

5 (ρ)_A) = 4 (ρ_B)

5 (1000) = 4 (ρ)_B)

ρ_B = 5000 / 4

ρ_B = 1250

Yawan ruwan a B shine 1250 kg m^-3

Amsar da ta dace ita ce A.

2. An cika bututun U dada ruwaye biyu daban-daban kamar yadda aka nuna a hoton da ke ƙasa! Idan yawan ρ₁ = 0,8 g.cm^-3, ρ₂ = 1 g.cm^-3, kuma h₁ = 10 cm, sannan tsayin h₂ shine….

A. 5 cm

B. 6 cm

C. 7 cm

D. 8 cm

E. 10 cm

Tattaunawa

An san cewa:

Yawan 1 = 0,8 g.cm^-3

Yawan 2 = 1 g.cm^-3

Tsawo 1 = 10 cm

An tambaya: Tsawo 2

Amsa:

Amsar da ta dace ita ce D.

3. Ana cika bututun U da ruwaye daban-daban guda biyu kamar yadda aka nuna a cikin hoton da ke ƙasa! Idan yawan p₁ = 0,8 g.cm^-3, p₂ = 1 g.cm^-3, kuma h₁ = 10 cm, sannan tsayin h₂ shine….

A. 5 cm
B. 6 cm
C. 7 cm
D. 8 cm
E. 10 cm

Tattaunawa
An san cewa:
Yawan 1 = 0,8 g.cm^-3
Yawan 2 = 1 g.cm^-3
Tsawo 1 = 10 cm
An tambaya: Tsawo 2
Amsa:
Amsar da ta dace ita ce D.

4. Kula da hoton da ke ƙasa:
Da farko ana cika bututun U da ruwa mai yawan kilogiram 1000.m^-3 Sannan, ana zuba man girki a cikin ɗaya daga cikin bututun don wurin da ya dace ya yi kama da hoton. Idan tsayin ginshiƙin mai ya kai cm 8 kuma ginshiƙin ruwa ya kai cm 5, yawan man girkin zai kasance….

A. 520 kg.m^-3
B. 525 kg.m^-3
C. 600 kg.m^-3
D. 625 kg.m^-3
E. 720 kg.m^-3

Tattaunawa
An san cewa:
Yawan ruwa = 1000 kg.m^-3
Tsawon ruwa = 5 cm
Tsawon man girki = 8 cm
Tambaya: Yawan man girki
Amsa:
Amsar da ta dace ita ce D.

Tushen tambaya:

Tambayoyin Nazarin Fizik na Ƙasa ga Makarantar Sakandare ta Babbar Sakandare/Makarantar Sakandare ta Sana'a