Cuairt AC Sreath LRC – duilgheadasan agus fuasglaidhean

1.

Obraich a-mach an sruth dealain sa chuairt (1 µF = 10^-6 F)

Aithnichte:

Resistor (R) = 12 Ohms

Ionnsaigh (L) = 0.075 U

Ceangalaichean BBC (C) = 500 µF = 500 x 10^-6 F = 5 x 10^-4 Farad

Vbholtaids (V) = V_o peacadh ωt = v_o sin 2πft = 26 peacadh 200t

A dhìth: Sruth dealain

fuasgladh:

Impedance (Z):

An ath-bhualadh ionduchtach (X_L) = ωL = (200)(0,075) = 15 Ohm

An ath-bhualadh comasach (X_C) = 1 / ωC = 1 / (200)(5 x 10^-4) = 1 / (1000 x 10^-4) = 1 / 10^-1 = 10¹ = 10 Ohm

An aghaidh (R) = 12 Ohm

Sruth dealain (I) :

I = V / Z = 26 Volts / 13 Ohms

I = 2 Volt/Ohm

I = 2 Amp

2. Ma tha impedance na cuairte 250 Ω, obraich a-mach strì an resistor R.

Aithnichte:

Impedance na cuairte (Z) = 250 Ω

Comharaiche (C) = 8 m F = 8 x 10^-6 F

Ionductor (L) = 0.8 H

Bholtaids (V) = 200 Volt

w = 500 rad/s

A dhìth: An aghaidh an aghaidh (R)

fuasgladh:

3. Obraich a-mach an diofar comasachd aig gach taobh den inductor.

Aithnichte:

R = 40 W

X_L = 150 W

X_C= 120 W

V = 100 Volt

Ag iarraidh: an diofar comasach

fuasgladh:

An impedance iomlan Z den chuairt:

An diofar comasachd aig gach taobh den inductor: