11 Eisimpleirean de dhuilgheadasan le capacitor – cuairtean sreath is co-shìnte
1. Trì comasair ceangailte ann an sreath-co-shìnte mar a chithear san dealbh gu h-ìosal. Ma tha C1 = 2 μF, C2 = 4 μF, C3 = 4 μF, is e an comas ath-chuiridh…
Deasbad
Tha fios gu bheil:
Comharaiche C1 = 2 μF
Comharaiche C2 = 4 μF
Comharaiche C3 = 4 μF
Dh'fhaighnich: Comas ath-chur (C)
Freagairt:
Comharaiche C2 dan C3 ceangailte ann an co-shìnte. Is e comas an ath-chuir:
CP = C.2 + C.3 = 4 + 4 = 8 μF
Comharaiche C1 dan CP ceangailte ann an sreath. Is e comas an ath-chuir:
1/C = 1/C1 + 1/CP = 1/2 + 1/8 = 4/8 + 1/8 = 5/8
C = 8/5 μF
μF = microfarad (aonad comas dealain ) . 1 μF = 10⁻⁶ Farad
2. Tha trì comasairean ceangailte ann an sreath agus co-shìnte mar a chithear san fhigear gu h-ìosal. Ma tha C1 = 2 μF, C2 = 4 μF, C3 = 6 μF, C4 = 5 μF agus C5 = 10 μF, is e an comas ath-chuiridh…
Deasbad
Tha fios gu bheil:
Comharaiche C1 = 2 μF
Comharaiche C2 = 4 μF
Comharaiche C3 = 6 μF
Comharaiche C4 = 5 μF
Comharaiche C5 = 10 μF
Dh'fhaighnich: Comas ath-chur (C)
Freagairt:
Comharaiche C2 dan C3 ceangailte ann an co-shìnte. Is e comas an ath-chuir:
CP = C.2 + C.3
CP = 4 + 6
CP = 10 μF
Comharaiche C1, CP, C4 dan C5 ceangailte ann an sreath. Is e comas an ath-chuir:
1/C = 1/C1 + 1/CP + 1/C4 + 1/C5
1/C = 1/2 + 1/10 + 1/5 + 1/10
1/C = 5/10 + 1/10 + 2/10 + 1/10
1/C = 9/10
C = 10/9 μF
3 C1 = 3 μF, C2 = 4 μF agus C3 = 3 μF. Tha na trì comasairean ceangailte ann an sreath agus co-shìnte. Obraich a-mach an lùth dealain sa chuairt!
Deasbad
Tha fios gu bheil:
Comharaiche C1 = 3 μF
Comharaiche C2 = 4 μF
Comharaiche C3 = 3 μF
Dh'fhaighnich: Comas ath-chur (C)
Freagairt:
Comharaiche C2 dan C3 ceangailte ann an co-shìnte. Is e comas an ath-chuir:
CP = C.2 + C.3
CP = 4 + 3
CP = 7 μF
Comharaiche C1 dan CP ceangailte ann an sreath. Is e comas an ath-chuir:
1/C = 1/C1 + 1/CP
1/C = 1/3 + 1/7
1/C = 7/21 + 3/21
1/C = 10/21
C = 21/10
C = 2,1 μF
C = 2,1 x 10-6 F
Lùth dealain anns a’ chuairt:
E = ½ CV2
E = ½ (2,1 x 10-6)(122)
E = ½ (2,1 x 10-6(144)
E = (2,1 x 10-6(72)
E = 151,2 x 10-6 Joule
E = 1,5 x 10-4 Joule
