Eisimpleir de chuairt resistor

3 Eisimpleirean de cheistean mu chuairtean resistor

1. An t-sreath de resistors gu h-ìosal aig a bheil an aghaidh co-ionann as motha...

Deasbad

Freagairt A

R₁ = 2 Ω, R₂ = 2 Ω, R₃ = 6 Ω, R₄ = 6 Ω

R₃ agus R₄ ceangailte ann an co-shìnte. Is e an resistor ùr:

1 / R.₃₄ = 1/R₃ +1/R₄ = 1/6 + 1/6 = 2/6

R₃₄ = 6/2 = 3 Ω

R_1, R₂ agus R₃₄ ceangailte ann an sreath. Is e an resistor ùr:

R = R₁ + R₂ + R.₃₄ = 2 Ω + 2 Ω + 3 Ω

R = 7Ω

Freagairt B

R₁ = 2 Ω, R₂ = 4 Ω, R₃ = 4 Ω, R₄ = 8 Ω

R₂ agus R₃ ceangailte ann an sreath. Is e an resistor ùr:

R₂₃ = R₂ + R₃ = 4 Ω + 4 Ω = 8 Ω

R₂₃ agus R₄ ceangailte ann an co-shìnte. Is e an resistor ùr:

1 / R.₂₃₄ = 1/R₂₃ +1/R₄ = 1/8 + 1/8 = 2/8

R₂₃₄ = 8/2 = 4 Ω

R₁ agus R₂₃₄ ceangailte ann an sreath. Is e an resistor ùr:

R = R₁ + R.₂₃₄ = 2 Ω + 4 Ω

R = 6 Ω

Freagair C

R₁ = 9 Ω, R₂ = 9 Ω, R₃ = 9 Ω, R₄ = 2 Ω

R_1, R₂ agus R₃ ceangailte ann an co-shìnte. Is e an resistor ùr:

1 / R.₁₂₃ = 1 /R₁ + 1/R₂ +1/R₃ = 1/9 + 1/9 + 1/9 = 3/9

R₁₂₃ = 9/3 = 3 Ω

R₁₂₃ agus R₄ ceangailte ann an sreath. Is e an resistor ùr:

R = R₁₂₃ + R.₄ = 3 Ω + 2 Ω

R = 5 Ω

Freagair D

R₁ = 5 Ω, R₂ = 10 Ω, R₃ = 2 Ω, R₄ = 2 Ω

R₁ agus R₂ ceangailte ann an co-shìnte. Is e an resistor ùr:

1 / R.₁₂ = 1/R₁ +1/R₂ = 1/5 + 1/10 = 2/10 + 1/10

1 / R.₁₂ = 3 / 10

R₁₂ = 10 / 3 Ω

R₃ agus R₄ ceangailte ann an co-shìnte. Is e an resistor ùr:

1 / R.₃₄ = 1/R₃ +1/R₄ = 1/2 + 1/2 = 2/2

R₃₄ = 1 Ω

R₁₂ agus R₃₄ ceangailte ann an sreath. Is e an resistor ùr:

R = R₁₂ + R.₃₄ = 10/3 + 3/3 = 13/3

R = 4,3 Ω

Is e A am freagairt cheart.

2. Is e an aghaidh co-ionann san ìomhaigh gu h-ìosal…

A. 26 Ohm

B. 16 Ohm

C. 15 Ohm

D. 11 Ohm

Deasbad

Tha na resistors 6 Ω, 3 Ω agus 2 Ω ceangailte ann an co-shìnte. Is iad seo na resistors ùra:

1 / R._P = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6

R_P = 6/6 = 1 Ω

Tha na resistors 7 Ω, 8 Ω, agus 1 Ω ceangailte ann an sreath. Is iad na resistors ùra:

R = 7 + 8 + 1 = 16 Ω

Is e am freagairt cheart B.

3. Dè an ìre a th’ ann an Rp anns a’ chuairt mheasgaichte gu h-ìosal?

A. 8 ohms

B. 1/8 ohm

C. 1 ohm

D. 7 ohms

Deasbad

Tha fios gu bheil:

Resistor 1 (R₁) = 2 Ohms

Resistor 2 (R₂) = 2 Ohms

Resistor 3 (R₃) = 2 Ohms

Resistor 4 (R₄) = 2 Ohms

Dh'fhaighnich: Resistor ath-chur

Freagairt:

An aghaidh R₂ agus an aghaidh-aghaidh R₃ ceangailte ann an co-shìnte. Resistor ùr:

1 / R.₂₃ = 1/R₂ +1/R₃

1 / R.₂₃ = 1/2 + 1/2 = 2/2

R₂₃ = 1 Ohm

An aghaidh R₁, an aghaidh R₂₃ agus an aghaidh-aghaidh R₃ ceangailte ann an sreath. Resistor ùr:

R = R₁ + R.₂ + R.₃ = 2 + 1 + 2

R = 5 Ohm

Is e 5 Ohms am freagairt cheart.

Stòr na ceiste:

Ceistean Deuchainn Nàiseanta Saidheans Àrd-sgoil Òg/Ioslamach Àrd-sgoil Òg