Roues reliées par courroies – problèmes et solutions

Roues reliées par courroies – problèmes et solutions

1. Trois roues sont reliées comme indiquén dans la figure ci-dessous.

Si RA = 10 cm, RB = 4 cm, et RC = 40cm, puis le rapport du système vitesse angulaire de la roue A et de la roue C est …

Connu :Roues reliées par courroies - problèmes et solutions 1

Rayon de la roue A (rA) = 10 cm

Rayon de la roue B (rB) = 4 cm

Rayon de la roue C (rC) = 40 cm

Voulait: the ratio of the angular velocity of wheel A and wheel C

Solution:

The angular velocity of wheel A and C

The circumference of wheel A is much larger than the circumference of wheel C. When the C wheel has been circularly rotated one circle (360o), during the same time interval the wheel A not yet rotates one circle (360o). Thus, the angular speed of the wheel A is not equal to the angular speed of the wheel C.

However, wheel A and wheel C are interconnected through ropes, so that in the same time interval, the distance traveled by the edge of the wheel A is equal to the distance traveled by the edge of the wheel C. Thus the linear speed of the edge of the wheel C (vC) equal to the vitesse linéaire of the edge of the wheel A (vA).

vA = vC

rA ωA = rC ωC

10ωA = 40 ωC

ωA / ωC = 40 / 10

ωA / ωC = 4 / 1

Voir aussi   Équation de vitesse

2. Wheels B and C have the same axis of rotation and wheel A is tangent to wheel B. If radius de roue A = radius de roue C = 30 cm, the radius de roue B = 60 cm, then determine the ratio of the linear speed between wheel A, B, and C.

Connu :

Radius of wheel A (rA) = 30 cm = 0.3 mètreRoues reliées par courroies - problèmes et solutions 2

Rayon de la roue B (rB) = 60 cm = 0.6 mètres

Rayon de la roue C (rC) = 30 cm = 0.3 mètres

Recherché : ratio of the linear speed between wheel A, B , and C.

Solution:

The linear speed of the edge of the wheel Un :

Wheel A and wheel B are interconnected as shown in figure below, therefore the angular velocity of the wheel A is not equal to the angular velocity of the wheel B. This is because the circumference of wheel B is larger than wheel A. During the same time interval, when wheel A around one circle (360o), wheel B not yet around one circle (360o). However, during the same time interval, the distance traveled by the edge of wheel A is equal to the distance traveled by the edge of wheel B. Thus the linear velocity of the edge of the wheel A (vA) is equal to the linear velocity of the edge of the wheel B (vB).

The linear speed of the edge of wheel A :

vA = rA ωA = 0.3 ωA

The linear speed of the edge of the wheekg :

Wheel B and wheel B stick together, therefore, wheel B and wheel C rotate together. When wheel B around one circle (360o) than during the same time interval, wheel C also around one circle (360o). Since it rotates together, then the angular speed of wheel B (ωB) is equal to the angular speed of wheel C (ωC) = ω. But the linear speed of wheel B (vB) is not equal to the linear speed of wheel C (vC)

The linear speed of the edge of wheel B :

vB = rB ωB = 0.6ωB = 0.6ω

The linear speed of the edge of wheel C :

vC = rC ωC = 0.3ωC = 0.3ω

The linear speed of the edge of wheel A (vA) same as the linear speed of the edge of whele B (vB)

vA = vB

0.3ωA = 0.6ω

ωA = 0.6 ω / 0.3

ωA = 2 ω

The linear speed of the edge of wheel A (vA):

vA = 0.3 ωA = 0.3 (2 ω) = 0.6 ω

Le rapport of the linear speed between wheel A, B, and C.

vA: vB: vC

0.6 ω : 0.6 ω : 0.3 ω

0.6: 0.6: 0.3

6: 6 : 3

2: 2: 1

Voir aussi   Dynamique rotationnelle – problèmes et solutions