Application of conservation of mechanical energy for projectile motion – problems and solutions

1. 'n Geskopte sokkerbal verlaat die grond teen 'n hoek θ = 30^o with the initial velocity of 10 m/s. Ball’s massa = 0.1 kg. Versnelling as gevolg van swaartekrag is 10 m / s². Determine (a) The gravitasie potensiële energie at the highest point (b) The highest point or the maximum height

Bekend:

Massa (m) = 0.1 kg

Die aanvanklike snelheid (v_o) = 10 m/s

Hoek = 30^o

Versnelling as gevolg van swaartekrag (g) = 10 m/s²

oplossing:

(a) The gravitational potential energy

Calculate the horizontal component (v_ox) and the vertical component (v_oy) of initial velocity.

v_ox =v_o cos θ = (10)(cos 30^o) = (10)(0.5√3) = 5√3 m/s

v_oy =v_o sonder θ = (10)(sin 30^o) = (10)(0.5) = 5 m/s

Die aanvanklike meganiese energie

Die aanvanklike meganiese energie (ME_o) = kinetiese energie (KE)

ME_o = KE = ½ m v_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 Joule

The final mechanical energy

Kinetic energy at the highest point :

KE = ½ m v_ox² = ½ (0.1)(5√3)² = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Joule

Principle of conservation of mechanical energy

The initial mechanical energy (ME_o) = the final mechanical energy (ME_t)

KE = PE + KE

5 = EP + 3.75

PE = 5 – 3.75 = 1.25 Joule

The gravitational potential energy at the highest point is 1.25 Joule.

(b) The highest point or the maximum height

PE = mgh

1.25 = (0.1)(10) h

1.25 = h

The maximum height is 1.25 meters.

2. A 0.1-kg ball projected horizontally with initial velocity v_o = 10 m/s from a building 10 meter high. Acceleration due to gravity is 10 m/s². Determine ball’s kinetic energy when it hits the ground.

Bekend:

Massa (m) = 0.1 kg

Aanvanklike snelheid (v_o) = 10 m/s

Versnelling as gevolg van swaartekrag (g) = 10 m/s²

The change in height (h) = 10 – 2 = 8 m

Gesoek: kinetic energy at 2 meters above the ground

oplossing:

The gravitational potential energy (PE) = m g h = (0.1)(10)(10) = 10 Joule

The initial kinetic energy (KE)= ½ m v_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 Joule

The final kinetic energy = the initial gravitational potential energy + the initial kinetic energy = 10 + 5 = 15 Joule

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3. Werk-meganiese energiebeginselprobleme en oplossings
4. Probleme en oplossings vir gravitasie-potensiële energie
5. Die potensiële energie van elastiese veerprobleme en oplossings
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8. Toepassing van die behoud van meganiese energie vir op- en afwaartse beweging in vryvalbeweging
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