4. Thoir sùil air diagram cuairt a’ chomasair air an taobh! Is e an cosgais iomlan air cuairt a’ chomasair… (1 μF = 10⁻⁶ F )
A. 1,50 μC
B. 2,75 μC
C. 3,50 μC
D. 4,50 μC
E. 4,75 μC
Deasbad
Tha fios gu bheil:
Comharaiche 1 (C1 ) = 3 μF
Comharaiche 2 (C2 ) = 3 μF
Comharaiche 3 (C3 ) = 3 μF
Comharaiche 4 (C4 ) = 2 μF
Comharaiche 5 (C5 ) = 3 μF
Bholtaids (V) = 3 Volts
Ceist: Cosgais iomlan air cuairt an capacitor (Q)
Freagairt:
Capacitor ath-chur
Tha comasairean C1 , C2 agus C3 ceangailte ann an sreath. Comasairean ùra :
1/C 123 = 1/C 1 + 1/C 2 + 1/C 3 = 1/3 + 1/3 + 1/3 = 3/3
C 123 = 3/3 = 1 μF
Tha comasairean C123 agus C4 ceangailte ann an co-shìnte. Comasair ath-chuir:
C1234 = C123 + C4 = 1 + 2 = 3 μF
Tha comasairean C 1234 agus C 5 ceangailte ann an sreath. Comharaiche ath-chuir:
1/C = 1/C 1234 + 1/C 5 = 1/3 + 1/3 = 2/3
C = 3/2 μF
C = 3/2 x 10-6 F
Cosgais dealain iomlan
An cosgais dealain air a’ chomasair ùr = an cosgais iomlan air cuairt a’ chomasair :
Q = VC = (3 Volt)(3/2 x 10⁻⁶ Farad ) = 6/2 x 10⁻⁶ Coulomb
Q = 9/2 microCoulomb = 9/2 μC
Q = 4,5 μC
Is e D am freagairt cheart.
5. Thoir sùil air diagram cuairteachaidh a’ chomasair air an taobh! Ma tha luach gach comasair C1 = C.2 = 2 μF, C3 = C.4 = 1 μF agus C5 = 4 μF, is e an luach cosgais iomlan sa chuairt… (1 μF = 10-6 F)
A. 1/7 μC
B. 2/7 μC
C. 4/7 μC
D. 6/7 μC
E. 1 μC
Deasbad
Tha fios gu bheil:
Comharaiche 1 (C1 ) = 2 μF
Comharaiche 2 (C2 ) = 2 μF
Comharaiche 3 (C3 ) = 1 μF
Comharaiche 4 (C4 ) = 1 μF
Comharaiche 5 (C5 ) = 4 μF
Bholtaids (V) = 1,5 Volts
A dhìth: Cosgais iomlan air a’ chuairt (Q)
Freagairt:
Capacitor ath-chur
Tha comasairean C3 agus C4 ceangailte ann an co-shìnte. Comasair ath-chuir:
C34 = C3 + C4 = 1 + 1 = 2 μF
Tha comasairean C5 , C1 , C2 agus C34 ceangailte ann an sreath. Comasairean ath-chur:
1/C = 1/C 5 + 1/C 1 + 1/C 2 + 1/C 34
1/C = 1/4 + 1/2 + 1/2 + 1/2
1/C = 1/4 + 2/4 + 2/4 + 2/4
1/C = 7/4
C = 4/7 μF
C = 4/7 x 10-6 F
Cosgais dealain iomlan
An cosgais dealain air a’ chomasair ath-chuir = an cosgais iomlan air a’ chuairt :
Q = VC = (1,5 Volt)(4/7 x 10⁻⁶ Farad ) = 6/7 x 10⁻⁶ Coulomb
Q = 6/7 microCoulomb
Q = 6/7 μC
Is e D am freagairt cheart.
