Pritisak fluida – problemi i rješenja

1.

Pritisak fluida – problemi i rješenja 1

AUbrzanje usljed gravitacije je 10 N/kg. Površina ribe koju pritiska voda iznad nje je 6 cm2Odredite silu vode iznad ribe koja djeluje na ribu.

Poznato:

Ubrzanje zbog gravitacije (g) = 10 N/kg

Surface area of fish (A) = 6 cm2 = 6 x 10-4 m2

gustoća of water = 1 gram/cm3 = 1 (10-3 kg) / 10-6 m3 = 103 kg / m3 = 1000 kg/m3

Height of water = 100 cm – 15 cm = 85 cm = 85 x 10-2 Metara

Traži se: Force of the water above fish that acts on fish

Rešenje:

Jednadžba pritisak:

P = F / A

F = P A

F = ρ g h A

F = (1000)(10)(85 x 10-2)(6 x 10-4 m2)

F = (104)(510 x 10-6)

Vidi također  Kinetička energija – problemi i rješenja

F = 510 x 10-2

F = 5.1 Njutna

2. The normal pressure of blood is 80 mm hg to 120 mm hg. This value is equal to…

A. 80 Pascal to 120 Pascal

B. 800 Pascal to 1200 Pascal

C. 10256 Pascal to 17589 Pascal

D. 10526 Pascal to 15789 Pascal

Poznato:

The normal pressure of blood = 80 mm Hg – 120 mm Hg

Wanted: This value is equal to… Pascal

Rešenje:

The height of mercury in a barometer (above the surface of the sea) = 760 mm Hg

Pressure of air (above the surface of sea) = 1 atm = 1.0 x 105 paskal

1 mm Hg = ……. Pascal?

Vidi također  Moć – problemi i rješenja

Pritisak fluida – problemi i rješenja 2

80 mm Hg = 80 x 131.58 Pascal = 10,526 Pascal

120 mm Hg = 120 x 131.58 Pascal = 15,789 Pascal

Tačan odgovor je D.

3. Above the surface of the sea, the height of mercury in a barometer is 760 mm. If at a place, the height of mercury in a barometer is 700 mm. Determine the pressure of air at that place.

Poznato:

The height of mercury in a barometer (above the surface of the sea) = 760 mm Hg

Pressure of air (above the surface of sea) = 1 atm = 1,013 x 105 paskal

Wanted: Determine the pressure of air if the height of mercury is 700 mm

Rešenje:

Vidi također  Rotaciono kretanje – problemi i rješenja

760 mm Hg = 1.013 x 105 paskal

700 mm Hg = ……… Pascal?

Pritisak fluida – problemi i rješenja 3

Ostavite komentar