1. Twee eenvoudige pendulums is op twee verskillende plekke. Die lengte van die tweede pendulum is 0.4 keer die lengte van die eerste pendulum, en die versnellingn van swaartekrag ervaar deur die die tweede pendulum is 0.9 keer die versnelling van swaartekrag ervaar deur die eerste pendulum. Bepaal die cvergelyking van die frekwensie van die eerste pendulum sekonded slinger.
A. 2/3
B. 3/2
C. 4/9
D. 9/4
Bekend:
The length of the cord of the first pendulum (l1) = 1
The length of cord of the second pendulum (l2) = 0.4 (l1) = 0.4 (1) = 0.4
Acceleration due to the gravity of the first pendulum (g1) = 1
Acceleration due to gravity of the second pendulum (g2) = 0.9 (1) = 0.9
Gesoek: The comparison of the frequency of the first pendulum (f1) to the second pendulum (f2)
oplossing:
The comparison of the frequency of the first pendulum (f1) to the second pendulum (f2):
Die korrekte antwoord is A.
2. An object is suspended from 1 end of a cord en dan voer a eenvoudige harmoniese beweging with a frequency of 0.5 Hertz. If the length of the cord is increased by four times the initial length, then determine the period of the harmonic motion.
A. ¼ seconds
B. ½ seconds
C. 2 sekondes
D. 4 sekondes
Bekend:
Frequency of pendulum (f) = 0.5 Hz
Gesoek: Determine the period (T) of the pendulum if the length of cord (L) is four times the initial length
oplossing:
Tydperk of the first pendulum :
The initial length of cord :
If the length of the cord is increased by four times the initial length :
Then the period of a pendulum is :
The period of motion is 4 sekondes.
Die korrekte antwoord is D.
3. Two pendulums with the same length of its cord, but the mass of the second pendulum is four times the mass of the first pendulum. If f1 is the frequency of the first pendulum and f2 is the frequency of the second pendulum, then determine the relationship between f1 en f2.
A. f1 = f2
B. f1 = 2 f2
C. f2 = 2 f1
D. f1 = 4 f2
oplossing:
The equation of frequency of the simple pendulum :
f = frequency, g = acceleration due to gravity, l = the length of cord
Based on the equation above, can conclude that massa does not affect the frequency of the simple pendulum.
Die korrekte antwoord is A.
4. The quantities below that do not impact the period of the simple pendulum are…..
A. length of cord and mass of the object
B. length of cord and acceleration due to gravity
C. mass of the object and initial angle
D. length of cord and initial angle
oplossing:
The equation of period of the simple pendulum :
T = period, g = acceleration due to gravity, l = length of cord
Based on the above formula, can conclude the length of the staaf (l) and the acceleration of gravity (g) impact the period of the simple pendulum. Otherwise, the mass of die voorwerp en die aanvanklike hoek does not impact the periode van die simple pendulum.
Die korrekte antwoord is C.
5. The rope of the simple pendulum made from nylon. At one end of the rope suspended a mass of 10 gram and length of rope is 1 meter. If the frequency produced twice the initial frequency, then the length of the rope must be changed to…
A. 0.25 meter
B. 0.50 meter
C. 2.0 meter
D. 4.0 meter
Bekend:
The mass does not impact the frequency of the simple pendulum.
The length of the cord of the simple pendulum (l) = 1 meter
Gesoek: determine the length of rope if the frequency is twice the initial frequency
oplossing:
The initial frequency of the simple pendulum :
The frequency of the simple pendulum is twice the initial frequency :
vir die finale frequency to be doubled, the length of the pendulum should be changed to 0.25 meters.
Die korrekte antwoord is A.