6. Thoir sùil air a’ chuairt capacitor a leanas! Is e an cosgais iomlan sa chuairt…
A. 20 μC 
B. 40 μC
C. 60 μC
D. 80 μC
E. 160 μC
Deasbad
Tha fios gu bheil:
Comharaiche 1 (C1 ) = 3 μF
Comharaiche 2 (C2 ) = 3 μF
Comharaiche 3 (C3 ) = 4 μF
Comharaiche 4 (C4 ) = 4 μF
Comharaiche 5 (C5 ) = 8 μF
Bholtaids (V) = 10 Volts
A dhìth: Cosgais iomlan air a’ chuairt (Q)
Freagairt:
Capacitor ath-chur
Tha comasairean C1 agus C2 ceangailte ann an co-shìnte. Comasair ath-chuir:
C12 = C1 + C2 = 3 + 3 = 6 μF
Tha comasairean C3 agus C4 ceangailte ann an sreath. Comharaiche ath-chuir :
1/C 34 = 1/C 3 + 1/C 4 = 1/4 + 1/4 = 2/4
C34 = 4/2 = 2 μF
Tha comasair C12 , comasair C34 agus comasair C5 ceangailte ann an co-shìnte. Comasair ath-chuir :
C = C12 + C34 + C5 = 6 + 2 + 8 = 16 μF = 16 x 10⁻⁶ Farad
Cosgais dealain iomlan
An cosgais dealain air a’ chomasair ùr = an cosgais iomlan air cuairt a’ chomasair :
Q = VC = (10 Volt)( 16 x 10⁻⁶ Farad) = 160 x 10⁻⁶ Coulomb
Q = 160 microCoulomb = 160 μC
Is e E am freagairt cheart.
7. Thoir sùil air diagram cuairteachaidh a’ chomasair air an taobh! Is e an ìre de lùth dealain anns a’ chuairt… (1 µF = 10-6 F)
A. 65 x 10-6 Joule
B. 52 x 10-6 Joule
C. 39 x 10-6 Joule
D. 26 x 10-6 Joule
E. 13 x 10-6 Joule
Deasbad
Tha fios :
Comharaiche 1 (C1) = 3 µF
Comharaiche 2 (C2) = 1 µF
Comharaiche 3 (C3) = 2 µF
Comharaiche 4 (C4) = 6 µF
Comharaiche 5 (C5) = 4 µF
Bholtaids dealain (V) = 5 bholt
Chaidh faighneachd Lùth dealain anns a’ chuairt
Jawab :
Comharaiche ath-chuir airson cuairt comharaiche sreath-co-shìnte
Tha comasairean 2 agus 3 ceangailte ann an co-shìnte. Comharaiche ath-chuir:
CA = C.2 + C.3 = 1 + 2 = 3 µF
Tha comasair 1, comasair A agus comasair 4 ceangailte ann an sreath. Comasair ath-chuir:
1 / C.B = 1/C1 + 1/CA + 1/C4 = 1/3 + 1/3 + 1/6 = 2/6 + 2/6 + 1/6 = 5/6
CB = 6/5 µF
Tha comasair B agus comasair 5 ceangailte ann an co-shìnte. Comasair ath-chuir:
C = CB + C.5 = 6/5 + 4 = 6/5 + 16/4 = 24/20 + 80/20 = 104/20 = 5,2 µF
C = 5,2 x 10-6 Farad
Lùth dealain anns a’ chuairt
E = ½ CV2 = ½ (5,2 x 10-6)(52) = (2,6 x 10-6(25)
E = 65 x 10-6 Joule
Is e A am freagairt cheart.
