Voltas leictreach – fadhbanna agus réitigh

1. Faigh amach an poitéinseal leictreach ag pointe atá suite 1 cm ó mhuirear 5.0 μC . Tairiseach Coulomb (k) = 9 x 10⁶ ^Nm² C⁻² ^{, 1} μC = ^10⁻⁶ C.

Ar a dtugtar:

An fad ón muirear (r) = 1 cm = 1/100 m = 0.01 m = ^10⁻⁹ m

Muirear (q) = 5.0 μC = 5.0 x ^10-6 C

Tairiseach Coulomb (k) = 9 x 10 ^ ⁹ Nm² ^{C −2}

Ag Teastáil: Poitéinseal leictreach (V)

Réiteach:

Poitéinseal leictreach:

Is é 4.5 x ¹⁰⁶ Volta an poitéinseal leictreach

[irp]

2. Muirear Q₁ = 5.0 μC agus muirear Q₂ = 6.0 μC. Tairiseach Coulomb (k) = 9 x 10⁹ Nm²C^-2, 1 μC = 10^-6 C. Tá pointe A suite idir na muirir. Faigh amach an poitéinseal leictreach ag pointe A.

Ar a dtugtar:

Muirear Q1 = -5.0 μC = -5.0 x ^10-6 _C

Fad phointe A ó _Q1 = 10 cm = 0.1 m = ^10-1 m

Muirear Q2 = 6.0 μC = 6.0 x ^10-6 _C

Fad phointe a ó _Q2 = 10 cm = 0.1 m = ^10-1 m

Tairiseach Coulomb (k) = 9 x 10 ^ ⁹ Nm² ^{C −2}

Ag Teastáil: Poitéinseal leictreach ag pointe A

Réiteach:

Poitéinseal leictreach 1 :

Poitéinseal leictreach 2 :

Poitéinseal leictreach ag pointe A :

V = _V2 – _V1

V = (54 – 45) x ¹⁰⁴

V = 9 x ¹⁰⁴

[irp]

3. Muirear q₁ = 5.0 μC agus muirear q₂ = 6.0 μC. Tairiseach Coulomb (k) = 9 x 10⁹ Nm²C^-2, 1 μC = 10^-6 C. Faigh amach an poitéinseal leictreach ag pointe A.

Ar a dtugtar:

Muirear Q1 = -5.0 μC = -5.0 x ^10-6 _C

Fad phointe A ó _Q1 = 40 cm = 0.4 m = 4 x ^10-1 m

Muirear Q2 = 6.0 μC = 6.0 x ^10-6 _C

Fad phointe A ó _Q2 = 50 cm = 0.5 m = 5 x ^10-1 m

Tairiseach Coulomb (k) = 9 x 10 ^ ⁹ Nm² ^{C −2}

Ag Teastáil: Poitéinseal leictreach ag pointe A

Réiteach:

Poitéinseal leictreach 1 :

Poitéinseal leictreach 2 :

Poitéinseal leictreach ag pointe A :

_V = _V1 + V2

V = (-11.25 + 10.8) x ¹⁰⁴

V = -0.45 x ^10³

V = -4.5 x ^10³

Is é an poitéinseal leictreach ag pointe A ná -4.5 x ^10³ Volta