1. A 500-gram object, A, moving at 10 ሜ / ሰ and 200-gram object, B, moving at 12 m/s. The objects approach each other and collide. If the speed of object A after the ግጭት is 6 m/s, what is the speed of object B after the collision?
የሚታወቅ፦
ቅዳሴ of object 1 (m1) = 500 ግራም = 0.5 ኪ.ግ
ቅዳሴ የነገር 2 (ሜ2) = 200 ግራም = 0.2 ኪ.ግ
የመጀመሪያ ፍጥነት of object 1 (v1) = -10 ሜ/ሰ
Initial velocity of object 2 (v2) = 12 ሜ/ሰ
የነገር 1 የመጨረሻ ፍጥነት (v1') = 6 ሜ/ሰ
የመደመር እና የመቀነስ ምልክቶች እቃዎቹ በተቃራኒው አቅጣጫ እንደሚንቀሳቀሱ ያመለክታሉ።
የሚፈለጉ : the final velocity of object 2 (v2')
መፍትሔው
m1 v1 + ሜ2 v2 = ሜ1 v1'+ ሜ2 v2'
(0.5)(-10) + (0.2)(12) = (0.5)(6) + (0.2)(v2')
-5 + 2.4 = 3 + 0.2 v2'
-2.6 = 3 + 0.2 v2'
-2.6 – 3 = 0.2 v2'
-5.6 = 0.2 v2'
v2’ = -5.6 / 0.2
v2' = -28 ሜ/ሰ
The speed of object 2 after collision is 28 m/s.
የመደመር እና የመቀነስ ምልክቶች እቃዎቹ በተቃራኒው አቅጣጫ እንደሚንቀሳቀሱ ያመለክታሉ።
2. Two equal-mass objects approach each other and collide. The speed of object 1 is 6 m/s and the speed of object 2 is 8 m/s. After the collision, object 2 moves leftward with speed of 5 m/s. What is the magnitude and direction of the velocity of object 1 after the ግጭት?
Know :
ቅዳሴ የነገር 1 (ሜ1) = ሜትር
ቅዳሴ of object 2 (m2) = ሜትር
Initial speed of object 1 (v1) = -6 ሜ/ሰ
initial speed of object 2 (v2) = 8 ሜ/ሰ
The final speed of object 2 (v2') = -5 ሜ/ሰ
የሚፈለጉ : the magnitude and direction of object 1 after collision
መፍትሔው
Formula of conservation of linear momentum :
m1 v1 + ሜ2 v2 = ሜ1 v1'+ ሜ2 v2'
ኤምቪ1 + ሜ v2 = ሜ v1'+ ሜ v2'
ሜትር (ቪ)1 + ቁ2) = ሜትር (ቪ1'+ v2')
v1 + ቁ2 = v1'+ v2'
-6 + 8 = v1’ – 5
2 = v1’ – 5
2 + 5 = v1'
v1' = 7 ሜ/ሰ
The speed of object 1 after collision (v1') is 3 ሜ / ሰ
የመደመር እና የመቀነስ ምልክቶች እቃዎቹ በተቃራኒው አቅጣጫ እንደሚንቀሳቀሱ ያመለክታሉ።
3. A 1-kg ball 1 and 2-kg ball 2 have the same direction and collide inelastically. Before the collision, ball 1 moves with speed of 10 m/s and ball 2 moves with speed of 5 m/s. The speed of ball 2 after the collision is 4 m/s. Determine the speed of ball 1 after the collision.
የሚታወቅ፦
ቅዳሴ ኳስ 1 (ሜ1) = 1 ኪ.ግ
ቅዳሴ ኳስ 2 (ሜ2) = 2 ኪ.ግ
The speed of ball 1 (በ1) = 10 ሜ/ሰ
The speed of ball 2 (v2) = 5 ሜ/ሰ
The final speed of ball 2 (v2') = 4 ሜ/ሰ
The plus sign of the velocity indicates that the balls have the same direction.
የሚፈለጉ : the final velocity of ball 1 (v1')
መፍትሔው
m1 v1 + ሜ2 v2 = ሜ1 v1'+ ሜ2 v2'
(1)(10) + (2)(5) = (1)(v1’) + (2)(4)
10 + 10 = v1' + 8
20 – 8 = v1'
v1' = 12 ሜ/ሰ
The speed of ball 1 after collision is 12 ሜ / ሰ
[wpdm_package id='1190′]
- መስመራዊ የሞመንተም ችግሮች እና መፍትሄዎች
- የሞመንተም እና የግፊት ችግሮች እና መፍትሄዎች
- በአንድ ልኬት ውስጥ ፍጹም የመለጠጥ ግጭቶች እና መፍትሄዎች
- በአንድ ልኬት ውስጥ ፍጹም የሆነ ኢላስቲክ ግጭቶች እና መፍትሄዎች
- በአንድ ልኬት ውስጥ ያሉ የማይለሰልስ ግጭቶች እና መፍትሄዎች