8. Thoir sùil air an diagram cuairteachaidh capacitor a leanas! Is e an ìre de lùth dealain anns a’ chuairt capacitor còmhla seo… (1 µF = 10-6 F)
A. 0,6 x 10-3 Joule
B. 1,2 x 10-3 Joule
C. 1,8 x 10-3 Joule
D. 2,4 x 10-3 Joule
E. 3,0 x 10-3 Joule
Deasbad
Tha fios :
Comharaiche 1 (C1) = 4 µF
Comharaiche 2 (C2) = 6 µF
Comharaiche 3 (C3) = 12 µF
Comharaiche 4 (C4) = 2 µF
Comharaiche 5 (C5) = 2 µF
Bholtaids dealain (V) = 40 bholt
Chaidh faighneachd Lùth dealain anns a’ chuairt
Jawab :
Comharaiche ath-chuir airson cuairt comharaiche sreath-co-shìnte
Tha comasair 1, comasair 2 agus comasair 3 ceangailte ann an sreath. Comasair ath-chuir:
1 / C.A = 1/C1 + 1/C2 + 1/C3 = 1/4 + 1/6 + 1/12 = 3/12 + 2/12 + 1/12 = 6/12
CA = 12/6 = 2 µF
Tha comasairean 4 agus 5 ceangailte ann an sreath. Comharaiche ath-chuir:
1 / C.B = 1/C4 + 1/C5 = 1/2 + 1/2 = 2/2
CB = 2/2 = 1 µF
Tha comasair A agus comasair B ceangailte ann an co-shìnte. Comasair ath-chuir:
C = CA + C.B = 2 + 1 = 3 µF
C = 3 x 10-6 Farad
Lùth dealain anns a’ chuairt
E = ½ CV2 = ½ (3 x 10-6)(402) = (1,5 x 10-6(1600)
E = 2400 x 10-6 = 2,4x10-3 Joule
Is e D am freagairt cheart.
9. Thoir sùil air an diagram cuairteachaidh comas a leanas. Is e an lùth a tha air a stòradh sa chuairt dealain gu h-àrd…
A. 576 Joules
B. 288 Joules
C. 144 Joules
D. 72 Joule
E. 48 Joule
Deasbad
Tha fios :
Comharaiche 1 (C1) = 4 F
Comharaiche 2 (C2) = 4 F
Comharaiche 3 (C3) = 4 F
Comharaiche 4 (C4) = 4 F
Comharaiche 5 (C5) = 2 F
Bholtaids dealain (V) = 12 bholt
Chaidh faighneachd Lùth dealain anns a’ chuairt
Jawab :
Jawab :
Comharaiche ath-chuir airson cuairt comharaiche sreath-co-shìnte
Tha comasair 1, comasair 2 agus comasair 3 ceangailte ann an co-shìnte. Comasair ath-chuir:
CA = C.1 + C.2 + C.3 = 4 + 4 + 4 = 12 F
Tha comasairean 4 agus 5 ceangailte ann an co-shìnte. Comharaiche ath-chuir:
CB = C.4 + C.5 = 4 + 2 = 6 F
Tha comasair A agus comasair B ceangailte ann an sreath. Comasair ath-chuir:
1/C = 1/CA + 1/CB = 1/12 + 1/6 = 1/12 + 2/12 = 3/12
C = 12/3 = 4 Farad
Lùth dealain anns a’ chuairt
E = ½ CV2 = ½ (4)(122) = (2)(144)
E = 288 Joule
Is e am freagairt cheart B.
10. 
Seall air a’ chuairt gu h-ìosal! Meud an luchd air comasair C5 tha…
A. 36 Coulomb
B. 24 Coulomb
C. 12 Coulomb
D. 6 Coulombs
E. 4 Coulombs
Deasbad
Tha fios gu bheil:
Comharaiche 1 (C1) = 6 F
Comharaiche 2 (C2) = 6 F
Comharaiche 3 (C3) = 3 F
Comharaiche 4 (C4) = 12 F
Comharaiche 5 (C5) = 6 F
Bholtaids (V) = 12 Volts
Ceist: An cosgais air a’ chomasair (C5)
Freagairt:
Kapasitor
Comharaiche C2 agus comasair C3 ceangailte ann an sreath. Comh-chomh-chomh-chomh-chomh-chur:
1 / C.A = 1/C2 + 1/C3 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6
CA = 6/3 = 2 Farad
Comharaiche C4 agus comasair C5 ceangailte ann an sreath. Comh-chomh-chomh-chomh-chomh-chur:
1 / C.B = 1/C4 + 1/C5 = 1/12 + 1/6 = 1/12 + 2/12 = 3/12
CB = 12/3 = 4 Farad
Comharaiche CA agus comasair CB ceangailte ann an co-shìnte. Comh-chomharaichear ùr:
CC = C.A + C.B = 2 + 4 = 6 Farad
Comharaiche C1 agus comasair CC ceangailte ann an sreath:
1/C = 1/C1 + 1/CC = 1/6 F + 1/6 F = 2/6
C = 6/2 = 3 Farad
Cosgais Dealain
An cosgais dealain air a’ chomasair ath-chuir C:
q = VC = (12 Volt)(3 Farad) = 36 Coulomb
Tha comasair 1 agus comasair CC ceangailte ann an sreath gus am bi an cosgais dealain air a’ chomasair ath-chuir C = an cosgais dealain air comasair C1 = cosgais dealain air comasair CC = 36 Coulomb.
