Momento de forza: problemas e solucións
1. If FR is the net force of F1, F2, e F3, what is the magnitude of force F2 and x?
Coñecido:
Net force (FR) = 40 N
Forza 1 (F1) = 10 N
Force (F3) = 20 N
Quería: The magnitude of force F2 and distance of x
Solución:
Find the magnitude of force F2 :
Force points to upward, signed negative and force points to downward, signed negative.
ΣF = 0
- FR +F1 +F2 - F3 = 0
– 40 + 10 + F2 - 20 = 0
– 30 + F2 - 20 = 0
– 50 + F2 = 0
F2 = 50 newtons.
Plus sign indicates that the direction of the force is upward.
Find x.
Choose A as the axis of rotation.
τ1 =F1 l1 = (10 N)(1 m) = 10 Nm
The torque 1 rotates beam counterclockwise so we assign positive sign to the torque 3.
τ2 =F2 x = (50)(x) = 50x Nm
The torque 1 rotates beam counterclockwise so we assign positive sign to the torque 3.
τ3 =F3 x = (20 N)(1.75 m) = -35 Nm
The torque 2 rotates beam clockwise so we assign negative sign to the torque 2.
The net of momento de forza :
Στ = 0
10 + 50x – 35 = 0
50x - 25 = 0
50x = 25
x = 25/50
x = 0.5 m
2. Forces of F1, F2, F3, e F4 acts on the rod of ABCD as shown in figure. If rod’s mass ignored, what is the magnitude of the moment of force, about point A.
The axis of rotation = points A.
Coñecido:
Forza F1 = 10 N, the lever arm l1 = 0 
Forza F2 = 4 N, the lever arm l2 = 2 metros
Forza F3 = 5 N, the lever arm l3 = 3 metros
Forza F4 = 10 N, the lever arm l4 = 6 metros
Buscase: the moment of force about point A
Solución:
Moment of force 1 (τ1) = F1 l1 = (10)(0) = 0
Moment of force 2 (τ2) = F2 l2 = (4)(2) = -8 Nm
Moment of force 3 (τ3) = F3 l3 = (5)(3) = 15 Nm
Moment of force 4 (τ4) = F4 l4 = (10)(6) = -60 Nm
If torque rotates rod counterclockwise then we assign positive sign.
If torque rotates rod clockwise then we assign negative sign.
A resultante do momento da forza:
τ = 0 – 8 Nm + 15 Nm – 60 Nm
τ = -68 Nm + 15 Nm
τ = -53 Nm
Minus sign indicates that the moment of force rotates rod clockwise.
3. Three forces act on a rod, FA =FC = 10 N e FB = 20 N, as shown in figure below. If distance of AB = BC = 20 cm, what is the moment of force about point C.
Coñecido:
The axis rotation at point C.
Distance between FA and the axis of rotation (rAC) = 40 cm = 0,4 meters
Distance between FB and the axis of rotation (rBC) = 20 cm = 0.2 meters
Distance between FC and the axis of rotation (rCC) = 0 centímetros
FA = 10 Newtons
FB = 20 Newtons
FC = 10 Newtons
Buscase: The resultant of the moment of force about point C.
Solución:
Moment of force A :
ΣτA = (FA)(rAC sen 90o) = (10 N)(0,4 m)(1) = -4 Nm
Minus sign indicates that the moment of force rotates rod clockwise.
Moment of force B :
ΣτB = (FB)(rBC sen 90o) = (20 N)(0,2 m)(1) = 4 Nm
Plus sign indicates that the moment of force rotates rod counterclockwise.
Moment of force C :
ΣτC = (FC)(rCC sen 90o) = (10 N)(0)(1) = 0
A resultante do momento da forza:
Στ = Στ1 + Στ2 + Στ3
Στ = -4 + 4 + 0
Στ = 0 Nm
4. Length of a rod is 50 cm. Three forces act on the rod, as shown in figure below. If the axis of rotation is point C, what is the net of the moment of force.
Coñecido:
The axis rotation at point C.
