1. Gebaseer op die figuur hieronder, as die radius van die kromming van die draad 50 cm is, bepaal die grootte van die magneetveld by die middelpunt van die kromming (by punt 0, sien figuur hieronder). (µo = 4π.10-7 Wb.A-1 m-1)
Bekend:
Radius (r) = 50 cm = 0.5 m
Elektriese stroom (I) = 1.5 Ampère
Die vakuumdeurlaatbaarheid (µo) = 4π.10-7 Wb.A-1 m-1
Gesoek: Tdie grootte van die magnetiese veld
oplossing:
360o = 1 omtrek van 'n sirkel. 120o / 360o = 1/3 dan 120o = 1/3 x omtrek of a circle.
The equation of the magnetic field at the center of the coil with several loops :
B = the magnitude of the magnetic field, N = number of loops, I = electric current, r = radius of curvature
In the above problem, there is only one loop so that N is eliminated from the equation. The wire coil on the above problem is not 1 circle but 1/3 circle :
The magnitude of the magnetic field at the center of curvature :
2. Based on the figure below, the electric current flows in the wire is 6-A and radius of curvature is R = 3π cm, to determine the magnitude of the magnetic field at point P.
Bekend:
Radius of curvature (r) = 3π cm = (3π/100) m
= 3π/102 m = 3π.10-2 m
Elektriese stroom (I) = 6 A
Die vakuumdeurlaatbaarheid (µo) = 4π.10-7 Wb.A-1 m-1
Gesoek: The magnitude of the magnetic field
oplossing:
360o = 1 omtrek of a circle. 45o / 360o = 1/8 dan 45o = 1 / 8 x omtrek of a circle.
The magnitude of the magnetic field at the center of curvature :
3. Electric current flows in wire = 9-A, the radius of curvature (R) = 2π cm and µo = 4π.10-7 Wb.A-1.m-1, determine the magnitude of the magnetic field at point P.
Bekend:
Radius of curvature (r) = 2π cm = (2π/100) m
= 2π/102 m = 2π.10-2 m
Elektriese stroom (I) = 9 A
Die vakuumdeurlaatbaarheid (µo) = 4π.10-7 Wb.A-1 m-1
Gesoek: The magnitude of the magnetic field at point P
oplossing:
360o - 120o = 240o. 240o / 360o = 2/3 dan 240o = 2/3 x omtrek of a circle.
The magnitude of the magnetic field at the center of curvature :