Comharaiche CC tha comas de 6 Farad aige agus tha cosgais de 36 Coulombs ann. An diofar comasach thar comasair CC is e: V = q/CC = 36 Coulombs / 6 Farads = 6 Volts
Comharaiche CC 's e comas-ionaid a th' ann airson comas-ionaid CA agus comasair CB a tha ceangailte ann an co-shìnte. Mar sin an diofar comasach thairis air comasair CC (VC) = eadar-dhealachadh comasach thar comasair CA (VA) = eadar-dhealachadh comasach thar comasair CB (VB) = 6 bholt.
Cosgais dealain air comasair CB :
qB = V.B CB = (6 Volt)(4 Farad) = 24 Coulomb
Is e comasair CB comasair ùr airson comasair C4 dan C5 a tha ceangailte ann an sreath. Leis gu bheil iad ceangailte ann an sreath, bidh an cosgais dealain air comasair CB (qB) = cosgais dealain air comasair C4 (q4) = cosgais dealain air comasair C5 (q5) = 24 Coulomb.
Is e am freagairt cheart B.
11. Tha còig comasairean co-ionann de 20 µF gach fear air an cur air dòigh mar a chithear san fhigear, ceangailte ri stòr bholtaids 6 bholt. Is e an cosgais iomlan a tha air a stòradh air comasair C 5 ….
A. 12 µC
B. 24 µC
C. 60 µC
D. 120 µC
E. 600 µC
Deasbad
Tha fios gu bheil:
Comharaiche C1 = C.2 = C.3 = C.4 = C.5 = 20 µF
Eadar-dhealachadh comasach (V) = 6 Volts
Ceist: Cosgais iomlan air a stòradh air comasair C5
Freagairt:
Kapasitor
Comharaiche C1 agus comasair C2 ceangailte ann an sreath. Comh-chomh-chomh-chomh-chomh-chur:
1 / C.A = 1/C1 + 1/C2 = 1/20 + 1/20 = 2/20
CA = 20/2 = 10 µF
Comharaiche C3 agus comasair C4 ceangailte ann an sreath. Comh-chomh-chomh-chomh-chomh-chur:
1 / C.B = 1/C3 + 1/C4 = 1/20 + 1/20 = 2/20
CB = 20/2 = 10 µF
Comharaiche CA agus comasair CB ceangailte ann an co-shìnte. Comh-chomharaichear ùr:
CC = C.A + C.B = 10 + 10 = 20 µF
Comharaiche CC agus comasair C5 ceangailte ann an sreath:
1/C = 1/CC + 1/C5 = 1/20 + 1/20 = 2/20
C = 20/2 = 10 µF
Cosgais Dealain
An cosgais dealain air a’ chomasair ath-chuir C:
q = VC = (6 bholt)(10 x 10-6 Farad) = 60 x 10-6 Coulomb = 60 µC
Comharaiche CC agus tha comasair 5 ceangailte ann an sreath gus am bi an cosgais dealain air a’ chomasair ath-chuir C = an cosgais dealain air comasair CC = cosgais dealain air comasair C5 = 60 µC.
Is e C am freagairt cheart.
Stòr na ceiste:
Ceistean Fiosaigs airson Àrd-sgoil Àrd-ìre/Àrd-sgoil Dreuchdail