Distance between F1 and the axis of rotation is (r1) = 30 cm = 0,3 meters
Distance between F2 and the axis of rotation (r2) = 10 cm = 0,1 meters
Distance between F3 and the axis of rotation (r3) = 20 cm = 0,2 meters
F1 = 10 Newtons
F2 = 10 Newtons
F3 = 10 Newtons
Buscase: Resultant of moment of force about point C.
Solución:
Moment of force 1 :
Στ1 = (F1)(r1 sen 90o) = (10 N)(0,3 m)(1) = -3 Nm
Minus sign indicates that the moment of force rotates rod clockwise.
Moment of force 2 :
Στ2 = (F2)(r2 sen 90o) = (10 N)(0,1 m)(1) = 1 Nm
Plus sign indicates that the moment of force rotates rod counterclockwise.
Moment of force 3 :
Στ3 = (F3)(r3 sen 30o) = (10 N)(0,2 m)(0,5) = -1 Nm
Minus sign indicates that the moment of force rotates rod clockwise.
A resultante do momento da forza:
Στ = Στ1 + Στ2 + Στ3
Στ = -3 + 1 – 1
Στ = -3 Nm
Minus sign indicates that the resultant of the moment of force rotates rod clockwise.
5. Three forces F1, F2, e F3 act on a rod as shown in figure below. Length of rod is 4 meters. What is the moment of force about point C.
(sin 53o = 0.8, cos 53o = 0.6, AB = BC = CD = DE = 1 metro)
Coñecido:
The axis of rotation at point C. 
Forza 1 (F1) = 5 Newtons
A distancia entre a liña de acción de F1 co eixo de rotación (r1) = 2 metros
Forza 2 (F2) = 0.4 Newtons
A distancia entre a liña de acción de F2 co eixo de rotación (r2) = 1 metros
Forza 3 (F3) = 4.8 Newtons
The distance between the line of action of F3 with the axis of rotation (r3) = 2 metro
Quería: The moment of force about point C.
Solución:
Moment of force 1 :
τ1 =F1 r sen 53o = (5 N)(2 m)(0,8) = (10)(0,8) N = 8 N
Plus sign indicates that the moment of force rotates rod counterclockwise.
Moment of force 2 :
τ2 =F2 r sen 90o = (0,4 N)(1 m)(1) = -0,4 N
Minus sign indicates that the moment of force rotates rod clockwise.
Moment of force 3 :
τ3 =F3 r sen 90o = (4,8 N)(2 m)(1) = -9,6 N
Minus sign indicates that the moment of force rotates rod clockwise.
A resultante do momento da forza:
Στ = τ1 – τ2 – τ3 = 8 – 0,4 – 9,6 = 8 – 10 = 2 N.m
Plus sign indicates that the moment of force rotates rod counterclockwise.
6. What is the resultant of the moment of force about the axis of rotation at point O by forces acts on the rod, as shown in the figure below?
Coñecido:
O eixo de rotación no punto O. 
Forza 1 (F1) = 6 Newtons
A distancia entre a liña de acción de F1 co eixo de rotación (r1) = 1 metros
Forza 2 (F2) = 6 Newtons
A distancia entre a liña de acción de F2 co eixo de rotación (r2) = 2 metros
Forza 3 (F3) = 4 Newtons
A distancia entre a liña de acción de F3 co eixo de rotación (r3) = 2 metros
Quería: The resultant of the moment of force about point C
Solución:
Moment of force 1 :
τ1 =F1 l1 = (6 N)(1 m) = 6 Nm
Plus sign indicates that the moment of force rotates rod counterclockwise.
Moment of force 2 :
τ2 =F2 r2 sen 30o = (6 N)(2 m)(0,5)= 6 Nm
Plus sign indicates that the moment of force rotates rod counterclockwise.
Moment of force 3 :
τ3 =F3 l3 = (4 N)(2 m) = -8 Nm
Minus sign indicates that the moment of force rotates rod clockwise.
A resultante do momento da forza:
Στ = τ1 + τ2 – τ3 = 6 + 6 – 8 = 4 Nm
Plus sign indicates that the moment of force rotates rod counterclockwise.